The diagonals of a rhombus-shaped field are 224 m and 420 m long.
What is the perimeter (in m) of the field?
- AOption (a)
952
- BOption (b)
922
- COption (c)
904
- DOption (d)
944
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Correct answer
952
Why this answer is correct
Shortcut Trick
Ratio of half-diagonals = (224/2) : (420/2) = 112 : 210 = 8 : 15 (divided by 14).
Using Pythagorean triplet (8, 15, 17), the side ratio is 17.
Actual side of rhombus = 17 × 14 = 238 m.
Perimeter = 4 × Side = 4 × 238 = 952 m.
∴ The correct answer is 952 m.
Alternate Method
Given:
Diagonal 1 (d1) = 224 m
Diagonal 2 (d2) = 420 m
Formula Used:
Side of rhombus (a) = √[(d1/2)2 + (d2/2)2]
Perimeter of rhombus = 4 × a
Calculations:
⇒ Half of Diagonal 1 = 224 ÷ 2 = 112 m
⇒ Half of Diagonal 2 = 420 ÷ 2 = 210 m
⇒ Side (a) = √(1122 + 2102)
⇒ Side (a) = √(12544 + 44100)
⇒ Side (a) = √56644
⇒ Side (a) = 238 m
⇒ Perimeter = 4 × 238
⇒ Perimeter = 952 m
∴ The correct answer is 952 m.
Additional Information
Properties of a Rhombus
A rhombus is a quadrilateral with all sides equal. Its diagonals bisect each other at right angles (90°).
Area of Rhombus
The area of a rhombus can be calculated using diagonals as: Area = 1/2 × d1 × d2.
Relation between Side and Diagonals
For a rhombus with side 'a' and diagonals d1 and d2, the relation is: 4a2 = d12 + d22.