Search Previous Year Questions

**Given:**Seven boxes, G, H, I, J, Q, R and S, are kept one over the other, but not necessarily in the same order.

1. Only Q is kept above S.
2. Only four boxes are kept between S and H.

1. Only two boxes are kept between J and R.
2. G is kept immediately above I.
3. R is not kept immediately above G.

Final Arrangement:

Thus, there are five boxes kept above R.

Hence, the correct answer is "Option 2"

The logic follows here, 

Logic: First letter of the 2^nd cluster = First letter of the 1^st cluster + 5; Second letter of the 2^nd cluster = Second letter of the 1^st cluster + 4.

For OM-TQ,

For QO-VS,

For  SQ-XV,

For  MK-RO,

Therefore, the letter-cluster pair that is different from the others is SQ-XV.

Hence, the correct answer is 'Option 3'.

BODMAS 

Sign Interchange Table:

Equation after interchanging signs and applying BODMAS rule

= 28 + 13 − 17 × 43 ÷ 43 

= 28 + 13 − 17 × 1

= 28 + 13 − 17

= 41 − 17

= 24

Hence, the correct answer is "option 1"

Given number: 621453

According to the question,if 2 is added to each odd digit and 2 is subtracted from each even digit in the number,

• The new number thus formed is: 403275
• Now, identify the even digits in this new number: 4, 0, and 2.
• So, the sum of all even digits is: 4 + 0 + 2 = 6.

Hence, the correct answer is  'Option 3'.

The logic follows here, 

Given: MELODIA

According to information, 

• The new group of letters formed is: L, F, K, P, C, J, B
• There are no letters that appear exactly twice in the new group.
• Therefore, the number of letters appearing exactly twice is Zero.

Hence, the correct answer is "Option 3"

The logic follows here, 

Logic: Second letter = First letter + 2; Third letter = Second letter − 4.

For OQM,

For  FHE,

For KMI,

For TVR,

Therefore, the letter cluster that is different from the others is FHE.

Hence, the correct answer is 'Option 2'.

The logic follows here, 

By comparing the words and their codes, we can determine the code for individual letters.

Thus, the code for A is 4.

Hence, the correct answer is "option 1"

The logic followed here is:

Logic: (First Number × Second Number) + 2 = Third Number

For the first set (24, 11, 266)

⇒ (24 × 11) + 2

⇒ 264 + 2 = 266.

For the second set (26, 13, 340)

⇒ (26 × 13) + 2

⇒ 338 + 2 = 340.

Applying the same logic to the third set

(25, 9, 227)

⇒ (25 × 9) + 2

⇒ 225 + 2 = 227.

Hence, the correct answer is 'Option 3'.

Given: Six boxes, Q, R, S, T, U and W, are kept one over the other, but not necessarily in the same order.

1. Only S is kept above W.
2. No box is kept below R.
3. Only one box is kept between U and R.

1. T is kept at some place below Q.

Final Arrangement:

Thus, the box kept immediately above T is U.

Hence, the correct answer is 'Option 2'.

The logic follows here,

The logic followed here is the comparison of common letters and their corresponding digits in the given words.

Therefore, the code for the letter M must be 6.

Hence, the correct answer is "Option 2"