Three numbers x ≤ y ≤ z which are co-prime to each other are such that the product of the first two numbers is 143 and that of the last two numbers is 195. The sum of the three numbers is ______.
- AOption (a)
62
- BOption (b)
45
- COption (c)
39
- DOption (d)
29
View answer & explanationHide answer & explanation
Correct answer
39
Why this answer is correct
Shortcut Trick
Given xy = 143 and yz = 195.
Since y is common, find HCF(143, 195).
143 = 11 × 13 and 195 = 15 × 13.
∴ y = 13, x = 11, and z = 15.
Sum = 11 + 13 + 15 = 39.
∴ The correct answer is 39.
Alternate Method
Given: x ≤ y ≤ z are co-prime numbers.
Equations:
⇒ x × y = 143
⇒ y × z = 195
Calculations:
⇒ y = HCF(143, 195)
⇒ 143 = 11 × 13
⇒ 195 = 13 × 15
⇒ Common factor y = 13
⇒ x = 143 ÷ 13 = 11
⇒ z = 195 ÷ 13 = 15
⇒ x (11) ≤ y (13) ≤ z (15) [Condition Satisfied]
⇒ Sum = 11 + 13 + 15 = 39
∴ The correct answer is 39.
Additional Information
Co-prime Numbers
Numbers are co-prime if their Highest Common Factor (HCF) is 1. In this set, HCF(11, 13) = 1, HCF(13, 15) = 1, and HCF(11, 15) = 1.
HCF and Product Property
When two products share a common variable, that variable must be the HCF of the two products if the remaining factors are co-prime.
Prime Factorization
Breaking down a composite number into a product of prime numbers helps in identifying common factors quickly.