A bike man can reach a certain place in 45 hrs. If he reduced his speed by 3/5, he goes 54 km less in that time. What is his speed?
- AOption (a)
3 km/hr
- BOption (b)
2 km/hr
- COption (c)
4 km/hr
- DOption (d)
8 km/hr
- EOption (e)
None of these
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Correct answer
2 km/hr
Why this answer is correct
Shortcut Trick
When time is constant, the distance ratio is equal to the speed ratio.
Speed reduced by 3/5 → New Speed = 1 − 3/5 = 2/5 of Original Speed.
Ratio of Speeds (Original : New) = 5 : 2 ∴ Ratio of Distance = 5 : 2.
Difference in distance = 5 − 2 = 3 units → 54 km. So, 1 unit = 18 km.
Original Distance = 5 units × 18 = 90 km. Speed = 90 km ÷ 45 hrs = 2 km/hr.
∴ The correct answer is 2 km/hr.
Alternate Method
Given: Time (T) = 45 hrs, Speed reduction = 3/5, Distance reduction = 54 km.
Formula: Distance = Speed × Time
⇒ Let the original speed be 's' km/hr.
⇒ Reduced speed = s − (3/5)s = (2/5)s km/hr.
⇒ Original Distance (D1) = s × 45
⇒ New Distance (D2) = (2/5)s × 45 = 18s
⇒ Difference in distance (D1 − D2) = 45s − 18s = 54 km
⇒ 27s = 54
⇒ s = 54 ÷ 27 = 2 km/hr
∴ The correct answer is 2 km/hr.
Additional Information
Constant Time Property
When time is kept constant, the ratio of the speeds of two objects is directly proportional to the ratio of the distances covered by them (S1/S2 = D1/D2).
Average Speed
If a person covers a certain distance at speed x and the same distance at speed y, the average speed for the whole journey is (2xy)/(x + y).
Relative Speed
Speed of two bodies moving in the same direction is the difference of their speeds (u − v), and in the opposite direction is the sum of their speeds (u + v).