Question 1281
Which two numbers (not digits) should be interchanged to make the given equation correct?
48 ÷ 3 + 12 × 4 – 6 × 7 + 21 = 27
- AOption (a)
3 and 4
- BOption (b)
3 and 6
- COption (c)
4 and 7
- DOption (d)
12 and 21
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Correct answer
3 and 4
Why this answer is correct
Given equation: 48 ÷ 3 + 12 × 4 – 6 × 7 + 21 = 27
According to the question, after interchanging the numbers:
Option 1) 3 and 4
48 ÷ 3 + 12 × 4 – 6 × 7 + 21 = 27 ⇒ 48 ÷ 4 + 12 × 3 – 6 × 7 + 21 = 27
⇒ 48 ÷ 4 + 12 × 3 – 6 × 7 + 21 = 27
⇒ 12 + 12 × 3 – 6 × 7 + 21 = 27
⇒ 12 + 36 + 21 – 42 = 27
⇒ 69 – 42 = 27
⇒ 27 = 27 (LHS = RHS)
Option 2) 3 and 6
48 ÷ 3 + 12 × 4 – 6 × 7 + 21 = 27 ⇒ 48 ÷ 6 + 12 × 4 – 3 × 7 + 21 = 27
⇒ 48 ÷ 6 + 12 × 4 – 3 × 7 + 21 = 27
⇒ 8 + 12 × 4 – 3 × 7 + 21 = 27
⇒ 8 + 48 + 21 – 21 = 27
⇒ 77 – 21 = 27
⇒ 56 ≠ 27 (LHS ≠ RHS)
Option 3) 4 and 7
48 ÷ 3 + 12 × 4 – 6 × 7 + 21 = 27 ⇒ 48 ÷ 3 + 12 × 7 – 6 × 4 + 21 = 27
⇒ 48 ÷ 3 + 12 × 7 – 6 × 4 + 21 = 27
⇒ 16 + 12 × 7 – 6 × 4 + 21 = 27
⇒ 16 + 84 + 24 – 21 = 27
⇒ 124 – 21 = 27
⇒ 103 ≠ 27 (LHS ≠ RHS)
Option 4) 12 and 21
48 ÷ 3 + 12 × 4 – 6 × 7 + 21 = 27 ⇒ 48 ÷ 3 + 21 × 4 – 6 × 7 + 12 = 27
⇒ 48 ÷ 3 + 21 × 4 – 6 × 7 + 12 = 27
⇒ 16 + 21 × 4 – 6 × 7 + 12 = 27
⇒ 16 + 84 + 42 – 12 = 27
⇒ 142 – 42 = 27
⇒ 100 ≠ 27 (LHS ≠ RHS)
Hence, "Option 1" is the correct answer.
















