Hooke's law is valid in which material deformation region?
- AOption (a)
Plastic
- BOption (b)
Elastic
- COption (c)
Brittle
- DOption (d)
Viscoelastic
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Correct answer
Plastic
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Browse complete papersHooke's law is valid in which material deformation region?
Plastic
Elastic
Brittle
Viscoelastic
Correct answer
Plastic
Which of the following quantities is expressed without any unit?
Young's Modulus
Stress
Strain
Yield point
Correct answer
Young's Modulus
What is the formula for Modulus of Rigidity?
Ratio of shear stress to shear strain
Ratio of ultimate stress to permissible stress
Ratio of tensile stress to tensile strain
Ratio of force to unit area
Correct answer
Ratio of shear stress to shear strain
During a tensile test on ductile material, necking begins at which stage?
Yield point
Ultimate tensile strength
Elastic limit
Breaking point
Correct answer
Yield point
A 2 m long steel rod with 20 mm diameter experiences 40 kN axial tensile load. Given that E = 200 GPa, the rod's elongation is approximately:
0.13 mm
0.25 mm
0.33 mm
1.27 mm
Correct answer
0.13 mm
The ability of a material to absorb energy before fracture defines which of the following properties:
Toughness
Resilience
Hardness
Plasticity
Correct answer
Toughness
A bar under 250 MPa engineering stress and 0.20 engineering strain has what true stress value?
100 MPa
300 MPa
350 MPa
400 MPa
Correct answer
100 MPa
A thin-walled spherical shell has an internal diameter of d, which is exposed to an internal pressure p. If \( \sigma_t \) represents the tensile stress of the shell's material, then the shell's thickness (t) can be determined as:
\( p.d/\sigma_t \)
\( p.d/3\sigma_t \)
\( p.d/2\sigma_t \)
\( p.d/4\sigma_t \)
Correct answer
\( p.d/\sigma_t \)
A thick cylinder with an internal diameter of d and an external diameter of 2d is exposed to an internal pressure p. The maximum hoop stress that occurs in the cylinder is then:
\( \frac{2}{3}p \)
p
\( \frac{5}{3}p \)
2p
Correct answer
\( \frac{2}{3}p \)
The frictional torque in a flat pivot bearing under uniform pressure distribution is given by:
\( \frac{1}{2}(\mu \times W \times R) \)
\( \frac{2}{3}(\mu \times W \times R) \)
\( \frac{3}{4}(\mu \times W \times R) \)
\( (\mu \times W \times R) \)
Correct answer
\( \frac{1}{2}(\mu \times W \times R) \)