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Question 351

SBI Clerk 2025• Numerical Ability

The simple interest on a sum of money is 1/16th of the principal, and the number of years is equal to rate per annum. Find the rate percentage.

  1. AOption (a)

    10%

  2. BOption (b)

    15%

  3. COption (c)

    5%

  4. DOption (d)

    2.5%

  5. EOption (e)

    6%

View answer & explanation

Correct answer

Answer: (d)D.

2.5%

Why this answer is correct

Shortcut Trick

When Simple Interest is a fraction (1/n) of Principal and Time (T) equals Rate (R).

Formula: Rate (R) = √(Fraction × 100)

R = √(1/16 × 100) = √(100/16)

R = 10/4 = 2.5%

∴ The correct answer is 2.5%.

Alternate Method

Given:

Simple Interest (SI) = 1/16 × Principal (P)

Number of years (T) = Rate per annum (R)

Formula Used:

SI = (P × R × T) ÷ 100

Calculations:

⇒ P/16 = (P × R × R) ÷ 100

⇒ 1/16 = R2 ÷ 100

⇒ R2 = 100 ÷ 16

⇒ R = √(100/16)

⇒ R = 10/4

⇒ R = 2.5%

∴ The correct answer is 2.5%.

Additional Information

Simple Interest Formula

The basic formula is SI = (P × R × T) / 100, where P is Principal, R is Rate, and T is Time.

Case when R = T

If numerical values of Rate and Time are equal, then R = T = 10 × √(SI/P).

Amount Calculation

Total Amount (A) is the sum of Principal and Simple Interest: A = P + SI.

Question 352

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The bar graph below illustrates the number of mines (in hundreds) located in four different places: A, B, C, and D. 

If the number of mines in Place A increases by 20% and those in Place D decrease by 10%, what will be the ratio of mines in A to D?

  1. AOption (a)

    7:8

  2. BOption (b)

    8:9

  3. COption (c)

    3:4

  4. DOption (d)

    5:6

  5. EOption (e)

    2:3

View answer & explanation

Correct answer

Answer: (e)E.

2:3

Why this answer is correct

New mines in A = 150 + 20% of 150 = 150 + 30 = 180

New mines in D = 300 − 10% of 300 = 300 − 30 = 270

Ratio (A:D) = 180 : 270 = 2 : 3

Hence, the correct answer is 2 : 3.

Question 353

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The bar graph below illustrates the number of mines (in hundreds) located in four different places: A, B, C, and D. 

If the number of mines in Place C were to double, what would be the percentage of the new number of mines in Place C to the total number of mines in all four places?

  1. AOption (a)

    27.27%

  2. BOption (b)

    36.36%

  3. COption (c)

    66.67%

  4. DOption (d)

    53.53%

  5. EOption (e)

    44.44%

View answer & explanation

Correct answer

Answer: (b)B.

36.36%

Why this answer is correct

Original mines in C = 200

If doubled ⇒ New mines in C = 200 × 2 = 400

New total mines = 150 + 250 + 400 + 300 = 1100

Required percentage = (400 ÷ 1100) × 100 = 36.36%

Hence, the correct answer is 36.36%.

Question 354

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The bar graph below illustrates the number of mines (in hundreds) located in four different places: A, B, C, and D. 

What is the difference between the average number of mines in Place A and B, and the average number of mines in Place C and D?

  1. AOption (a)

    80

  2. BOption (b)

    75

  3. COption (c)

    50

  4. DOption (d)

    60

  5. EOption (e)

    45

View answer & explanation

Correct answer

Answer: (c)C.

50

Why this answer is correct

Average number of mines in Place A and B = (150 + 250) ÷ 2 = 400 ÷ 2 = 200

Average number of mines in Place C and D = (200 + 300) ÷ 2 = 500 ÷ 2 = 250

Difference = 250 − 200 = 50

Hence, the correct answer is 50.

Question 355

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The bar graph below illustrates the number of mines (in hundreds) located in four different places: A, B, C, and D. 

By what percentage is the number of mines in Place B more than the number of mines in Place A?

  1. AOption (a)

    12.5%

  2. BOption (b)

    14.28%

  3. COption (c)

    33.33%

  4. DOption (d)

    66.67%

  5. EOption (e)

    90.09%

View answer & explanation

Correct answer

Answer: (d)D.

66.67%

Why this answer is correct

Mines in Place A = 150

Mines in Place B = 250

Difference = 250 − 150 = 100

Percentage increase = (Difference ÷ Place A) × 100

= (100 ÷ 150) × 100 = 66.67%

Hence, the correct answer is 66.67%.

Question 356

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The bar graph below illustrates the number of mines (in hundreds) located in four different places: A, B, C, and D. 

What is the ratio of the total number of mines in Place A and Place C to the total number of mines in Place B and Place D?

  1. AOption (a)

    11:7

  2. BOption (b)

    7:11

  3. COption (c)

    3:5

  4. DOption (d)

    5:3

  5. EOption (e)

    5:7

View answer & explanation

Correct answer

Answer: (b)B.

7:11

Why this answer is correct

Mines in Place A = 15 hundreds = 150

Mines in Place C = 20 hundreds = 200

Total (A + C) = 150 + 200 = 350

Mines in Place B = 250

Mines in Place D = 300

Total (B + D) = 250 + 300 = 550

Ratio (A + C) : (B + D) = 350 : 550 → 7 : 11

Hence, the correct answer is 7 : 11.

Question 357

SBI Clerk 2025• Numerical Ability

The radius of the semicircle is equal to the half of the side of the square. The area of the square is 1764 sq cm. Find the perimeter of the semicircle?

  1. AOption (a)

     105cm

  2. BOption (b)

     112cm

  3. COption (c)

     108cm

  4. DOption (d)

     115cm

  5. EOption (e)

     120cm

View answer & explanation

Correct answer

Answer: (c)C.

 108cm

Why this answer is correct

Shortcut Trick

Side of Square = √1764 = 42 cm.

Radius of Semicircle (r) = 42 ÷ 2 = 21 cm.

Perimeter of Semicircle = r × (36 ÷ 7).

Perimeter = 21 × (36 ÷ 7) = 3 × 36 = 108 cm.

∴ The correct answer is 108 cm.

Alternate Method

Given: Area of Square = 1764 cm2; Radius = Side / 2.

Formula Used: Area of Square = a2; Perimeter of Semicircle = πr + 2r.

⇒ Side of Square (a) = √1764

⇒ a = 42 cm

⇒ Radius of Semicircle (r) = 42 ÷ 2 = 21 cm

⇒ Perimeter = (π × r) + (2 × r)

⇒ Perimeter = (22/7 × 21) + (2 × 21)

⇒ Perimeter = 66 + 42 = 108 cm

∴ The correct answer is 108 cm.

Additional Information

Area of Semicircle

The Area is half of the circle's area, given by (πr2) ÷ 2.

Diagonal of a Square

The Diagonal of a square with side 'a' is calculated as a√2.

Simplified Perimeter Constant

The Perimeter of a semicircle can be expressed as r × (36/7) when using π = 22/7.

Question 358

SBI Clerk 2025• Numerical Ability

A invested Rs. 76,000 in a business. After a few months, B joined him with Rs. 57,000. At the end of the year, the total profit was divided between them in the ratio 2 : 1, After how many months did B join?

  1. AOption (a)

    6

  2. BOption (b)

    4

  3. COption (c)

    3

  4. DOption (d)

    8

  5. EOption (e)

    5

View answer & explanation

Correct answer

Answer: (b)B.

4

Why this answer is correct

Shortcut Trick

Profit ratio = (CapitalA × TimeA) : (CapitalB × TimeB)

Ratio of Capitals A : B = 76,000 : 57,000 = 4 : 3

Let B joined for x months. A was there for 12 months.

(4 × 12) : (3 × x) = 2 : 1 ⇒ 48 : 3x = 2 : 1

3x × 2 = 48 × 1 ⇒ 6x = 48 ⇒ x = 8 months.

B joined after = 12 − 8 = 4 months.

∴ The correct answer is 4 months.

Alternate Method

Given → Investment of A = Rs. 76,000, Investment of B = Rs. 57,000, Profit Ratio = 2 : 1, Time for A = 12 months. Formulas: Profit = Investment × Time | Investment1 × T1 ÷ Investment2 × T2 = P1 ÷ P2

⇒ Let B invested for t months. ⇒ (76000 × 12) ÷ (57000 × t) = 2 ÷ 1 ⇒ (4 × 12) ÷ (3 × t) = 2 ÷ 1 ⇒ 48 ÷ 3t = 2 ÷ 1 ⇒ 16 ÷ t = 2 ⇒ t = 8 months. ⇒ Since the business ran for 12 months and B was in for 8 months, B joined after 12 − 8 = 4 months.

∴ The correct answer is 4 months.

Additional Information

Partnership Basics

In a partnership, the profit is distributed based on the weighted investment, which is the product of Capital and Time Period.

Time Calculation

Always distinguish between the duration of investment and the time after which a partner joins. Time joined after = Total time − Duration of investment.

Question 359

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The following data shows the number of male and female visitors to a shopping mall on Monday and Tuesday. 

On Monday, the total number of visitors was 390. The number of males on Tuesday was 35 more than the number of females on Monday. The number of females on Monday was 62.5% of the number of males on Monday.

If the number of males on Monday had been 20% less, what would have been the new total number of visitors on Monday?

  1. AOption (a)

    348

  2. BOption (b)

    349

  3. COption (c)

    346

  4. DOption (d)

    342

  5. EOption (e)

    344

View answer & explanation

Correct answer

Answer: (d)D.

342

Why this answer is correct

General Solution:

Given:

Total visitors on Monday = 390

Females on Monday = 62.5% of Males on Monday

Males on Tuesday = Females on Monday + 35

Let MMon = males on Monday, FMon = females on Monday.

Calculations:

FMon = 62.5% of MMon = (5/8)·MMon

MMon + FMon = 390 ⇒ MMon + (5/8)MMon = 390

⇒ (13/8)MMon = 390 ⇒ MMon = 390 × 8 / 13 = 240

⇒ FMon = 390 − 240 = 150

Males on Tuesday = FMon + 35 = 150 + 35 = 185

Thus,

Males on Monday = 240

Females on Monday = 150

Males on Tuesday = 185

Calculations:

Original males on Monday = 240

Reduced by 20% ⇒ New males = 240 − 0.2 × 240 = 240 − 48 = 192

Females remain the same = 150

New total visitors = 192 + 150 = 342

Hence, the correct answer is 342.

Question 360

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The following data shows the number of male and female visitors to a shopping mall on Monday and Tuesday. 

On Monday, the total number of visitors was 390. The number of males on Tuesday was 35 more than the number of females on Monday. The number of females on Monday was 62.5% of the number of males on Monday.

What is the ratio of the number of males on Monday to the number of males on Tuesday?

  1. AOption (a)

    44:31

  2. BOption (b)

    48:37

  3. COption (c)

    40:29

  4. DOption (d)

    27:22

  5. EOption (e)

    25:17

View answer & explanation

Correct answer

Answer: (b)B.

48:37

Why this answer is correct

General Solution:

Given:

Total visitors on Monday = 390

Females on Monday = 62.5% of Males on Monday

Males on Tuesday = Females on Monday + 35

Let MMon = males on Monday, FMon = females on Monday.

Calculations:

FMon = 62.5% of MMon = (5/8)·MMon

MMon + FMon = 390 ⇒ MMon + (5/8)MMon = 390

⇒ (13/8)MMon = 390 ⇒ MMon = 390 × 8 / 13 = 240

⇒ FMon = 390 − 240 = 150

Males on Tuesday = FMon + 35 = 150 + 35 = 185

Thus,

Males on Monday = 240

Females on Monday = 150

Males on Tuesday = 185

Calculations:

Males on Monday = 240

Males on Tuesday = 185

Ratio = Males(Monday) : Males(Tuesday) = 240 : 185 → 48 : 37

Hence, the correct answer is 48 : 37.

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