If in the given figure PS||QR and PQ||SR , then the value of ∠QPS is :

- AOption (a)
36°
- BOption (b)
90°
- COption (c)
54°
- DOption (d)
100°
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Correct answer
90°
Why this answer is correct
Concept used:
The Sum of the angle of a triangle is 180°
When a transversal intersects two parallel lines then alternate interior angles are equal
Calculations:
ΔQSR
∠SQR + ∠QRS + ∠RSQ = 180°
⇒ 2x + 3x + 5x = 180°
⇒ 10x = 180°
⇒ x = 18°
⇒ ∠SQR = 2 × 18° = 36°
⇒ ∠QSR = 3 × 18° = 54°
⇒ ∠SRQ = 5 × 18° = 90°
Now, PS II QR and SQ is transversal
⇒ ∠RSQ = ∠SQP = 54° --(as PQ||SR)
⇒ ∠RQS = ∠QSP = 36° --(as PS||QR)
In ΔPQS
∠PQS + ∠PSQ + ∠QPS = 180°
⇒ 54° + 36° + ∠QPS = 180°
⇒ ∠QPS = 180° - (54° + 36°)
⇒ ∠QPS = 180° - 90°
∴ ∠QPS = 90°