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Question 851

SBI Clerk 2025• Numerical Ability

The line graph given below shows the number of boys participating in a sports event on four different days of a week. Study the graph carefully and answer the following questions. 

If 20% of the boys participating on Monday and 30% of the boys participating on Wednesday were selected for the final round, then how many boys were not selected from these two days together?

  1. AOption (a)

    504

  2. BOption (b)

    528

  3. COption (c)

    582

  4. DOption (d)

    516

  5. EOption (e)

    540

View answer & explanation

Correct answer

Answer: (c)C.

582

Why this answer is correct

Boys not selected from Monday = 80% of 360 = 288

Boys not selected from Wednesday = 70% of 420 = 294

Total not selected = 288 + 294 = 582

Question 852

SBI Clerk 2025• Numerical Ability

The line graph given below shows the number of boys participating in a sports event on four different days of a week. Study the graph carefully and answer the following questions. 

The number of boys participating on Sunday is what percentage less than the number of boys participating on Wednesday?

  1. AOption (a)

    35%

  2. BOption (b)

    40%

  3. COption (c)

    42.85%

  4. DOption (d)

    45%

  5. EOption (e)

    50%

View answer & explanation

Correct answer

Answer: (c)C.

42.85%

Why this answer is correct

Difference between the number of boys participating = 420 – 240 = 180

Required Percentage = (180/420) ×100 = 42.85%

Question 853

SBI Clerk 2025• Numerical Ability

The ratio of A to B is 4 : 5 and the ratio of A to C is 4 : 6. If the sum of B and C is 66, find the sum of A and B.

  1. AOption (a)

    45

  2. BOption (b)

    48

  3. COption (c)

    54

  4. DOption (d)

    60

  5. EOption (e)

    50

View answer & explanation

Correct answer

Answer: (c)C.

54

Why this answer is correct

Shortcut Trick

Since A is common in both ratios and has the same value (4), we can combine them directly.

Ratio A : B : C = 4 : 5 : 6.

Sum of B + C = 5 + 6 = 11 units → 66. So, 1 unit = 6.

Sum of A + B = 4 + 5 = 9 units → 9 × 6 = 54.

∴ The correct answer is 54.

Alternate Method

Given:

Ratio A : B = 4 : 5

Ratio A : C = 4 : 6

Sum of B and C = 66

Calculations:

⇒ Since A is 4 in both ratios, A : B : C = 4 : 5 : 6

⇒ Let A = 4x, B = 5x, and C = 6x

⇒ B + C = 5x + 6x = 11x

⇒ 11x = 66

⇒ x = 66 ÷ 11 = 6

⇒ A + B = 4x + 5x = 9x

⇒ A + B = 9 × 6 = 54

∴ The correct answer is 54.

Additional Information

Combining Ratios

To combine ratios like A:B and B:C, make the common term (B) equal by multiplying the ratios by suitable constants.

Compound Ratio

The compound ratio of a:b and c:d is (ac):(bd), found by multiplying the corresponding terms.

Proportion Rule

If a:b = c:d, then the product of extremes equals the product of means: a × d = b × c.

Question 854

SBI Clerk 2025• Numerical Ability

A shopkeeper marks an article 50% above its cost price and then gives a discount of ₹360. If the difference between the cost price and the profit earned in this transaction is ₹960, find the cost price of the article.

  1. AOption (a)

    ₹1000

  2. BOption (b)

    ₹1200

  3. COption (c)

    ₹1500

  4. DOption (d)

    ₹900

  5. EOption (e)

    ₹1100

View answer & explanation

Correct answer

Answer: (b)B.

₹1200

Why this answer is correct

Shortcut Trick

Let Cost Price (CP) = 100x. Then Marked Price (MP) = 150x.

Selling Price (SP) = 150x − 360. Profit = SP − CP = 50x − 360.

Given: CP − Profit = 960 ⇒ 100x − (50x − 360) = 960.

50x + 360 = 960 ⇒ 50x = 600 ⇒ 100x = 1200.

∴ The correct answer is ₹1200.

Alternate Method

Given: Markup = 50%, Discount = ₹360, CP − Profit = ₹960.

Formula: Profit = SP − CP; SP = MP − Discount.

⇒ Let Cost Price (CP) = C.

⇒ Marked Price (MP) = 1.5C.

⇒ Selling Price (SP) = 1.5C − 360.

⇒ Profit (P) = (1.5C − 360) − C = 0.5C − 360.

⇒ According to the question: C − (0.5C − 360) = 960.

⇒ 0.5C + 360 = 960.

⇒ 0.5C = 600.

⇒ C = 600 ÷ 0.5 = 1200.

∴ The correct answer is ₹1200.

Additional Information

Marked Price and Discount

Marked Price is the price listed on the product. Discount is always calculated on the Marked Price: SP = MP × (100 − Discount%)/100.

Profit and Loss Basics

Profit = SP − CP. Profit percentage is always calculated on the Cost Price: Profit% = (Profit/CP) × 100.

Markup Percentage

Markup is the extra amount added to the CP to fix the MP. Markup% = [(MP − CP)/CP] × 100.

Question 855

SBI Clerk 2025• Numerical Ability

A and B enter into a partnership. A invests ₹X and B invests ₹2500. After 4 months, A withdraws 50% of his investment. At the end of the year, the profit is shared between A and B in the ratio 4 : 3. Find the value of X.

  1. AOption (a)

    ₹4000

  2. BOption (b)

    ₹5000

  3. COption (c)

    ₹6000

  4. DOption (d)

    ₹4500

  5. EOption (e)

    ₹5500

View answer & explanation

Correct answer

Answer: (b)B.

₹5000

Why this answer is correct

Shortcut Trick

Profit Ratio = (CapitalA × TimeA) : (CapitalB × TimeB)

A's effective investment = (X × 4) + (0.5X × 8) = 4X + 4X = 8X

B's effective investment = 2500 × 12 = 30000

Ratio 8X : 30000 = 4 : 3 ⇒ 2X : 7500 = 4 : 3 ⇒ X = 5000

∴ The correct answer is ₹5000.

Alternate Method

Given:

Investment of A = ₹X for 4 months, then 0.5X for 8 months.

Investment of B = ₹2500 for 12 months.

Profit Ratio A : B = 4 : 3.

Calculations:

⇒ Total investment of A = (X × 4) + (X/2 × 8) = 4X + 4X = 8X

⇒ Total investment of B = 2500 × 12 = 30000

⇒ Ratio of Profits = 8X / 30000 = 4 / 3

⇒ 8X × 3 = 30000 × 4

⇒ 24X = 120000

⇒ X = 120000 ÷ 24

⇒ X = 5000

∴ The correct answer is ₹5000.

Additional Information

Partnership Profit Sharing Rule

The profit shared between partners is directly proportional to the product of their capital and the time period for which the capital is invested: P1 : P2 = C1T1 : C2T2.

Variable Investment

If a partner changes their investment during the period, the total investment is calculated as the sum of (Amount × Duration) for each interval.

Active vs Sleeping Partner

An active partner may receive an additional commission or salary from the profit before the remaining profit is divided according to the investment ratio.

Question 856

SBI Clerk 2025• Numerical Ability

A person's monthly income is ₹45,000. He spends 10% on groceries, 20% on rent, and ₹3,500 on others. He saves the remaining amount. Find the difference between his monthly savings and his expenditure on groceries.

  1. AOption (a)

    ₹24,000

  2. BOption (b)

    ₹22,500

  3. COption (c)

    ₹23,500

  4. DOption (d)

    ₹25,000

  5. EOption (e)

    ₹23,000

View answer & explanation

Correct answer

Answer: (c)C.

₹23,500

Why this answer is correct

Shortcut Trick

Groceries = 10% of 45,000 = ₹4,500

Rent = 20% of 45,000 = ₹9,000

Savings = 45,000 − (4,500 + 9,000 + 3,500) = ₹28,000

Difference = Savings − Groceries = 28,000 − 4,500 = ₹23,500

∴ The correct answer is ₹23,500.

Alternate Method

Given:

Monthly Income = ₹45,000

Groceries = 10% | Rent = 20% | Others = ₹3,500

Calculations:

⇒ Expenditure on Groceries = 10/100 × 45,000 = ₹4,500

⇒ Expenditure on Rent = 20/100 × 45,000 = ₹9,000

⇒ Total Expenditure = 4,500 + 9,000 + 3,500 = ₹17,000

⇒ Monthly Savings = Total Income − Total Expenditure

⇒ Monthly Savings = 45,000 − 17,000 = ₹28,000

⇒ Required Difference = Savings − Groceries

⇒ Difference = 28,000 − 4,500 = ₹23,500

∴ The correct answer is ₹23,500.

Additional Information

Income and Expenditure Formula

Income = Expenditure + Savings. This fundamental identity is used to calculate any one missing component when the other two are known.

Percentage Calculation

To find x% of a value Y, use the formula: (x ÷ 100) × Y. For quick calculations, 10% is simply the value divided by 10.

Successive Percentage vs. Flat Percentage

If percentages are of the 'remaining' amount, use the multiplying factor method. If they are of the 'total' income, simply add the percentages together.

Question 857

SBI Clerk 2025• Numerical Ability

Study the following table carefully and answer the questions given below.

The table shows the number of students playing Cricket, Football and Hockey in four different colleges (A, B, C and D).

CollegeCricketFootballHockey
A240180120
B300240160
C360280200
D400320240

The number of students playing Cricket in Colleges B and C together is what percentage more than the number of students playing Football in Colleges A and D together? 

  1. AOption (a)

    12%

  2. BOption (b)

    18%

  3. COption (c)

    24%

  4. DOption (d)

    32%

  5. EOption (e)

    36%

View answer & explanation

Correct answer

Answer: (d)D.

32%

Why this answer is correct

Cricket players in B and C together = 300 + 360 = 660

Football players in A and D together = 180 + 320 = 500

Percentage increase = {660 – 500}/500 x 100) = 32%

Question 858

SBI Clerk 2025• Numerical Ability

Study the following table carefully and answer the questions given below.

The table shows the number of students playing Cricket, Football and Hockey in four different colleges (A, B, C and D).

CollegeCricketFootballHockey
A240180120
B300240160
C360280200
D400320240

What is the average number of students playing Hockey in all the colleges?

  1. AOption (a)

    160

  2. BOption (b)

    170

  3. COption (c)

    180

  4. DOption (d)

    190

  5. EOption (e)

    200

View answer & explanation

Correct answer

Answer: (c)C.

180

Why this answer is correct

Total Hockey players = 120 + 160 + 200 + 240 = 720

Required Average = 720 ÷ 4 = 180

Question 859

SBI Clerk 2025• Numerical Ability

Study the following table carefully and answer the questions given below.

The table shows the number of students playing Cricket, Football and Hockey in four different colleges (A, B, C and D).

CollegeCricketFootballHockey
A240180120
B300240160
C360280200
D400320240

What is the ratio between the number of students playing Cricket in College A and Football in College D?

  1. AOption (a)

    2:3

  2. BOption (b)

    3:4

  3. COption (c)

    4:5

  4. DOption (d)

    5:6

  5. EOption (e)

    6:7

View answer & explanation

Correct answer

Answer: (b)B.

3:4

Why this answer is correct

Cricket players in College A = 240

Football players in College D = 320

Required ratio = 240:320 = 3:4

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