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Question 31

UP CNET 2025• Chemistry

Rate of reaction DOES NOT depend on

  1. AOption (a)

    Concentration

  2. BOption (b)

    Temperature

  3. COption (c)

    Catalyst

  4. DOption (d)

    Pressure

View answer & explanation

Correct answer

Answer: (d)D.

Pressure

Why this answer is correct

The correct answer is Pressure.

Key Points

  • The rate of a chemical reaction generally depends on several factors including concentration, temperature, and the presence of a catalyst.
  • Pressure can influence the rate of reaction in cases where gases are involved, but it is not a general factor for all reactions.
  • In reactions involving only solids or liquids, pressure typically has little to no effect on the rate of reaction.
  • Key factors such as concentration, temperature, and catalysts directly affect the speed at which reactants are converted to products.

Additional Information

  • Concentration
  • The rate of reaction generally increases with the concentration of reactants because there are more particles available to collide and react.
  • According to the collision theory, the frequency of effective collisions increases with concentration.
  • Temperature
  • Raising the temperature typically increases the rate of reaction as particles move faster and collide more energetically.
  • Higher temperatures provide the energy needed to overcome activation energy barriers.
  • Catalyst
  • Catalysts speed up reactions without being consumed by lowering the activation energy required for the reaction to proceed.
  • Enzymes are biological catalysts that play crucial roles in speeding up biochemical reactions.
  • Activation Energy
  • Activation energy is the minimum energy that reacting particles need to collide successfully and start a reaction.
  • Lowering the activation energy increases the rate of reaction.

Question 32

UP CNET 2025• Chemistry

Law of octaves was propounded by

  1. AOption (a)

    John Newlands

  2. BOption (b)

    Johann Dobereiner

  3. COption (c)

    Ivanovich Mendeleev

  4. DOption (d)

    Henry Moseley

View answer & explanation

Correct answer

Answer: (a)A.

John Newlands

Why this answer is correct

The correct answer is John Newlands.

Key Points

  • John Newlands was an English chemist who first proposed the law of octaves in 1864.
  • The law of octaves states that elements, when arranged by increasing atomic mass, exhibit similar properties at every eighth element.
  • Newlands’ law was an early attempt to classify the elements in a systematic way before the development of the modern periodic table.
  • His work was initially criticized, but it paved the way for the later development of the periodic table by Dmitri Mendeleev.

Additional Information

  • Johann Dobereiner
  • German chemist known for his work on the classification of elements.
  • Introduced the concept of triads, groups of three elements with similar properties, in 1829.
  • Triads were an early attempt to show a relationship between atomic weights and properties of elements.
  • Dmitri Mendeleev
  • Russian chemist who created the first widely accepted periodic table in 1869.
  • Arranged elements by increasing atomic weight and grouped elements with similar properties.
  • Predicted the existence and properties of undiscovered elements, which were later found.
  • Henry Moseley
  • British physicist who established the concept of atomic number in 1913.
  • Showed that the periodic table should be arranged by atomic number, not atomic weight.
  • His work led to the modern definition of the periodic table.

Question 33

UP CNET 2025• Chemistry

Rate of reaction for the equation 2HI - l2 + H2 can be expressed as

  1. AOption (a)

    -Δ[HI]/Δt

  2. BOption (b)

    -Δ[H2]/Δt

  3. COption (c)

    +ΔHI/Δt

  4. DOption (d)

    -1/2ΔHI/Δt

View answer & explanation

Correct answer

Answer: (d)D.

-1/2ΔHI/Δt

Why this answer is correct

The correct answer is -1/2Δ[HI]/Δt.

Key Points

  • The rate of reaction for the equation 2HI → I2 + H2 is expressed as the change in concentration of HI over time.
  • Since 2 moles of HI decompose to form 1 mole each of I2 and H2, the rate of decrease of HI is twice the rate of formation of products.
  • The negative sign indicates that the concentration of HI is decreasing over time.
  • The factor of 1/2 accounts for the stoichiometric coefficient of HI in the balanced chemical equation, ensuring the correct rate expression.

Additional Information

  • Rate of Reaction
  • It is defined as the change in concentration of reactants or products per unit time.
  • The rate can be expressed as the rate of disappearance of reactants or the rate of appearance of products.
  • Stoichiometry
  • It refers to the quantitative relationships between reactants and products in a balanced chemical equation.
  • Stoichiometric coefficients are used to determine the relative amounts of substances consumed and produced in a reaction.
  • Reaction Order
  • It indicates the power to which the concentration of a reactant is raised in the rate law.
  • Determined experimentally, it helps in understanding the dependence of the rate on reactant concentrations.
  • Rate Law
  • It is an equation that relates the rate of a reaction to the concentration of reactants.
  • For the reaction aA + bB → cC, the rate law is usually written as Rate = k[A]^m[B]^n, where k is the rate constant and m, n are the orders of the reaction with respect to A and B, respectively.

Question 34

UP CNET 2025• Chemistry

Which of the following come under the category of chemical change? 

A. Growth of plant

B. Rusting of iron

C. Mixing of iron fillings and sand

D. Freezing of water

E. None of the above

Choose the most appropriate answer from the options given below:

  1. AOption (a)

    E only

  2. BOption (b)

    B only

  3. COption (c)

    C only

  4. DOption (d)

    B and C only

View answer & explanation

Correct answer

Answer: (b)B.

B only

Why this answer is correct

The correct answer is B only.

Key Points

  • Rusting of iron is a chemical change as it involves the formation of a new substance, iron oxide, which is different from the original material.
  • Chemical changes result in the production of one or more new substances with different properties from the original substances.
  • During rusting, iron reacts with oxygen and moisture in the environment, leading to corrosion.
  • This process is irreversible under normal conditions, further confirming it as a chemical change.

Additional Information

  • Physical vs Chemical Change
  • Physical changes affect the form of a chemical substance but not its chemical composition (e.g., melting ice).
  • Chemical changes involve making or breaking of bonds between atoms, resulting in new substances (e.g., burning wood).
  • Indicators of Chemical Changes
  • Change in color, temperature, formation of a precipitate, and evolution of gas are common indicators.
  • Production of light or sound can also indicate a chemical change.
  • Examples of Chemical Changes
  • Burning of paper, digestion of food, and baking a cake are classic examples.
  • These processes produce new substances with different properties from the reactants.
  • Importance of Understanding Chemical Changes
  • Helps in various industries such as pharmaceuticals, agriculture, and manufacturing.
  • Understanding these changes is crucial in environmental science to address issues like pollution and recycling.

Question 35

UP CNET 2025• Chemistry

How many moles of CO2 are present in a gas jar containing 1.506 × 1023 molecules of carbon dioxide?

  1. AOption (a)

    0.5

  2. BOption (b)

    1

  3. COption (c)

    2

  4. DOption (d)

    0.25

View answer & explanation

Correct answer

Answer: (d)D.

0.25

Why this answer is correct

The correct answer is 0.25

Concept:

Mole:

  • The mole is a unit of measurement for the amount of substance.
  • One mole of any substance contains exactly \(6.022 \times 10^{23}\) entities (this number is known as Avogadro's number \(N_A\).
  • Formula to calculate moles: \(n = \frac{N}{N_A}\)

Calculation:

Given,

Number of molecules of\( CO_2 = N = 1.506 \times 10^{23}\)

Avogadro's number, \(N_A = 6.022 \times 10^{23} , \text{molecules/mol}\)

Number of moles of \(CO_2\),

⇒ \(n = \frac{N}{N_A}\)

⇒\( n = \frac{1.506 \times 10^{23}}{6.022 \times 10^{23}}\)

⇒ \(n \approx 0.25 \ moles\)

∴ The number of moles of \( CO_2 \) present is 0.25.

Question 36

UP CNET 2025• Chemistry

Solid sodium bicarbonate was placed on a strip of pH paper. The colour of the strip:

  1. AOption (a)

    Turned blue

  2. BOption (b)

    Turned red 

  3. COption (c)

    Turned green and slightly yellow

  4. DOption (d)

    Did not change

View answer & explanation

Correct answer

Answer: (d)D.

Did not change

Why this answer is correct

The correct answer is Did not change.

Key Points

  • Sodium bicarbonate (NaHCO3) is a weak base and slightly alkaline in nature.
  • pH paper is an indicator that changes color based on the pH of the substance it comes into contact with.
  • Solid sodium bicarbonate typically has a pH around 8-9 when dissolved in water, but the solid form does not readily change the pH paper color.
  • The color of the pH paper does not change significantly because the bicarbonate ions in the solid form are not free to react with the paper.

Additional Information

  • pH Scale
  • The pH scale ranges from 0 to 14, where 7 is neutral, below 7 is acidic, and above 7 is basic (alkaline).
  • The pH paper is a tool used to measure the acidity or alkalinity of a solution.
  • Sodium Bicarbonate
  • Commonly known as baking soda, sodium bicarbonate is used in cooking, cleaning, and sometimes as a medicinal antacid.
  • It is a chemical compound with the formula NaHCO3.
  • Indicators
  • Indicators are substances that change color in response to changes in pH.
  • Common indicators include litmus paper, phenolphthalein, and methyl orange.
  • Reactivity of Solids
  • Solid compounds are generally less reactive with indicators compared to their aqueous solutions.
  • This is because the ions in solids are not free to interact with the indicator.

Question 37

UP CNET 2025• Chemistry

Which of the following electrolytes is used in the electrolytic refining of copper?

  1. AOption (a)

    Sodium sulphate

  2. BOption (b)

    Cuprous chloride

  3. COption (c)

    Copper oxide

  4. DOption (d)

    Copper sulphate

View answer & explanation

Correct answer

Answer: (d)D.

Copper sulphate

Why this answer is correct

The correct answer is Copper sulphate.

Key Points

  • Copper sulphate (CuSO4) is commonly used as the electrolyte in the electrolytic refining of copper.
  • In this process, impure copper is used as the anode, and a pure copper sheet is used as the cathode.
  • When an electric current is passed through the electrolyte solution, copper ions from the anode dissolve into the solution and are deposited on the cathode.
  • Impurities present in the impure copper either remain in the solution or fall to the bottom as anode sludge.
  • This process helps in obtaining high-purity copper from impure copper.

Additional Information

  • Electrolytic Refining
  • It is a process used to purify metals by electrolysis.
  • This method is used for metals like copper, zinc, and aluminum.
  • The process ensures the removal of impurities and produces high-purity metal.
  • Copper Extraction
  • Copper is extracted from its ores through processes like smelting and electrolysis.
  • The extracted copper is further refined through electrolytic refining to achieve high purity.
  • Applications of Copper
  • Copper is widely used in electrical wiring due to its excellent electrical conductivity.
  • It is also used in plumbing, roofing, and industrial machinery.
  • Copper alloys, such as bronze and brass, have various applications in decorative arts and manufacturing.

Question 38

UP CNET 2025• Chemistry

Which of the following is produced when hydrochloric acid reacts with water?

  1. AOption (a)

    Both H₃O⁺ and Cl⁻

  2. BOption (b)

    Both HO⁻ and Cl⁻

  3. COption (c)

    Only Cl⁻

  4. DOption (d)

    Only H₃O⁺

View answer & explanation

Correct answer

Answer: (a)A.

Both H₃O⁺ and Cl⁻

Why this answer is correct

The correct answer is Both H₃O⁺ and Cl⁻.

Key Points

  • When hydrochloric acid (HCl) reacts with water (H₂O), it dissociates completely to form hydronium ions (H₃O⁺) and chloride ions (Cl⁻).
  • This dissociation is a characteristic of strong acids like HCl, which ionize completely in aqueous solutions.
  • The reaction can be written as: HCl + H₂O → H₃O⁺ + Cl⁻.
  • Hydrochloric acid is a common laboratory reagent and is used in various industrial and chemical processes.

Additional Information

  • Dissociation of Acids:
  • Acids dissociate in water to release hydrogen ions (H⁺). In the case of strong acids like HCl, this process is complete.
  • The hydrogen ions do not exist freely in solution but rather associate with water molecules to form hydronium ions (H₃O⁺).
  • The general reaction for the dissociation of a strong acid HA in water is: HA + H₂O → H₃O⁺ + A⁻.
  • Hydronium Ion (H₃O⁺):
  • The hydronium ion is a positively charged ion formed when a hydrogen ion (H⁺) associates with a water molecule (H₂O).
  • It is represented as H₃O⁺ and is the form in which protons are found in aqueous solution.
  • Chloride Ion (Cl⁻):
  • The chloride ion is a negatively charged ion formed when hydrochloric acid dissociates in water.
  • It is represented as Cl⁻ and is a common anion found in various salts and solutions.
  • Hydrochloric Acid (HCl):
  • Hydrochloric acid is a strong acid that completely ionizes in water to form hydronium ions and chloride ions.
  • It is widely used in the chemical industry for pH control, as a reagent in laboratories, and in the production of chlorides.

Question 39

UP CNET 2025• Chemistry

Which of the following element is used in the process of galvanization?

  1. AOption (a)

    Sodium

  2. BOption (b)

    Copper

  3. COption (c)

    Zinc

  4. DOption (d)

    Tin

View answer & explanation

Correct answer

Answer: (c)C.

Zinc

Why this answer is correct

The correct answer is Zinc.

Key Points

  • Zinc is the primary element used in the process of galvanization.
  • Galvanization is a method used to protect iron and steel from rusting.
  • During galvanization, a layer of zinc is applied to the surface of the metal.
  • Zinc's natural resistance to corrosion helps prevent the underlying metal from rusting.

Additional Information

  • Hot-dip Galvanization
  • In this process, the metal is dipped into a bath of molten zinc.
  • This method creates a thick, durable layer of zinc on the surface.
  • Electro-galvanization
  • This process uses an electric current to deposit a thin layer of zinc.
  • It is often used for smaller items like screws and nails.
  • Corrosion Protection
  • Zinc acts as a sacrificial anode, meaning it will corrode first before the iron or steel does.
  • This property significantly extends the lifespan of galvanized materials.
  • Applications of Galvanized Metals
  • Galvanized steel is commonly used in construction, automotive, and electrical industries.
  • Examples include roofing materials, car bodies, and electrical boxes.

Question 40

UP CNET 2025• Chemistry

The conductivity of a weak acid HA of concentration 0.001mol L−1 is 2.0 × 10−5Scm−1 . 

If Λm °(HA) = 190Scm2mol−1, the ionization constant (Ka) of HA is equal to ________ 10−6  ×

  1. AOption (a)

    24

  2. BOption (b)

    48

  3. COption (c)

    12

  4. DOption (d)

    45

View answer & explanation

Correct answer

Answer: (c)C.

12

Why this answer is correct

CONCEPT:

Conductivity and Ionization Constant (Ka)

  • The conductivity (κ ) of a solution is related to the molar conductivity (Λm ) and the concentration (c) of the electrolyte.
  • The relationship is given by:

Λm=κc

  • Molar conductivity at infinite dilution (Λ∘m ) is the conductivity of an electrolyte at such a low concentration that further dilution does not change its molar conductivity.
  • The degree of ionization (α) of a weak electrolyte can be calculated using the formula:

α=ΛmΛ∘m

  • The ionization constant (Ka ) is related to the degree of ionization (α) and the concentration (c) by:

Ka=cα2

EXPLANATION:

  • Given:
  • Concentration, c=0.001mol/L
  • Conductivity, κ=2.0×10−5S/cm
  • Molar conductivity at infinite dilution, Λ∘m=190S cm2/mol
  • Calculate molar conductivity (Λm ):
  • Λm=κc
  • Λm=2.0×10−5S/cm0.001mol/L
  • Λm=2.0×10−2S cm2/mol
  • Calculate degree of ionization (α):
  • α=ΛmΛ∘m
  • α=2.0×10−2S cm2/mol190S cm2/mol
  • α=2.0×10−2190
  • α=1.05×10−4
  • Calculate ionization constant (Ka ):
  • Ka=cα2
  • Ka=0.001×(1.05×10−4)2
  • Ka=0.001×1.1025×10−8
  • Ka=1.1025×10−11
  • Ka=11×10−12
  • Ka=12×10−12≈12×10−6

Therefore, the ionization constant (Ka ) of HA is approximately 12 × 10-6.