Search Previous Year Questions

Here, persons are B, F, H, K, O, R, V and X.

1. At least three persons purchased gift between K and X.

2. K purchased gift before X and neither of them is the first or last person.

3. Three persons purchased gift between V and F.

4. Only two persons purchased gift between V and O who purchased gift after V.

5. O purchased a gift two persons before H.

6. H purchased gift before B.

7. R does not purchase a gift adjacent to X and V. Therefore, cases 1, 2(b) and 3 are eliminated. Hence, the final arrangement is as follows

Since, B is the last person who purchased a gift. Therefore, statement first is correct.

H purchased a gift just before X. Therefore, statement second is correct.

K purchased a gift just after V. Therefore, statement third is correct.

Only two persons purchased gift after H. Therefore, statement fourth is incorrect.

Hence, the incorrect statement is More than three persons purchased gift after H.

Here, persons are B, F, H, K, O, R, V and X.

1. At least three persons purchased gift between K and X.

2. K purchased gift before X and neither of them is the first or last person.

3. Three persons purchased gift between V and F.

4. Only two persons purchased gift between V and O who purchased gift after V.

5. O purchased a gift two persons before H.

6. H purchased gift before B.

7. R does not purchase a gift adjacent to X and V. Therefore, cases 1, 2(b) and 3 are eliminated. Hence, the final arrangement is as follows

Since, three persons purchased gift before O and three persons purchased gift after F.

Hence, the correct answer is F.

Here, persons are B, F, H, K, O, R, V and X.

1. At least three persons purchased gift between K and X.

2. K purchased gift before X and neither of them is the first or last person.

3. Three persons purchased gift between V and F.

4. Only two persons purchased gift between V and O who purchased gift after V.

5. O purchased a gift two persons before H.

6. H purchased gift before B.

7. R does not purchase a gift adjacent to X and V. Therefore, cases 1, 2(b) and 3 are eliminated. Hence, the final arrangement is as follows

Since, two persons purchased gift before R and same number of persons purchased gift after H. Therefore, statement A is correct.

O purchased gift just after R. Therefore, statement B is correct.

F purchased gift after R not before R. Therefore, statement C is incorrect.

Hence, the correct statement is both A and B.

the pattern of code is as follows,

Similarly, the word PAUSED can be coded as,

Hence, the word PAUSED would be coded as UCFRYW.

1. Y’s visit takes place immediately before X’s visit, and X’s visit is on 7^th March. 

​2. Exactly three people have their visits between X’s visit and V’s visit. 

3. T’s visit is in a month that has 31 days.  4. There are more than two people whose visits fall between T’s visit and S’s visit.

Here, we have 4 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

5. U’s visit is scheduled immediately after W’s visit. 

Now, we can eliminate Case 3, but we have a new subcase of Case 1.

6. Z’s visit is scheduled after S’s visit. 

Now, we can eliminate Case 1a and Case 2.

7. Not more than two people visit between T and Z.

Now, we can eliminate Case 1.

This is our final arrangement,

Hence, the correct answer is The one whose visit is on 7^th March.

1. Y’s visit takes place immediately before X’s visit, and X’s visit is on 7^th March. 

​2. Exactly three people have their visits between X’s visit and V’s visit. 

3. T’s visit is in a month that has 31 days.  4. There are more than two people whose visits fall between T’s visit and S’s visit.

Here, we have 4 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

5. U’s visit is scheduled immediately after W’s visit. 

Now, we can eliminate Case 3, but we have a new subcase of Case 1.

6. Z’s visit is scheduled after S’s visit. 

Now, we can eliminate Case 1a and Case 2.

7. Not more than two people visit between T and Z.

Now, we can eliminate Case 1.

This is our final arrangement,

Hence, the correct answer is 20^th September.

1. Y’s visit takes place immediately before X’s visit, and X’s visit is on 7^th March. 

​2. Exactly three people have their visits between X’s visit and V’s visit. 

3. T’s visit is in a month that has 31 days.  4. There are more than two people whose visits fall between T’s visit and S’s visit.

Here, we have 4 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

5. U’s visit is scheduled immediately after W’s visit. 

Now, we can eliminate Case 3, but we have a new subcase of Case 1.

6. Z’s visit is scheduled after S’s visit. 

Now, we can eliminate Case 1a and Case 2.

7. Not more than two people visit between T and Z.

Now, we can eliminate Case 1.

This is our final arrangement,

Hence, the correct answer is Three.

1. Y’s visit takes place immediately before X’s visit, and X’s visit is on 7^th March. 

​2. Exactly three people have their visits between X’s visit and V’s visit. 

3. T’s visit is in a month that has 31 days.  4. There are more than two people whose visits fall between T’s visit and S’s visit.

Here, we have 4 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

5. U’s visit is scheduled immediately after W’s visit. 

Now, we can eliminate Case 3, but we have a new subcase of Case 1.

6. Z’s visit is scheduled after S’s visit. 

Now, we can eliminate Case 1a and Case 2.

7. Not more than two people visit between T and Z.

Now, we can eliminate Case 1.

This is our final arrangement,

Except for the Z who visited in the month which have 30 ays, all others visit in month having 31 days.

Hence, the correct answer is Z.

1. Y’s visit takes place immediately before X’s visit, and X’s visit is on 7^th March. 

​2. Exactly three people have their visits between X’s visit and V’s visit. 

3. T’s visit is in a month that has 31 days.  4. There are more than two people whose visits fall between T’s visit and S’s visit.

Here, we have 4 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

5. U’s visit is scheduled immediately after W’s visit. 

Now, we can eliminate Case 3, but we have a new subcase of Case 1.

6. Z’s visit is scheduled after S’s visit. 

Now, we can eliminate Case 1a and Case 2.

7. Not more than two people visit between T and Z.

Now, we can eliminate Case 1.

This is our final arrangement,

Hence, the correct answer is Five.

The least possible Venn diagram for the given statements is as follows,

Conclusions:

I. No pen is eraser → False (it is possible but not definite.)

II. Some erasers are pencil → False (as no pencil is eraser which also  means no eraser is pencil.)

III. All pen being pencils is a possibility → False (not possible as only few pens are pencils which means some pens are pencils and some pen are not pencils.)

Thus, none of the conclusions follows.