Which two numbers should be interchanged to make the given equation correct?
(28 ÷ 4) × 6 + 14 × 3 − 7 × 9 + (66 ÷ 2) + 38 = 67
- AOption (a)
2 and 6
- BOption (b)
2 and 3
- COption (c)
6 and 3
- DOption (d)
4 and 7
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Correct answer
2 and 3
Why this answer is correct
BODMAS Table:
On interchanging each option one by one,
- 2 and 6L.H.S = (28 ÷ 4) × 2 + 14 × 3 − 7 × 9 + (66 ÷ 6) + 38
= 7 × 2 + 42 − 63 + 11 + 38
= 14 + 42 − 63 + 11 + 38
= 56 − 63 + 11 + 38
= −7 + 11 + 38
= 42 ≠ 67 (R.H.S)
Option 2) 2 and 3
(28÷4) × 6 + 14 × 2 − 7 × 9 + (66 ÷ 3 ) + 38 = 67
L.H.S = 7 × 6 + 14 × 2 − 63 + 22 + 38
= 42 + 28 − 63 + 22 + 38
= 70 − 63 + 22 + 38
= 7 + 22 + 38
= 67 = 67 (R.H.S)
- (28 ÷ 4 ) × 3 + 14 × 6 − 7 × 9 + (66÷2) + 38 = 67
L.H.S = 7 × 3 + 14 × 6 − 63 + 33 + 38
= 21 + 84 − 63 + 33 + 38
= 105 − 63 + 33 + 38
= 42 + 33 + 38
= 113 ≠ 67 (R.H.S)
- 4 and 7
L.H.S = (28÷7) × 6 + 14 × 3 − 4 × 9 + (66 ÷ 2) + 38 = 67
= 4 × 6 + 42 − 36 + 33 + 38
= 24 + 42 − 36 + 33 + 38
= 66 − 36 + 33 + 38
= 30 + 33 + 38
= 101 ≠ 67 (R.H.S)
Since LHS = RHS, the equation is correct after interchanging 2 and 3.
Hence, the correct answer is "option 2"