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Question 921

RRB NTPC 2026• Mathematics• Mathematics

Riya, Kabir, and Sana start a business together. Riya invests ₹13500 for 8 months, Kabir invests ₹21000 for 6 months, and Sana invests ₹18000 for 12 months. At the end of the year, they earn a total profit of ₹12,600. What is Kabir's share of the profit (in ₹)?

  1. AOption (a)

    ₹3,528

  2. BOption (b)

    ₹4,030

  3. COption (c)

    ₹3,722

  4. DOption (d)

    ₹4,285

View answer & explanation

Correct answer

Answer: (a)A.

₹3,528

Why this answer is correct

Shortcut Trick

Ratio of Profit = (Investment × Time)

Riya : Kabir : Sana = (13500 × 8) : (21000 × 6) : (18000 × 12)

Riya : Kabir : Sana = 108 : 126 : 216 = 6 : 7 : 12

Total units = 6 + 7 + 12 = 25 units → ₹12,600

Kabir's share (7 units) = (12600 ÷ 25) × 7 = 504 × 7 = ₹3,528

∴ The correct answer is ₹3,528.

Alternate Method

Given:

Riya's investment (CR) = ₹13,500, Time (TR) = 8 months

Kabir's investment (CK) = ₹21,000, Time (TK) = 6 months

Sana's investment (CS) = ₹18,000, Time (TS) = 12 months

Total Profit = ₹12,600

Formula Used: Profit Ratio = (C1 × T1) : (C2 × T2) : (C3 × T3)

Calculations:

⇒ Riya's Profit Share : Kabir's Profit Share : Sana's Profit Share

⇒ (13500 × 8) : (21000 × 6) : (18000 × 12)

⇒ 108000 : 126000 : 216000

⇒ 108 : 126 : 216

⇒ 6 : 7 : 12 (Dividing by 18)

⇒ Total Ratio = 6 + 7 + 12 = 25 units

⇒ 25 units = ₹12,600

⇒ 1 unit = 12600 ÷ 25 = ₹504

⇒ Kabir's share = 7 units = 7 × 504 = ₹3,528

∴ The correct answer is ₹3,528.

Additional Information

Partnership Profit Sharing Rule

Profit is distributed in the ratio of the product of Capital and Time. P1 : P2 = (C1 × T1) : (C2 × T2).

Active vs Sleeping Partner

An Active partner manages the business and may receive a salary or extra profit %, while a Sleeping partner only provides capital.

Variable Time Investment

If a partner changes investment mid-way, calculate total investment as: (C1 × T1) + (C2 × T2) for that partner.

Question 922

RRB NTPC 2026• Mathematics• Mathematics

A vendor uses a 50 g stone in place of a 60 g weight while selling salt. If he sells the salt at the cost price per kilogram, what is his profit percentage on the transaction?

  1. AOption (a)

    15%

  2. BOption (b)

    16.67%

  3. COption (c)

    20%

  4. DOption (d)

    18%

View answer & explanation

Correct answer

Answer: (c)C.

20%

Why this answer is correct

Shortcut Trick

For a dishonest vendor selling at Cost Price (CP):

Profit % = (Error in weight ÷ Actual weight given) × 100

Error = 60 g − 50 g = 10 g

Profit % = (10 ÷ 50) × 100 = 20%

∴ The correct answer is 20%.

Alternate Method

Given:

Stated Weight (what the customer pays for) = 60 g

Actual Weight (what the vendor gives) = 50 g

Formula Used:

Profit % = [(Stated Weight − Actual Weight) ÷ Actual Weight] × 100

Let the Cost Price of 1 g of salt be ₹1.

⇒ Total Cost Price (CP) of salt actually given (50 g) = ₹50

⇒ Total Selling Price (SP) (Price of 60 g at CP) = ₹60

⇒ Profit earned = SP − CP = ₹60 − ₹50 = ₹10

⇒ Profit Percentage = (Profit ÷ CP) × 100

⇒ Profit % = (10 ÷ 50) × 100

⇒ Profit % = 20%

∴ The correct answer is 20%.

Additional Information

Dishonest Dealer Weight Gain

Profit % = [Gain ÷ (True Weight − Gain)] × 100. This applies when the dealer sells at CP but uses a faulty less weight.

Cheating While Buying and Selling

If a dealer cheats x% in weight while buying and y% while selling, Net Profit % = [((100 + x)(100 + y) ÷ 100) − 100].

Markup and Weight Cheating

If a dealer marks up price by P% and uses a weight of W1 instead of W2, then Net Profit % = [((100 + P) × W2) ÷ (100 × W1) − 1] × 100.

Question 923

RRB NTPC 2026• Mathematics• Mathematics

Which single digit should replace the blank in the number 1_36 so that the number is divisible by 9?

  1. AOption (a)

    3

  2. BOption (b)

    5

  3. COption (c)

    8

  4. DOption (d)

    1

View answer & explanation

Correct answer

Answer: (c)C.

8

Why this answer is correct

Shortcut Trick

For a number to be divisible by 9, the sum of its digits must be divisible by 9.

Sum of existing digits in 1_36 = 1 + 3 + 6 = 10.

The next multiple of 9 greater than 10 is 18.

Required digit = 18 − 10 = 8.

∴ The correct answer is 8.

Alternate Method

Given: Number = 1x36 (where x is the missing digit), Divisor = 9.

Formula Used: Divisibility Rule of 9 → Sum of digits ÷ 9 = Integer.

Calculations:

⇒ Sum of digits = 1 + x + 3 + 6

⇒ Sum = 10 + x

⇒ For the number to be divisible by 9, (10 + x) must be a multiple of 9 (9, 18, 27...).

⇒ Since x is a single digit (0−9), 10 + x = 18 is the only valid case.

⇒ x = 18 − 10

⇒ x = 8

∴ The correct answer is 8.

Additional Information

Divisibility by 3

Similar to the rule for 9, a number is divisible by 3 if the sum of its digits is a multiple of 3.

Divisibility by 11

A number is divisible by 11 if the difference between the sum of digits at odd positions and the sum of digits at even positions is either 0 or a multiple of 11.

Divisibility by 8

A number is divisible by 8 if the last three digits of the number are divisible by 8.

Question 924

RRB NTPC 2026• Mathematics• Mathematics

A car travels a distance of 540 km. For the first 3 hours, it travels at a speed of 80 km/h, and for the remaining hours, it reduces its speed to 60 km/h. Find the total time taken by the car to cover the entire distance.

  1. AOption (a)

    2 hours

  2. BOption (b)

    8 hours

  3. COption (c)

    4 hours

  4. DOption (d)

    6 hours

View answer & explanation

Correct answer

Answer: (b)B.

8 hours

Why this answer is correct

Shortcut Trick

Distance covered in first 3 hr = 80 × 3 = 240 km.

Remaining distance = 540 − 240 = 300 km.

Remaining time = 300 ÷ 60 = 5 hr.

Total time taken = 3 + 5 = 8 hr.

∴ The correct answer is 8 hr.

Alternate Method

Given:

Total distance = 540 km

Initial speed (s1) = 80 km/h | Initial time (t1) = 3 hr

Reduced speed (s2) = 60 km/h

Formula Used:

Distance = Speed × Time | Time = Distance ÷ Speed

Calculations:

⇒ Distance covered in first part = 80 km/h × 3 hr = 240 km

⇒ Remaining distance = Total distance − Distance covered in Part 1

⇒ Remaining distance = 540 − 240 = 300 km

⇒ Time taken for remaining distance = 300 km ÷ 60 km/h = 5 hr

⇒ Total time = Initial time + Remaining time

⇒ Total time = 3 hr + 5 hr = 8 hr

∴ The correct answer is 8 hr.

Additional Information

Average Speed

Average Speed = Total Distance ÷ Total Time. In this case, Average Speed = 540 ÷ 8 = 67.5 km/h.

Unit Conversion

To convert Speed from km/h to m/s, multiply by 5/18. To convert m/s to km/h, multiply by 18/5.

Relation between S, T, and D

Speed is inversely proportional to Time (S ∝ 1/T) when Distance is constant, and Speed is directly proportional to Distance (S ∝ D) when Time is constant.

Question 925

RRB NTPC 2026• Mathematics• Mathematics

A shopkeeper fixes the marked price of an item 165% above its cost price. What percentage of discount on marked price should be allowed to gain 112%?

  1. AOption (a)

    21%

  2. BOption (b)

    19%

  3. COption (c)

    20%

  4. DOption (d)

    23%

View answer & explanation

Correct answer

Answer: (c)C.

20%

Why this answer is correct

Shortcut Trick

Let the Cost Price (CP) be 100.

Marked Price (MP) = 100 + 165 = 265.

Required Selling Price (SP) for 112% gain = 100 + 112 = 212.

Discount amount = 265 − 212 = 53.

Discount % = (53 ÷ 265) × 100 = 1/5 × 100 = 20%.

∴ The correct answer is 20%.

Alternate Method

Given:

Markup percentage = 165% above CP

Profit percentage = 112%

Formula Used:

  1. Marked Price (MP) = CP × (100 + Markup %)/100
  2. Selling Price (SP) = CP × (100 + Gain %)/100
  3. Discount % = [(MP − SP) ÷ MP] × 100

Calculations:

⇒ Let the Cost Price (CP) of the item be 100 units.

⇒ Since the Marked Price (MP) is 165% above CP:

⇒ MP = 100 + 165% of 100 = 100 + 165 = 265 units.

⇒ To gain 112%, the Selling Price (SP) must be:

⇒ SP = 100 + 112% of 100 = 100 + 112 = 212 units.

⇒ Discount = MP − SP = 265 − 212 = 53 units.

⇒ Discount % = (Discount ÷ MP) × 100

⇒ Discount % = (53 ÷ 265) × 100

⇒ Discount % = 1/5 × 100 = 20%.

∴ The correct answer is 20%.

Additional Information

Markup Percentage

It is the percentage by which the cost price is increased to set the marked price: Markup % = [(MP − CP) ÷ CP] × 100.

Effective Formula

The relation between Profit, Markup, and Discount is given by: (100 + P%) = (100 + M%) × (100 − D%) ÷ 100.

Discount Calculation

Discount is always calculated on the Marked Price (MP), whereas Profit or Loss is generally calculated on the Cost Price (CP).

Question 926

RRB NTPC 2026• Mathematics• Mathematics

Three friends P, Q, and R start a business by investing in the ratio 2:3:5. If the total profit is ₹10,000, how much more does R receive than P?

  1. AOption (a)

    ₹3,000

  2. BOption (b)

    ₹2,000

  3. COption (c)

    ₹1,000

  4. DOption (d)

    ₹4,000

View answer & explanation

Correct answer

Answer: (a)A.

₹3,000

Why this answer is correct

Shortcut Trick

Identify the ratio of investment for P, Q, and R as 2 : 3 : 5.

Calculate total ratio parts: 2 + 3 + 5 = 10 units.

Find the difference in parts between R and P: 5 − 2 = 3 units.

Apply unitary method: 10 units → ₹10,000, so 1 unit → ₹1,000.

Required difference = 3 units × ₹1,000 = ₹3,000.

∴ The correct answer is ₹3,000.

Alternate Method

Given: Investment ratio of P : Q : R = 2 : 3 : 5. Total Profit = ₹10,000.

Formula Used: Profit share of a partner = (Partner's ratio / Total ratio) × Total Profit

⇒ Total ratio units = 2 + 3 + 5 = 10 units

⇒ Value of 10 units = ₹10,000

⇒ Value of 1 unit = 10,000 ÷ 10 = ₹1,000

⇒ Profit share of P = 2 × 1,000 = ₹2,000

⇒ Profit share of R = 5 × 1,000 = ₹5,000

⇒ Difference between R and P = ₹5,000 − ₹2,000 = ₹3,000

∴ The correct answer is ₹3,000.

Additional Information

Basic Partnership Rule

When the time period of investment is the same for all partners, the profit is distributed directly in the ratio of their capitals.

Compound Partnership

When partners invest for different time periods, Profit Ratio = (Capital1 × Time1) : (Capital2 × Time2).

Ratio and Proportion

To find a specific share from a total, multiply the total by (Individual Ratio ÷ Sum of all Ratios).

Question 927

RRB NTPC 2026• Mathematics• Mathematics

Priya lent ₹920 to her friend at 5% per annum simple interest for 3 years. How much simple interest does she earn in this period?

  1. AOption (a)

    ₹150

  2. BOption (b)

    ₹145

  3. COption (c)

    ₹127

  4. DOption (d)

    ₹138

View answer & explanation

Correct answer

Answer: (d)D.

₹138

Why this answer is correct

Shortcut Trick

The effective rate of interest for 3 years at 5% per annum is:

Effective Interest Rate = 3 × 5% = 15%

Simple Interest (SI) = 15% of ₹920

⇒ SI = (15 ÷ 100) × 920 = ₹138

∴ The correct answer is ₹138.

Alternate Method

Given:

⇒ Principal (P) = ₹920

⇒ Rate of Interest (R) = 5% per annum

⇒ Time (T) = 3 years

Formula Used:

⇒ Simple Interest (SI) = (P × R × T) ÷ 100

Calculations:

⇒ SI = (920 × 5 × 3) ÷ 100

⇒ SI = (920 × 15) ÷ 100

⇒ SI = 13800 ÷ 100

⇒ SI = ₹138

∴ The correct answer is ₹138.

Additional Information

Simple Interest Formula

Interest is computed only on the original principal. SI = (P × R × T) ÷ 100, where P is the principal, R is the rate per annum, and T is time in years.

Total Amount Formula

The total accumulated amount is the sum of the principal and interest: A = P + SI = P × (1 + (R × T) ÷ 100).

Constant Interest Property

In simple interest, the interest amount remains exactly the same every year as long as the principal and rate of interest do not change.

Question 928

RRB NTPC 2026• Mathematics• Mathematics

The HCF of two numbers is 8, and their LCM is 240. If the sum of the two numbers is 88, what are the numbers?

  1. AOption (a)

    24 and 64

  2. BOption (b)

    40 and 48

  3. COption (c)

    32 and 56

  4. DOption (d)

    16 and 72

View answer & explanation

Correct answer

Answer: (b)B.

40 and 48

Why this answer is correct

Shortcut Trick

Check options for Sum = 88 and divisibility by HCF = 8.

For 40 and 48: 40 + 48 = 88 (Matches given Sum).

Check LCM: 40 = 8 × 5 and 48 = 8 × 6.

LCM = 8 × 5 × 6 = 240 (Matches given LCM).

∴ The correct answer is 40 and 48.

Alternate Method

Given: HCF = 8, LCM = 240, and Sum = 88.

Formula Used: Product of two numbers = HCF × LCM; Numbers = HCF × x and HCF × y (where x, y are co-prime).

⇒ Let the numbers be 8x and 8y.

⇒ 8x + 8y = 88 ⇒ x + y = 11

⇒ 8 × x × y = 240 (since LCM = HCF × x × y)

⇒ xy = 240 ÷ 8 = 30

⇒ We need two numbers whose sum is 11 and product is 30. By inspection or solving t2 − 11t + 30 = 0, we get t = 5 and t = 6.

⇒ x = 5 and y = 6.

⇒ Number 1 = 8 × 5 = 40

⇒ Number 2 = 8 × 6 = 48

∴ The correct answer is 40 and 48.

Additional Information

Product Property

For any two numbers a and b, the Product of numbers = HCF(a, b) × LCM(a, b).

Divisibility Rule

The HCF of two or more numbers is always a factor of their LCM and also a factor of their Sum and Difference.

Co-prime Factorization

If HCF is h, numbers can be written as hx and hy, where LCM = h × x × y and gcd(x, y) = 1.

Question 929

RRB NTPC 2026• Mathematics• Mathematics

ABC is an equilateral triangle with side 24 cm and AD is the median. If G is the centroid of the triangle ABC, find the length (in cm) of GD.

  1. AOption (a)

    \( 9\sqrt{3} \)

  2. BOption (b)

    \( 4\sqrt{3} \)

  3. COption (c)

    \( 6\sqrt{2} \)

  4. DOption (d)

    \( 3\sqrt{2} \)

View answer & explanation

Correct answer

Answer: (b)B.

\( 4\sqrt{3} \)

Why this answer is correct

Shortcut Trick

In an equilateral triangle with side a, the length of the median AD (which is also the altitude) is given by:

AD = (√3 ÷ 2) × a

The centroid G divides the median AD in the ratio 2 : 1. Thus, the segment GD is exactly 1/3 of the median AD:

GD = a ÷ (2√3)

Substituting a = 24 cm:

GD = 24 ÷ (2√3) = 12 ÷ √3 = 4√3 cm

∴ The correct answer is 4√3 cm.

Alternate Method

Given:

Side of the equilateral triangle ABC (a) = 24 cm

AD is the median and G is the centroid.

Formula Used:

Height/Median of an equilateral triangle of side a = (√3 ÷ 2) × a

The centroid G divides the median AD from vertex to base in the ratio 2 : 1 (AG : GD = 2 : 1).

Therefore, GD = (1 ÷ 3) × AD

Question 930

RRB NTPC 2026• Mathematics• Mathematics

The present ages of P and Q are in the ratio 4 : 5. Eight years ago, the ratio of their ages was 2 : 3. The harmonic mean of their present ages is:

  1. AOption (a)

    \( 19\frac{7}{9} \) years

  2. BOption (b)

    \( 16\frac{7}{9} \) years

  3. COption (c)

    \( 17\frac{7}{9} \) years

  4. DOption (d)

    \( 18\frac{7}{9} \) years

View answer & explanation

Correct answer

Answer: (c)C.

\( 17\frac{7}{9} \) years

Why this answer is correct

Shortcut Trick

The difference between ratio terms remains constant over time.

Present ratio of P : Q = 4 : 5 (difference = 1 unit)

8 years ago ratio of P : Q = 2 : 3 (difference = 1 unit)

Since the difference is already balanced, the change in ratio units = 4 − 2 = 2 units → 8 years.

⇒ 1 unit = 4 years → Present ages: P = 16 years, Q = 20 years.

Harmonic Mean (HM) = (2 × 16 × 20) ÷ (16 + 20) = 640 ÷ 36 = 160 ÷ 9 = 17(7)/(9) years.

∴ The correct answer is 17(7)/(9) years.

Alternate Method

Given:

Present ratio of ages of P and Q = 4 : 5

Ratio of their ages 8 years ago = 2 : 3

Formula Used:

Harmonic Mean (HM) of two values a and b = 2ab ÷ (a + b)

Present Ages Representation P (4x)