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Question 231

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

What is the average number of males in company A and C?

  1. AOption (a)

    24

  2. BOption (b)

    31

  3. COption (c)

    28

  4. DOption (d)

    35

  5. EOption (e)

    26

View answer & explanation

Correct answer

Answer: (c)C.

28

Why this answer is correct

General Solution:

Let

Males: A = x, B = y, C = z

Total males: x + y + z = 86

Given: y = 1.5 × x ⇒ y = 3x/2

z = y + 6 = 3x/2 + 6

Solve for x:

x + y + z = 86 ⇒ x + 3x/2 + (3x/2 + 6) = 86

x + 1.5x + 1.5x + 6 = 86

4x + 6 = 86 ⇒ 4x = 80 ⇒ x = 20

Then y = 1.5 × 20 = 30

z = 30 + 6 = 36

Females:

Let females in B = fB

Females in A = fA = 1.25 × fB

Females in C = fC = 20 = 0.8 × fA ⇒ fA = 25

Then fB = fA/1.25 = 25/1.25 = 20

Thus,

Males: A = 20, B = 30, C = 36

Females: A = 25, B = 20, C = 20

Calculations:

Males in A = 20, Males in C = 36

Average = (20 + 36) ÷ 2 = 56 ÷ 2 = 28

Hence, the correct answer is 28.

Question 232

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

If the number of females in company C were 10% more, what would be the new total number of females?

  1. AOption (a)

    82

  2. BOption (b)

    79

  3. COption (c)

    67

  4. DOption (d)

    55

  5. EOption (e)

    94

View answer & explanation

Correct answer

Answer: (c)C.

67

Why this answer is correct

General Solution:

Let

Males: A = x, B = y, C = z

Total males: x + y + z = 86

Given: y = 1.5 × x ⇒ y = 3x/2

z = y + 6 = 3x/2 + 6

Solve for x:

x + y + z = 86 ⇒ x + 3x/2 + (3x/2 + 6) = 86

x + 1.5x + 1.5x + 6 = 86

4x + 6 = 86 ⇒ 4x = 80 ⇒ x = 20

Then y = 1.5 × 20 = 30

z = 30 + 6 = 36

Females:

Let females in B = fB

Females in A = fA = 1.25 × fB

Females in C = fC = 20 = 0.8 × fA ⇒ fA = 25

Then fB = fA/1.25 = 25/1.25 = 20

Thus,

Males: A = 20, B = 30, C = 36

Females: A = 25, B = 20, C = 20

Calculations:

Original females:

A = 25

B = 20

C = 20

Increase females in C by 10%:

New females in C = 20 × 1.10 = 22

Total females now = 25 + 20 + 22 = 67

Hence, the correct answer is 67.

Question 233

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

What is the ratio of the number of males in company C to the number of females in company B?

  1. AOption (a)

    8:3

  2. BOption (b)

    9:5

  3. COption (c)

    4:1

  4. DOption (d)

    5:3

  5. EOption (e)

    6:5

View answer & explanation

Correct answer

Answer: (b)B.

9:5

Why this answer is correct

General Solution:

Let

Males: A = x, B = y, C = z

Total males: x + y + z = 86

Given: y = 1.5 × x ⇒ y = 3x/2

z = y + 6 = 3x/2 + 6

Solve for x:

x + y + z = 86 ⇒ x + 3x/2 + (3x/2 + 6) = 86

x + 1.5x + 1.5x + 6 = 86

4x + 6 = 86 ⇒ 4x = 80 ⇒ x = 20

Then y = 1.5 × 20 = 30

z = 30 + 6 = 36

Females:

Let females in B = fB

Females in A = fA = 1.25 × fB

Females in C = fC = 20 = 0.8 × fA ⇒ fA = 25

Then fB = fA/1.25 = 25/1.25 = 20

Thus,

Males: A = 20, B = 30, C = 36

Females: A = 25, B = 20, C = 20

Calculations:

From previous solution:

Males in C = 36

Females in B = 20

Ratio (Males in C : Females in B) = 36 : 20 = 9 : 5

Hence, the correct answer is 9 : 5.

Question 234

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

The number of females in company B is what percentage of the number of males in company A?

  1. AOption (a)

    25%

  2. BOption (b)

    50%

  3. COption (c)

    75%

  4. DOption (d)

    100%

  5. EOption (e)

    125%

View answer & explanation

Correct answer

Answer: (d)D.

100%

Why this answer is correct

Females with B = 20

Males with A = 20

Required percentage = (Females B ÷ Males A) × 100

= (20 ÷ 20) × 100 = 100%

Hence, the correct answer is 100%.

Question 235

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

What is the difference between the number of males and females in company C?

  1. AOption (a)

    14

  2. BOption (b)

    12

  3. COption (c)

    10

  4. DOption (d)

    16

  5. EOption (e)

    18

View answer & explanation

Correct answer

Answer: (d)D.

16

Why this answer is correct

General Solution:

Let

Males: A = x, B = y, C = z

Total males: x + y + z = 86

Given: y = 1.5 × x ⇒ y = 3x/2

z = y + 6 = 3x/2 + 6

Solve for x:

x + y + z = 86 ⇒ x + 3x/2 + (3x/2 + 6) = 86

x + 1.5x + 1.5x + 6 = 86

4x + 6 = 86 ⇒ 4x = 80 ⇒ x = 20

Then y = 1.5 × 20 = 30

z = 30 + 6 = 36

Females:

Let females in B = fB

Females in A = fA = 1.25 × fB

Females in C = fC = 20 = 0.8 × fA ⇒ fA = 25

Then fB = fA/1.25 = 25/1.25 = 20

Thus,

Males: A = 20, B = 30, C = 36

Females: A = 25, B = 20, C = 20

Calculations:

From general solution, Person C has:

Males = 36

Females = 20

Difference = Males − Females = 36 − 20 = 16

Hence, the correct answer is 16.

Question 236

SBI Clerk 2025• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

What is the total number of females with companies A and B combined?

  1. AOption (a)

    48

  2. BOption (b)

    39

  3. COption (c)

    46

  4. DOption (d)

    55

  5. EOption (e)

    45

View answer & explanation

Correct answer

Answer: (e)E.

45

Why this answer is correct

General Solution:

Let

Males: A = x, B = y, C = z

Total males: x + y + z = 86

Given: y = 1.5 × x ⇒ y = 3x/2

z = y + 6 = 3x/2 + 6

Solve for x:

x + y + z = 86 ⇒ x + 3x/2 + (3x/2 + 6) = 86

x + 1.5x + 1.5x + 6 = 86

4x + 6 = 86 ⇒ 4x = 80 ⇒ x = 20

Then y = 1.5 × 20 = 30

z = 30 + 6 = 36

Females:

Let females in B = fB

Females in A = fA = 1.25 × fB

Females in C = fC = 20 = 0.8 × fA ⇒ fA = 25

Then fB = fA/1.25 = 25/1.25 = 20

Thus,

Males: A = 20, B = 30, C = 36

Females: A = 25, B = 20, C = 20

Calculations:

Females with A = 25, Females with B = 20

Total females with A and B = 25 + 20 = 45

Hence, the correct answer is 45.

Question 237

SBI Clerk 2025• Numerical Ability

A borrowed sum was paid in two instalments of Rs.121 each. If the rate of compound interest is 10% per annum , what sum was borrowed?

  1. AOption (a)

    220

  2. BOption (b)

    210

  3. COption (c)

    200

  4. DOption (d)

    240

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

210

Why this answer is correct

Shortcut Trick

Rate = 10% = 1/10. For Compound Interest instalments, ratio of Principal to Amount for 1st year is 10 : 11 and for 2nd year is 102 : 112 = 100 : 121.

To make instalments equal, multiply 1st year ratio by 11: (10 × 11) : (11 × 11) = 110 : 121.

Total Principal = 110 + 100 = 210 units. Given instalment (121 units) = ₹121.

∴ 1 unit = ₹1. Total sum = 210 × 1 = ₹210.

∴ The correct answer is ₹210.

Alternate Method

Given: Instalment (I) = ₹121, Rate (r) = 10%, n = 2 years.

Formula Used: Principal (P) = [I / (1 + r/100)1] + [I / (1 + r/100)2]

⇒ P = [121 / (1 + 10/100)] + [121 / (1 + 10/100)2]

⇒ P = [121 / (1.1)] + [121 / (1.1)2]

⇒ P = [121 / 1.1] + [121 / 1.21]

⇒ P = 110 + 100

⇒ P = ₹210

∴ The correct answer is ₹210.

Additional Information

CI Instalment Formula

The total principal P for n instalments of value I is P = I × [((1+R)n − 1) / (R(1+R)n)], where R is the decimal rate.

Present Value Method

Total sum borrowed is the sum of the present values of each instalment: P = PV1 + PV2 + ... + PVn.

SI vs CI Instalment

In Simple Interest, instalments are calculated on a linear basis, whereas in Compound Interest, each instalment reduces the principal exponentially.

Question 238

SBI Clerk 2025• Numerical Ability

The circle and rectangle have the same area. The length and breadth of the rectangle are 44 cm and 56 cm respectively, then what is the area of the circle?

  1. AOption (a)

    2464 cm2

  2. BOption (b)

    2500 cm2

  3. COption (c)

    2564 cm2

  4. DOption (d)

    2600 cm2

  5. EOption (e)

    2574 cm2

View answer & explanation

Correct answer

Answer: (a)A.

2464 cm2

Why this answer is correct

Shortcut Trick

Since Area of Circle = Area of Rectangle, simply multiply the dimensions of the rectangle.

Area = Length × Breadth = 44 × 56.

Calculation: 44 × 56 = 2464 cm2.

∴ The correct answer is 2464 cm2.

Alternate Method

Given:

Length of rectangle (L) = 44 cm

Breadth of rectangle (B) = 56 cm

Formula Used:

Area of Rectangle = Length × Breadth

Calculations:

⇒ Area of rectangle = 44 × 56

⇒ Area of rectangle = 2464 cm2

⇒ According to the question, Area of Circle = Area of Rectangle

⇒ Area of Circle = 2464 cm2

∴ The correct answer is 2464 cm2.

Additional Information

Area of Circle

The area of a circle is calculated using the formula A = πr2, where r is the radius.

Perimeter of Rectangle

The perimeter of a rectangle is the total distance around the outside, calculated as P = 2 × (Length + Breadth).

Circumference of Circle

The boundary of a circle is called the circumference, given by the formula C = 2πr or πd.

Question 239

SBI Clerk 2025• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

410 × ? × 26 = 67250 + 50010

  1. AOption (a)

    11

  2. BOption (b)

    14

  3. COption (c)

    16

  4. DOption (d)

    22

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

11

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below,

Step - 1 - Parts of an equation enclosed in the ‘BRACKETS’ must be solved first

Step - 2 - Any mathematical ‘OF’ or ‘EXPONENTS’ must be solved next

Step - 3 - Next the part of the equation that contains ‘DIVISION; and ‘MULTIPLICATION’ are calculated

Step - 4 - Last but not least, the parts of the equation that contains ‘ADDITION’ and ‘SUBTRACTION’ should be calculated

Now, the given expression:

⇒ 410 × ? × 26 = 67250 + 50010

⇒ 10660 × ? = 117260

⇒ ?;=;11726010660;=;11?; = ;\frac{{117260}}{{10660}}; = ;11

Question 240

SBI Clerk 2025• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

207 ÷ 3 × 2.25 + 43.5 – 9 = ?

  1. AOption (a)

    136.45

  2. BOption (b)

    123.85

  3. COption (c)

    142.95

  4. DOption (d)

    189.75

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

189.75

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below,

Step - 1 - Parts of an equation enclosed in the ‘BRACKETS’ must be solved first

Step - 2 - Any mathematical ‘OF’ or ‘EXPONENTS’ must be solved next

Step - 3 - Next the part of the equation that contains ‘DIVISION; and ‘MULTIPLICATION’ are calculated

Step - 4 - Last but not least, the parts of the equation that contains ‘ADDITION’ and ‘SUBTRACTION’ should be calculated

Now, the given expression:

⇒ 207 ÷ 3 × 2.25 + 43.5 – 9 = ?

⇒ 69 × 2.25 + 43.5 – 9 = ?

⇒ 155.25 + 43.5 – 9 = ?

⇒ 198.75 – 9 = ?

⇒ 189.75 = ?

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