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Logic: In the pervious alphabet, 1 is added in the positional value to get the required set of alphabets.

But the second and third alphabet is applying logic diagonally.

GUN is coded as HVO is shown as below,

Similarly, PEN will be coded as QOF.

Hence, the correct answer is "QOF".

Statement: Should students study in early hours of morning?

Arg 1: Yes, mind is fresh and alert at that time.

Explanation: This argument is strong because it provides a clear and relevant benefit of studying in the early morning hours. It highlights the freshness and alertness of the mind, which can improve concentration and learning efficiency.

Arg 2: No, early risers feel sleepy throughout the day.

Explanation: This argument is weaker because it assumes that all early risers will feel sleepy throughout the day, which may not be universally true. The impact of waking up early varies from person to person, and some may adjust their schedules to avoid feeling sleepy.

Conclusion:

The first argument is strong because it provides a direct benefit related to studying efficiency.

The second argument is weaker as it makes a general assumption that may not apply to everyone.

Hence, the correct answer is "Only Arg. 1 is strong

Logic: Add the digits of each number and subtract that sum form maximum to minimum of each equation. Then that sum is equal to RHS.

⇒ 84 × 13 = 8 

⇒ (8 + 4) - (1 + 3) = 12 - 4 = 8 = 8 (RHS)

Now, check for the other equation,

⇒ 37 × 13 = 6

⇒ (3 + 7) - (1 + 3) = 10 - 4 = 6 = 6 (RHS)

Similar logic will be applied in the required equation, 

⇒ 56 × 22 = ?

⇒ (5 + 6) - (2 + 2)

⇒ 11 - 4 = 7

Hence, the correct answer is "7".

Checking with the options,

Option 1). -, +, -

⇒ 8 - 8 + 2 - 1 = 10 - 9 = 1 ≠ 14

Option 2). -, /, × 

⇒ 8 - 8 ÷ 2 × 1 = 8 - 4 = 4 ≠ 14

Option 3).  ×, /, - 

⇒ 8 × 8 ÷ 2 - 1 = 8 × 4 - 1 = 32 - 1 = 31 ≠ 14

Option 4). +, -, × 

⇒ 8 + 8 - 2 × 1 = 16 - 2 ⇒ 14 = 14 (RHS)

Hence, the correct answer is "+, -, ".

Logic: Opposite numbers outside the circle are multiplied with each other and then add to get the number which is given in the circle.

First Figure -  

⇒ (5 × 6) + (4 × 3) = 30 + 12 = 42

Third Figure - 

⇒ (3 × 6) + (9 × 2) = 18 + 18 = 36

Similarly, 

Second Figure - 

⇒ (8 × 2) + (7 × 5) = 16 + 35 = 51

So, the final figure is as follow,

Hence, the correct answer is "51".

The correct answer is "pages".

Pages: Essential for the physical existence of a traditional book. Without pages, it wouldn't be a book but perhaps a different form of content like a scroll, a document, or an e-book.

Story: Not all books contain stories. Examples include textbooks, reference books, and manuals.

Binding: While common, binding is not universal. Some books, such as spiral-bound or loose-leaf books, might not have traditional binding.

Content: Content is essential, but content alone without pages does not constitute a book in the traditional sense. An e-book, for example, has content but no pages.

The given words are arranged as your action of "Visiting a Doctor".

They must be arranged in the order in the sequence they will occur.

5. Patient
6. Doctor
7. Diagnosis
8. Treatment
9. Bill

Hence, the correct sequence is "5, 3, 4, 2, 1".

Logic: Positional value of alphabets are increasing by 1 and numbers are decreasing by 3.

Hence, the correct answer is "W26".

Given:

Ladder's length = 30m

Wall's height = 15m

Concept used:

In trigonometry,

In right angled triangle,

Sin θ = perpendicular/hypotenuse

Calculation:

Here, perpendicular = Wall's height = 15m

Hypotenuse = Ladder's length = 30m

Sin θ = perpendicular/hypotenuse

⇒  Sin θ = 15/30 = 1/2

⇒  Sin θ = sin 30º

⇒ θ = 30º

∴ Option 2 is correct.

Concept:

Let us consider sequence a1, a2, a3 …. an is an A.P.

• Common difference “d”= a2 – a1 = a3 – a2 = …. = an – an – 1
• nth term of the A.P. is given by an = a + (n – 1) d
• Sum of the first n terms = Sn =$\rm \frac n 2$ [2a + (n − 1) × d]= $\rm \frac n 2$(a + l)

Where, a = First term, d = Common difference, n = number of terms, an = nth term and l = Last term

Calculation:

Here 1^st term = a = 102 (Which is the 1^st term greater than 100 that is divisible by 6.) 

The last term less than 400, Which is divisible by 6 is 396. 

Terms in the AP; 102, 108, 114 … 396

Now

First term = a = 102

Common difference = d = 108 - 102 = 6

n^th term = 396

As we know, n^th term of AP = a_n = a + (n – 1) d

⇒ 396 = 102 + (n - 1) × 6

⇒ 294 = (n - 1) × 6

⇒ (n - 1) = 49

∴ n = 50

Now,

Sum =  $\rm \frac n 2$(a + l) =  $\rm \frac {50}{2}$(102 + 396) = 25 × 498 = 12450.