Search Previous Year Questions

Given that December 31 of a leap year is a Monday.

Therefore, the first day of the next year, January 1, will be a Tuesday.

To find the day of the week on March 1 of the next year, we calculate the total number of days passed in January and February:

Days in January = 31 days

Days in February = 28 days (as it is a non-leap year)

Total days from January 1 to March 1 = 31 + 28 = 59 days

To find the number of odd days, we divide by 7: 59 ÷ 7 = 8 weeks and 3 odd days.

Day on March 1 = Tuesday + 3 days = Friday.

Now, let us list the occurrences of Mondays and Thursdays in March (31 days):

Since March 1 is a Friday, the calendar for the month is as follows:

1. Mondays fall on: March 4, 11, 18, and 25. (Total = 4 Mondays)
2. Thursdays fall on: March 7, 14, 21, and 28. (Total = 4 Thursdays)

Total number of Mondays and Thursdays = 4 + 4 = 8.

Hence, the correct answer is “Option 2”.

We need to find the day on 1^st January 1611.

Period until 31^st December 1610 = 1600 years + 10 years.

Odd days in 1600 years = 0 odd days (as it is a multiple of 400).

Now, calculate odd days in the remaining 10 years (from 1601 to 1610):

Number of leap years in these 10 years = 2 (Years 1604 and 1608).

Number of ordinary years in these 10 years = 10 − 2 = 8.

Odd days from 2 leap years = 2 × 2 = 4 odd days.

Odd days from 8 ordinary years = 8 × 1 = 8 odd days.

Total odd days in 10 years = 4 + 8 = 12 odd days.

To simplify, 12 ÷ 7 = 1 week and 5 odd days.

Total odd days until 31^st December 1610 = 0 (from 1600 years) + 5 = 5 odd days.

Based on the day mapping, 5 odd days indicates that 31^st December 1610 was a Friday.

The next day, 1^st January 1611, is Friday + 1 = Saturday.

Hence, the correct answer is “Option 3”.

5 persons P, B, C, G and H are sitting around a circular table facing towards the centre (not necessarily in the same order).

1. B is second to the left of H.
2. G is the immediate neighbour of B and H.
3. C is not the immediate neighbour of B. 

"B" is the second to the right of C.

Hence, the correct answer is “Option 1”.

7 boys A, B, C, D, E, F and G are sitting in a row facing north (not necessarily in the same order).

1. E is second to the left of A.
2. D is fourth to the left of F.
3. A is fifth from the right end of the row.
4. B is third to the left of G. 

B is to the immediate left of C.

Hence, the correct answer is “Option 1”.

Family chart:

Family tree,

Therefore, D is the husband of C (the mother), which makes D the Father of A.

Hence, the correct answer is 'Option 2'.

Given word: CONTAMINATION

(1) ANIMATION → Can be formed as all the required letters are present in the given word.

(2) CINNAMON → Can be formed as all the required letters are present in the given word.

(3) NOTATIONS → Can not be formed as it requires letter "S", whereas the given word does not contains "S".

(4) ATOMIC → Can be formed as all the required letters are present in the given word.

Hence, the correct answer is “Option 3”.

The given word is: JOURNALISM

The alphabetical arrangement is: 

To find the third letter from the right end, we count from the end of the sequence:

3^rd from right end = R

The third letter from the right end is R.

The correct answer is "Option 4".

First, we find the prime factors for each number:

The prime factors involved are 2, 3, and 5.

The highest power of 2 is 22.

The highest power of 3 is 32.

The highest power of 5 is 52.

LCM = 22 × 32 × 52

LCM = 4 × 9 × 25

LCM = 36 × 25

LCM = 900

Therefore, the smallest positive integer divisible by 45, 60, and 75 is 900.

Hence, the correct answer is “Option 4”.

In a farm, cows have 4 legs and 1 head each, while hens have 2 legs and 1 head each.

Let the number of cows be C and the number of hens be H.

C + H = 50 ---- (Equation 1)

(4 × C) + (2 × H) = 140

2C + H = 70 ---- (Equation 2)

Subtract Equation 1 from Equation 2:

(2C + H) − (C + H) = 70 − 50

C = 20

So, the total number of cows in the farm is 20.

Hence, the correct answer is “Option 1”.

Alternate Method 

If all 50 animals were hens, the total legs would be 50 × 2 = 100.

Difference in legs = 140 − 100 = 40.

Difference in legs per animal (Cow vs Hen) = 4 − 2 = 2.

Number of cows = 40 ÷ 2 = 20.

The correct answer is option 1.

Logic followed here is,

275 + 16 = 291

291 + 24 = 315

315 + 32 = 347

347 + 40 = 387

Hence, the correct answer is “Option 2”.