Based on the alphabetical order, three of the following four are alike in a certain way and thus form a group.
Which is the one that does not belong to that group?
(Note: The odd man out is not based on the number of consonants/vowels or their position in the letter cluster.)
- AOption (a)
OLM
- BOption (b)
CYA
- COption (c)
EAC
- DOption (d)
AWY
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Correct answer
OLM
Why this answer is correct
The logic followed here is,
Logic: Second letter = First letter − 4; Third letter = Second letter + 2.
OLM,
CYA,
EAC,
AWY,
Therefore, the letter cluster that is different from the others is OLM.
Hence, the correct answer is 'Option 1'.