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**Given

Statements:

** P > A ≥ R; A = C ≤ H < U = T > E

On combining: P > A = C ≥ R; R ≤ A = C ≤ H < U = T > E

Conclusions:

I. R = H → False (as R ≤ A = C ≤ H; R ≤ H)

II. R < H → False (as R ≤ A = C ≤ H; R ≤ H)

Note:

conclusion I and II form a complimentary pair.

Hence, Either conclusion I or II is true.

Given

Statements:

O > U ≥ T ≤ G; R ≥ O > W

On combining: R ≥ O > U ≥ T ≤ G; R ≥ O > W

Conclusions:

I. R > G → False (as R ≥ O > U ≥ T ≤ G; as clear relation between R and G cannot be established)

II. W > U → False (as W < O > U; as clear relation between W and U cannot be established)

Hence, none of the conclusion is true.

**Given

Statements:

** P < E = N ≤ T; N ≤ S < U = L < A

On combining: P < E = N ≤ T; P < E = N ≤ S < U = L < A

Conclusions:

I. P < U → true (as P < E = N < U → P < U)

II. E ≤ S → true (as E = N ≤ S → E ≤ S)

Hence, Both the conclusions I and II are true.

The logic followed here is:

Option 1) QSU

Option 2) UWY

Option 3) CEG

Option 4) HJI

Here, 'HJI' is odd among the given options.

Hence, the correct answer is "Option 4".

Here, persons are N, O, P, Q, R, S and T.

1. Three persons went temple between T and N.

2. T went temple two days before O.

3. N went temple neither Friday nor Saturday.

4. As many persons went temple before P as many after Q.

5. Q went temple after R.

6. S went temple before R but not after P. Therefore, case 1 is eliminated.

Hence, the final arrangement is as follows

Since, R went temple on Thursday. Therefore, statement A is correct.

O went temple just after R. Therefore, statement B is correct.

As many persons went temple before R as many after him. Therefore, statement C is correct.

Hence, the incorrect statement is None of these.

Here, persons are N, O, P, Q, R, S and T.

1. Three persons went temple between T and N.

2. T went temple two days before O.

3. N went temple neither Friday nor Saturday.

4. As many persons went temple before P as many after Q.

5. Q went temple after R.

6. S went temple before R but not after P. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

Since, P went temple on Tuesday not on Wednesday. Therefore, statement first is incorrect.

Two persons went temple after O. Therefore, statement second is incorrect.

R went temple on Thursday not on Tuesday. Therefore, statement third is incorrect.

As many persons went temple before T as many after O not R. Therefore, statement fourth is incorrect.

Hence, the correct statement is None of these.

Here, persons are N, O, P, Q, R, S and T.

1. Three persons went temple between T and N.

2. T went temple two days before O.

3. N went temple neither Friday nor Saturday.

4. As many persons went temple before P as many after Q.

5. Q went temple after R.

6. S went temple before R but not after P. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

Hence, two persons went temple between P and O.

Here, persons are N, O, P, Q, R, S and T.

1. Three persons went temple between T and N.

2. T went temple two days before O.

3. N went temple neither Friday nor Saturday.

4. As many persons went temple before P as many after Q.

5. Q went temple after R.

6. S went temple before R but not after P. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

Hence, O went temple on Friday.

Here, persons are N, O, P, Q, R, S and T.

1. Three persons went temple between T and N.

2. T went temple two days before O.

3. N went temple neither Friday nor Saturday.

4. As many persons went temple before P as many after Q.

5. Q went temple after R.

6. S went temple before R but not after P. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

Since, S is the first person who went temple so no one went temple before him and N is the last person so no one went after him.

Hence, the correct answer is N.

1. D has fewer items than A and C, but more items than E and F.

A/C > C/A > D > E/F > F/E

2. Exactly two persons have more items than B.

_ > _ > B > _ > _ > _

3. Exactly one person has fewer items than E.

A/C > C/A > B > D > E > F

Either A or C has the highest number of items.

Hence, the correct answer is Can't be determined.