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The least possible Venn diagram for the given statements is:

(I) Some Eagles are Peacocks - Doesn't Follow

There is no direct relation between eagles and peacock. So, may be it is possible but not definite. Hence, it is false)

(II) No Peacocks are Eagles -  Doesn't Follow

There is no direct relation between eagles and peacock. So, may be it is possible but not definite. Hence, it is false)

Neither conclusion (I) nor (II) follows

Hence, the correct answer is "Option 3"

Preparing the family tree diagram by using the following symbols:

As per the given information:

Given: A ÷ B × C + D − E ÷ F

The Family tree diagram,

​Therefore, A is the sister of B, who is the father of F → A is the Father's sister of F.

Hence, the correct answer is 'Option 1'.

The logic follows here, 

Hence, the code for the " add " is se

Hence, the correct answer is "option 1"

The logic followed here is:

• 4 × 2 + 2 = 10
• 10 × 2 − 2 = 18
• 18 × 2 + 2 = 38
• 38 × 2 − 2 = 74
• 74 × 2 + 2 = 150

Thus, the missing term in the series is 150.

Hence, the correct answer is 'Option 4';

The logic followed here is,

Logic: Each vowel in the word is changed to the letter immediately following it (+1), and each consonant is changed to the letter immediately preceding it (−1) 

Given word :  RADULAE

The new group of letters formed is: Q, B, C, V, K, B, F.

• B appears exactly twice in the new sequence.
• Therefore, the total count of letters appearing exactly twice is one.

Hence, the correct answer is "option 2"

The logic follows here, 

KL 9 is related to IH −2,

PG 7 is related to NC −4,

Applying the same logic to JQ 14,

Hence, the correct answer is 'Option 2'.

The logic follows here, 

The term that comes in place of the question mark is RTA.

Hence the correct answer is "option 1"

BODMAS Table:

Given equation:3 A 42 B 14 C 29 D 22 = ?

Replacing the alphabets with signs and applying BODMAS rule:

= 3 ÷ 42 × 14 + 29 − 22

= (1/14) × 14 + 29 − 22

= 1 + 29 − 22

= 30 − 22

= 8

Hence, the correct answer is "option 1"

The logic follows here, 

Logic: Each letter in a group is shifted forward by 4 positions in the English alphabetical .

Combining the letters, we get the term JKM.

Hence, the  correct answer is "option 2"

Given: Seven boxes, K, N, I, G, H, T and S, are kept one over the other, but not necessarily in the same order.

1. K is kept fourth from the top.
2. Only one box is kept between H and K.
3. S is kept at some place above K.
4. Only three boxes are kept between H and S.

1. I is kept immediately below S.
2. G is not kept immediately above or below H.
3. N is kept at one of the places above T.

Final Arrangement:

Thus, there are two boxes kept below N.

Hence, the correct answer is 'Option 1'.