Search Previous Year Questions

The logic follows here, 

NK - PM,

IF - KH,

KH - MJ,

PM - NM,

Therefore, the letter-cluster pair that is different from the others is PM - NM.

Hence, the correct answer is 'Option 2'.

The least possible Venn diagram for the given statements is:

(I) Some butters are scales—Doesn't follow

(Their is no direct relation between butters and scales and some butters are scales; it may be possible but not definite. Hence, it is false) 

(II) All vegetables are scales—Doesn't follow

(All scales are vegetables but all vegetables are scale is may be possible but not definite. Hence, it is false)

Neither conclusion (I) nor (II) follows.

Hence, the correct answer is "option 1".

The logic followed here is:

The pattern is as follows:

• 8 × 2 − 1 = 15
• 15 × 2 − 2 = 28
• 28 × 2 − 3 = 53
• 53 × 2 − 4 = 102
• 102 × 2 − 5 = 199

According to the pattern, the value that should replace the question mark is 102.

Hence, the correct answer is "option 1"

Given: Seven boxes, G, H, I, L, M, N and O, are kept one over the other, but not necessarily in the same order.

1. No box is kept below L.
2. Only four boxes are kept between M and L.
3. H is kept above M.

1. Only two boxes are kept between O and N.
2. I is kept immediately above G.
3. N is not kept immediately above I.

Final Arrangement:

Thus, the box kept fourth from the bottom is I.

Hence, the correct answer is "Option 2".

The logic followed here is ,

The new group of letters formed is: B P M S B B S

Left   B P M S B B S   Right 

The first letter from the right in this group is S.

Hence, the correct answer is "Option 2".

Given: Seven boxes M, N, O, P, X, Y, and Z, are kept one over the other but not necessarily in the same order

1. Only N is kept above P.
2. Only two boxes are kept between P and X.
3. Only O is kept below Y.

1. Z is not kept immediately above X.
2. Only M and Z are remaining to be placed in positions 4 and 5.

Final Arrangement:

Thus, the box kept second above M is P.

Hence, the correct answer is 'Option 2'.

Given: Seven boxes R, A, N, D, O, M and S are kept one over the other but not necessarily in the same order

1. Only five boxes are kept above N.
2. Only three boxes are kept between N and S.
3. O is kept at one of the positions below N.

1. Only D is kept between S and R.
2. A is kept at one of the positions above S.

Final Arrangement:

Thus, two boxes are kept between R and O.

Hence, the correct answer is 'Option 4'.

BODMAS Table: 

Given: 34 B 45 D 5 A 2 C 4 

Replacing the letters with mathematical signs and applying the BODMAS rule:

= 34 − 45 ÷ 5 + 2 × 4

= 34 − 9 + 2 × 4

= 34 + 8 − 9

= 42 − 9

= 33

Hence, the correct answer is "option 3"

Given number: 8254316

Number formed : 6 0 8 2 6 4 4

• Third from the left is: 8
• Third from the right is: 6

So, the sum of the digit third from the left and the digit third from the right is:8 + 6 = 14.

Hence, the correct answer is 'Option 2'.

The logic followed here is:

• 47 + 14 = 61
• 61 + 17 = 78
• 78 + 20 = 98
• 98 + 23 = 121
• 121 + 26 = 147
• 147 + 29 = 176

Thus, the missing term in the series is 176.

Hence, the correct answer is 'Option 3';