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Question 151

SBI Clerk 2025• Numerical Ability

What should come in place of question mark (?) in the following question?

5350 - 50 × 3139 ÷ 73 = ? × 64

  1. AOption (a)

    3560

  2. BOption (b)

    50

  3. COption (c)

    150

  4. DOption (d)

    3600

  5. EOption (e)

    75

View answer & explanation

Correct answer

Answer: (b)B.

50

Why this answer is correct

Suppose x will come in place of question mark;

5350 – 50 × 3139 ÷ 73 = x × 64

Applying BODMAS Rule;

⇒ 5350 – 50 × 43 = 64x

⇒ 5350 – 2150 = 64x

⇒ 3200 = 64x

⇒ x = 50

Question 152

SBI Clerk 2025• Numerical Ability

What will come in place of question (?) in the following question?

(224 ÷ 16 × 33) ÷ 21 = 2 × (? + 3)

  1. AOption (a)

    5

  2. BOption (b)

    10

  3. COption (c)

    11

  4. DOption (d)

    7

  5. EOption (e)

    8

View answer & explanation

Correct answer

Answer: (e)E.

8

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1 - steps of an equation enclosed in ‘Brackets’ must be solved first.

Step - 2 - any mathematical ‘Of’ or ‘Exponent’ must be solved next.

Step - 3 - Next, the parts of the equation that contain ‘Division’ and ‘Multiplication’ are calculated.

Step - 4 - Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.

Now, the given expression:

⇒ (224 ÷ 16 × 33) ÷ 21 = 2 × (? + 3)

⇒ (14 × 33) ÷ 21 = 2 × (? + 3)

⇒ 462 ÷ 21 = 2 × ? + 6

⇒ 22 = 2 × ? + 6

⇒ 2 × ? = 22 - 6

⇒ 2 × ? = 16

⇒ ? = 8

Question 153

SBI Clerk 2025• Numerical Ability

If the compound interest on a certain sum of money for 2 years at 2% per annum  is Rs 323.2. Find the sum.

  1. AOption (a)

    Rs. 8,000

  2. BOption (b)

    Rs. 7,000

  3. COption (c)

    Rs. 4,000

  4. DOption (d)

    Rs. 5,500

  5. EOption (e)

    Rs. 6,500

View answer & explanation

Correct answer

Answer: (a)A.

Rs. 8,000

Why this answer is correct

Shortcut Trick

Effective Rate of Interest for 2 years at 2% = r + r + (r × r)/100 = 2 + 2 + (2 × 2)/100 = 4.04%.

Given Compound Interest (CI) = ₹323.2.

Equating percentage to value: 4.04% of Principal = ₹323.2.

Principal = 323.2 ÷ 0.0404 = ₹8,000.

∴ The correct answer is ₹8,000.

Alternate Method

Given:

Time (T) = 2 years

Rate (R) = 2% per annum

Compound Interest (CI) = ₹323.2

Formula Used:

CI = P[(1 + R/100)T − 1]

Calculations:

⇒ 323.2 = P[(1 + 2/100)2 − 1]

⇒ 323.2 = P[(1.02)2 − 1]

⇒ 323.2 = P[1.0404 − 1]

⇒ 323.2 = P × 0.0404

⇒ P = 323.2 ÷ 0.0404

⇒ P = 3232000 ÷ 404

⇒ P = ₹8,000

∴ The correct answer is ₹8,000.

Additional Information

Effective Interest Rate

For 2 years, the net effective rate for CI is given by x + y + (xy/100). For 2%, it is 2 + 2 + 0.04 = 4.04%.

Difference between CI and SI

The difference for 2 years is P(R/100)2. Here, the difference would be ₹8000 × (0.0004) = ₹3.2.

Amount Formula

Total Amount (A) = Principal (P) + Compound Interest (CI). Also, A = P(1 + R/100)T.

Question 154

SBI Clerk 2025• Numerical Ability

Two alcohol-water mixtures of ratios 7 ∶ 3 and 3 ∶ 5 are mixed together in the ratio 3 ∶ 4 respectively to form a new mixture. How much alcohol is present in 70 litres of the new mixture?

  1. AOption (a)

    24 litres

  2. BOption (b)

    30 litres

  3. COption (c)

    36 litres

  4. DOption (d)

    42 litres

  5. EOption (e)

    48 litres

View answer & explanation

Correct answer

Answer: (c)C.

36 litres

Why this answer is correct

Shortcut Trick

Proportion of alcohol in Mixture 1 = 7/10 and Mixture 2 = 3/8.

Mixed in ratio 3 : 4 → Total parts = 3 + 4 = 7 units.

Total alcohol in 7 units = [3 × (7/10)] + [4 × (3/8)] = 2.1 + 1.5 = 3.6 units.

Alcohol fraction in final mix = 3.6 / 7.

Alcohol in 70 litres = (3.6 / 7) × 70 = 36 litres.

∴ The correct answer is 36 litres.

Alternate Method

Given: Ratio in Mix 1 = 7 : 3, Ratio in Mix 2 = 3 : 5, Mixing ratio = 3 : 4, Total quantity = 70 litres.

Formula: Total Alcohol = Σ(Quantity × Alcohol Fraction)

⇒ Quantity of Mix 1 = [3 / (3 + 4)] × 70 = 30 litres.

⇒ Quantity of Mix 2 = [4 / (3 + 4)] × 70 = 40 litres.

⇒ Alcohol from Mix 1 = 30 × (7 / (7 + 3)) = 30 × (7/10) = 21 litres.

⇒ Alcohol from Mix 2 = 40 × (3 / (3 + 5)) = 40 × (3/8) = 15 litres.

⇒ Total Alcohol = 21 + 15 = 36 litres.

∴ The correct answer is 36 litres.

Additional Information

Alligation Method

Used to find the ratio in which two ingredients at given prices/concentrations must be mixed to produce a mixture of a desired price/concentration.

Fractional Mixing

When mixing two ratios A:B and C:D in ratio m:n, ensure the sum of parts (A+B and C+D) are made equal or scaled to m and n respectively before adding.

Question 155

SBI Clerk 2025• Numerical Ability

The given table shows the number of cakes sold in three shops [A, B, and C] in four days [ Sunday, Monday, Tuesday, and Wednesday].  

DayCakes sold in shop ACakes sold in shop BCakes sold in shop C
Sunday845564
Monday483232
Tuesday565048
Wednesday706548

Find the difference between total cakes sold On Sunday in all shops together and total cakes sold in Monday in all shops together?

  1. AOption (a)

    68

  2. BOption (b)

    91

  3. COption (c)

    9

  4. DOption (d)

    147

  5. EOption (e)

    66

View answer & explanation

Correct answer

Answer: (b)B.

91

Why this answer is correct

Calculation

Sunday total = 84 + 55 + 64 = 203

Monday total = 48 + 32 + 32 = 112

Difference = 203 – 112 = 91

Question 156

SBI Clerk 2025• Numerical Ability

The given table shows the number of cakes sold in three shops [A, B, and C] in four days [ Sunday, Monday, Tuesday, and Wednesday].  

DayCakes sold in shop ACakes sold in shop BCakes sold in shop C
Sunday845564
Monday483232
Tuesday565048
Wednesday706548

Average number of cakes sold on Tuesday in shop B, C and D is 42. Find the difference between number of cakes sold in shop A and D on Tuesday?

  1. AOption (a)

    44

  2. BOption (b)

    28

  3. COption (c)

    22

  4. DOption (d)

    26

  5. EOption (e)

    32

View answer & explanation

Correct answer

Answer: (b)B.

28

Why this answer is correct

Calculation

Given: Average (B + C + D)/3 = 42

→ B + C + D = 42 × 3 = 126

B + C = 50 + 48 = 98 → D = 126 – 98 = 28

Shop A on Tuesday = 56

Difference = 56 – 28 = 28 cakes

Question 157

SBI Clerk 2025• Numerical Ability

The given table shows the number of cakes sold in three shops [A, B, and C] in four days [ Sunday, Monday, Tuesday, and Wednesday].  

DayCakes sold in shop ACakes sold in shop BCakes sold in shop C
Sunday845564
Monday483232
Tuesday565048
Wednesday706548

Ratio of number of cakes sold on Wednesday and Thursday in shop C is 4:5. Number of cakes sold on Thursday in shop B is 19 more than the cakes sold in Thursday in shop C. Find the number of cakes sold in shop B on Thursday?

  1. AOption (a)

    39

  2. BOption (b)

    79

  3. COption (c)

    66

  4. DOption (d)

    54

  5. EOption (e)

    68

View answer & explanation

Correct answer

Answer: (b)B.

79

Why this answer is correct

Calculation

Given: Shop C on Wednesday = 48

Ratio C (Wed) : C (Thu) = 4 : 5

→ C (Thu) = (48 × 5)/4 = 60

Shop B (Thu) = C (Thu) + 19 = 60 + 19 = 79 cakes

Question 158

SBI Clerk 2025• Numerical Ability

The given table shows the number of cakes sold in three shops [A, B, and C] in four days [ Sunday, Monday, Tuesday, and Wednesday].  

DayCakes sold in shop ACakes sold in shop BCakes sold in shop C
Sunday845564
Monday483232
Tuesday565048
Wednesday706548

Find the ratio of number of cakes sold in shop A on Tuesday and Wednesday together and Number of cakes sold in shop C on Wednesday?

  1. AOption (a)

    19:17

  2. BOption (b)

    21:8

  3. COption (c)

    3:2

  4. DOption (d)

    4:5

  5. EOption (e)

    6:5

View answer & explanation

Correct answer

Answer: (b)B.

21:8

Why this answer is correct

Calculation

Shop A (Tue + Wed) = 56 + 70 = 126

Shop C Wed = 48

Ratio = 126 : 48

→ 21 : 8

Question 159

SBI Clerk 2025• Numerical Ability

The given table shows the number of cakes sold in three shops [A, B, and C] in four days [ Sunday, Monday, Tuesday, and Wednesday].  

DayCakes sold in shop ACakes sold in shop BCakes sold in shop C
Sunday845564
Monday483232
Tuesday565048
Wednesday706548

Number of cakes sold in shop C on Monday is what percent more or less than the number of cakes sold in same shop on Wednesday?

  1. AOption (a)

    19%

  2. BOption (b)

    33.33%

  3. COption (c)

    25%

  4. DOption (d)

    37.5%

  5. EOption (e)

    20%

View answer & explanation

Correct answer

Answer: (b)B.

33.33%

Why this answer is correct

Calculation

Shop C Monday = 32, Wednesday = 48

Difference = 48 – 32 = 16

Percentage less = (16 ÷ 48) × 100 = 33.33%

Question 160

SBI Clerk 2025• Numerical Ability

A person covers two- third of distance by bus at 60 km/hr and remaining distance by bicycle at 30 km/hr. He takes 3 hours to cover the total distance. What is the distance covered by bicycle?

  1. AOption (a)

    135 km

  2. BOption (b)

    45 km

  3. COption (c)

    4.5 km

  4. DOption (d)

    13.5 km

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

45 km

Why this answer is correct

Shortcut Trick

Let the total distance be 3x km. Bus distance = 2x, Bicycle distance = x.

Total time = (Distance1 ÷ Speed1) + (Distance2 ÷ Speed2)

⇒ 3 = (2x ÷ 60) + (x ÷ 30) ⇒ 3 = (x ÷ 30) + (x ÷ 30) ⇒ 3 = 2x ÷ 30

⇒ x = (3 × 30) ÷ 2 = 45 km.

∴ The correct answer is 45 km.

Alternate Method

Given: Bus Speed = 60 km/hr, Bicycle Speed = 30 km/hr, Total Time = 3 hours.

Formula: Time = Distance ÷ Speed

Let total distance be D.

⇒ Time taken by bus = (2D/3) ÷ 60 = 2D ÷ 180 = D ÷ 90

⇒ Time taken by bicycle = (D/3) ÷ 30 = D ÷ 90

⇒ Total Time = (D ÷ 90) + (D ÷ 90) = 3

⇒ 2D ÷ 90 = 3

⇒ D = (3 × 90) ÷ 2 = 135 km

⇒ Distance by bicycle = (1/3) × 135

∴ The correct answer is 45 km.

Additional Information

Average Speed Formula

When a distance is divided into parts, Average Speed = Total Distance ÷ Total Time.

Time, Speed, Distance Relationship

For a constant distance, speed is inversely proportional to time (S1/S2 = T2/T1).

Unit Conversion

To convert km/hr to m/s, multiply by 5/18. To convert m/s to km/hr, multiply by 18/5.