If \(\frac{a}{{1 - a}} + \frac{b}{{1 - b}} + \frac{c}{{1 - c}} = 1\). then the value of \(\frac{1}{{1 - a}} + \frac{1}{{1 - b}} + \frac{1}{{1 - c}} \) is
- AOption (a)
0
- BOption (b)
1
- COption (c)
2
- DOption (d)
4
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Correct answer
4
Why this answer is correct
Given:
(a/1 – a) + (b/1 – b) + (c/1 – c) = 1
Calculation:
Add 1 to 1st term on LHS, add 1 to second term and again 1 to last term. Balance this by adding 3 to RHS.
[1 + a/(1 – a)] + [1 + b/(1 – b)] + [1 + c/ (1 – c)] = 1 + 3
⇒ (a + 1 – a)/(1 – a) + (b + 1 – b)/(1 – b) + (c + 1 – c)/(1 – c) = 1 + 3
⇒ 1/(1 – a) + (1/1 – b) + (1/ 1 – c) = 4
∴ The value of (1/1 – a) + (1/1 – b) + (1/ 1 – c) is 4.