Search Previous Year Questions

Find real questions from previous competitive exam papers with answers and solutions.

Leave the keyword blank to browse saved questions for your selected exam, newest papers first. Add a keyword, year or topic to narrow the results.

Browse complete papers
Showing 10 question(s)
Clear

Question 651

SBI Clerk 2025• Numerical Ability

What will come in place of the question mark (?) in the following question?

60% of 360 + 56 ÷ 8 = ? + 5 × 4

  1. AOption (a)

    213

  2. BOption (b)

    223

  3. COption (c)

    203

  4. DOption (d)

    233

  5. EOption (e)

    133

View answer & explanation

Correct answer

Answer: (c)C.

203

Why this answer is correct

Given:

60% of 360 + 56 ÷ 8 = ? + 5 × 4

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

60% of 360 + 56 ÷ 8 = ? + 5 × 4

⇒ (60/100) × 360 + 7 = ? + 20

⇒ (3/5) × 360 + 7 – 20 = ?

⇒ ? = 216 – 13

⇒ ? = 203

∴ 203 will come in place of the question mark (?).

Question 652

SBI Clerk 2025• Numerical Ability

What should come in the place of question mark ‘?’ in the following question?

2/9 of 405 ÷ 15 + 23 = √(?)

  1. AOption (a)

    841

  2. BOption (b)

    800

  3. COption (c)

    843

  4. DOption (d)

    851

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

841

Why this answer is correct

Concept:

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket.

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated. 

Calculation:

Applying BODMAS:

Taking square both sides

⇒ (2/9 of 405 ÷ 15 + 23)2 = x

⇒ (90 ÷ 15 + 23)2 = x

⇒ (6 + 23)2 = x

⇒ (29)2 = x

⇒ x = 841

Question 653

SBI Clerk 2025• Numerical Ability

What will come in place of the question mark ‘?’ in the following question?

√(5/8 × 32% of 1200 ÷ 16 + 34) = ?

  1. AOption (a)

    9

  2. BOption (b)

    6

  3. COption (c)

    8

  4. DOption (d)

    7

  5. EOption (e)

    12

View answer & explanation

Correct answer

Answer: (d)D.

7

Why this answer is correct

√(5/8 × 32% of 1200 ÷ 16 + 34)

Applying BODMAS Rule;

⇒ √(5/8 × (32/100) × 1200 ÷ 16 + 34)

⇒ √(5/8 × 384 ÷ 16 + 34)

⇒ √(5/8 × 24 + 34)

⇒ √(15 + 34)

⇒ √49

⇒ 7

Question 654

SBI Clerk 2025• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

125% of 560 + 22% of 450 = ?

  1. AOption (a)

    799

  2. BOption (b)

    782

  3. COption (c)

    700

  4. DOption (d)

    749

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

799

Why this answer is correct

Given:

125% of 560 + 22% of 450 = ?

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

125% of 560 + 22% of 450 = ?

⇒ 125/100 × 560 + 22/100 × 450

⇒ 5/4 × 560 + 11/50 × 450

⇒ 700 + 99

⇒ 799

∴ The value of ? is 799.

Question 655

SBI Clerk 2025• Numerical Ability

What will come in place of the question mark (?) in the following equation?

25 × 4 ÷ 5 = 80 ÷ 20 × ?

  1. AOption (a)

    8

  2. BOption (b)

    10

  3. COption (c)

    12

  4. DOption (d)

    5

  5. EOption (e)

    17

View answer & explanation

Correct answer

Answer: (d)D.

5

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below, 

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, 

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next, 

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, 

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated 

 25 × 4 ÷ 5 = 80 ÷ 20 × ?

⇒ 25 × (4/5) = 4 × ?

⇒ 5 × 4 = 4 × ?

∴ ? = 5

Question 656

SBI Clerk 2025• Numerical Ability

What should come in place of question mark (?) in the following question?

153 ÷ 17 × (9)2 – 53 = (?)2

  1. AOption (a)

    ±26

  2. BOption (b)

    √26

  3. COption (c)

    –729

  4. DOption (d)

    27

  5. EOption (e)

    √27

View answer & explanation

Correct answer

Answer: (a)A.

±26

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

⇒ 153 ÷ 17 × (9)2 – 53 = (?)2

⇒ 9 × (9)2 – 53 = (?)2

⇒ 729 – 53 = (?)2

⇒ (±26)2 = (?)2

∴ ? = ±26

Question 657

SBI Clerk 2025• Numerical Ability

The speed of a boat in still water is 18 km/hr. When traveling upstream, the boat covers 60 km in 4 hours. Find the difference between the distance the boat can cover in 3 hours while traveling downstream and 173 km.

  1. AOption (a)

    112 km 

  2. BOption (b)

    92 km 

  3. COption (c)

    110 km 

  4. DOption (d)

    98 km 

  5. EOption (e)

    120 km

View answer & explanation

Correct answer

Answer: (c)C.

110 km 

Why this answer is correct

Shortcut Trick

Upstream speed (u) = 60 km ÷ 4 hours = 15 kmph.

Stream speed (v) = Still water speed − Upstream speed = 18 − 15 = 3 kmph.

Downstream speed (d) = Still water speed + Stream speed = 18 + 3 = 21 kmph.

Downstream distance (3 hr) = 21 × 3 = 63 km.

Difference = 173 − 63 = 110 km.

∴ The correct answer is 110 km.

Alternate Method

Given: Speed of boat in still water (x) = 18 kmph, Upstream distance = 60 km, Time = 4 hr.

Formula Used: Speed = Distance ÷ Time; Upstream speed = x − y; Downstream speed = x + y.

⇒ Upstream Speed = 60 ÷ 4 = 15 kmph.

⇒ Let Stream Speed be y kmph.

⇒ 18 − y = 15

⇒ y = 3 kmph.

⇒ Downstream Speed = 18 + 3 = 21 kmph.

⇒ Distance covered in 3 hours downstream = 21 × 3 = 63 km.

⇒ Required Difference = 173 − 63 = 110 km.

∴ The correct answer is 110 km.

Additional Information

Still Water Speed Formula

Speed of boat in still water (x) = (Downstream speed + Upstream speed) ÷ 2.

Stream Speed Formula

Speed of current/stream (y) = (Downstream speed − Upstream speed) ÷ 2.

Average Speed of Boat

Average speed for a round trip = (Downstream Speed × Upstream Speed) ÷ Still Water Speed.

Question 658

SBI Clerk 2025• Numerical Ability

Directions: Study the given table carefully and answer the given questions. 

The following table shows the number of mobile covers sold by three persons A, B, and C in three different months March, April, and May.

PersonMarchAprilMay
A947292
B12099102
C886570

Find the average number of mobile covers sold by B in all the given months.

  1. AOption (a)

    103

  2. BOption (b)

    105

  3. COption (c)

    107

  4. DOption (d)

    111

  5. EOption (e)

    114

View answer & explanation

Correct answer

Answer: (c)C.

107

Why this answer is correct

The total number of mobile covers sold by B.

Total = March + April + May = 120 + 99 + 102 = 321

The average is calculated as:

Average = Total / Number of months

Here, the number of months = 3.

So:

Average = 321 / 3 = 107

Thus, the average number of mobile covers sold by B in all the given months is 107.

Question 659

SBI Clerk 2025• Numerical Ability

Directions: Study the given table carefully and answer the given questions. 

The following table shows the number of mobile covers sold by three persons A, B, and C in three different months March, April, and May.

PersonMarchAprilMay
A947292
B12099102
C886570

If in the month of April, A sold each mobile cover in Rs.50, then find the total revenue generated by him in April.

  1. AOption (a)

    Rs. 4800

  2. BOption (b)

    Rs. 3600

  3. COption (c)

    Rs. 6400

  4. DOption (d)

    Rs. 5600

  5. EOption (e)

    Rs. 2400

View answer & explanation

Correct answer

Answer: (b)B.

Rs. 3600

Why this answer is correct

A sold 72 mobile covers in April.

Each mobile cover is sold for Rs. 50.

Total revenue = Number of covers sold × Price per cover

Total revenue =72 × 50 = 3600 .

Thus, the total revenue generated by A in April is Rs. 3600.

Question 660

SBI Clerk 2025• Numerical Ability

Directions: Study the given table carefully and answer the given questions. 

The following table shows the number of mobile covers sold by three persons A, B, and C in three different months March, April, and May.

PersonMarchAprilMay
A947292
B12099102
C886570

The number of mobile covers sold by C in April is what percent of the number of mobile covers sold by B in March?

  1. AOption (a)

    62.13% 

  2. BOption (b)

    44.72% 

  3. COption (c)

    88.22% 

  4. DOption (d)

    54.17% 

  5. EOption (e)

    60.42%

View answer & explanation

Correct answer

Answer: (d)D.

54.17% 

Why this answer is correct

C in April: 65 mobile covers.

B in March: 120 mobile covers.

The formula to calculate the percentage is:

Percentage = Part / Whole × 100

Here:

Part = Number of mobile covers sold by C in April = 65.

Whole = Number of mobile covers sold by B in March = 120.

Substitute the values:

Percentage = 65 / 120 × 100

65 / 120 = 0.5417

Percentage = 0.5417 × 100 = 54.17%

Thus, the number of mobile covers sold by C in April is 54.17% of the number of mobile covers sold by B in March.

Page 66