The largest four-digit number which when divided by 10, 11 and 8 leaves remainder 7 in each case is:
- AOption (a)
9687
- BOption (b)
9557
- COption (c)
9398
- DOption (d)
9978
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Correct answer
9687
Why this answer is correct
Shortcut Trick
Step 1: Calculate the LCM of 10, 11, and 8 ⇒ 440.
Step 2: Find the largest 4-digit multiple of 440 ⇒ 440 × 22 = 9680.
Step 3: Add the required remainder (7) to this multiple ⇒ 9680 + 7 = 9687.
∴ The correct answer is 9687.
Alternate Method
Given: Divisors are 10, 11, and 8; Remainder in each case is 7.
Formula Used: Required Number = (LCM of divisors × k) + Remainder
⇒ LCM(10, 11, 8) = 23 × 5 × 11 = 8 × 5 × 11 = 440
⇒ The largest four-digit number is 9999.
⇒ Dividing 9999 by 440: 9999 ÷ 440 = 22 with a remainder of 319.
⇒ The largest multiple of 440 below 10000 = 9999 − 319 = 9680.
⇒ The required number = 9680 + 7 = 9687.
∴ The correct answer is 9687.
Additional Information
LCM (Least Common Multiple)
It is the smallest positive integer that is evenly divisible by all numbers in a given set.
The Remainder Property
If a number N leaves a constant remainder R when divided by a, b, and c, then N = LCM(a, b, c) × k + R.
Divisibility Rule of 11
A number is divisible by 11 if the difference between the sum of digits at odd places and even places is 0 or a multiple of 11.