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Follow BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in the ‘BRACKETS’ must be solved first

Step-2: Any mathematical ‘OF’ or ‘EXPONENTS’ must be solved next

Step-3: Next the part of the equation that contains ‘DIVISION; and ‘MULTIPLICATION’ are calculated

Step-4: Last but not least, the parts of the equation that contains ‘ADDITION’ and ‘SUBTRACTION’ should be calculated

Now, the given expression:

⇒ 937 + (9)³ ÷ 27 × (3)⁴ = ?

\(\Rightarrow 937; + ;\frac{{{{\left( 9 \right)}^3}}}{{27}}; \times ;{3^{4;}}; = ;?\)

⇒ 937 + (9)³ × 3 = ?

⇒ 937 + 729 × 3 = ?

⇒ 937 + 2187 = ?

⇒ 3124 = ?

Follow BODMAS rule to solve this question, as per the order is given below,

Step-1∶ Parts of an equation enclosed in 'Brackets' must be solved first and in the bracket,

Step-2∶ Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3∶ Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4∶ Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

⇒ 5 + (5 × 5) – 5 + 5

⇒ 5 + 25 – 5 + 5

⇒ 30

Follow BODMAS rule to solve this question, as per the order given below,

Step 1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step 2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step 4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is,

⇒ {(3654 + 1346) × 2} ÷ 100 = ?

⇒ {(5000) × 2} ÷ 100 = ?

⇒ ? = 10000 ÷ 100

⇒ ? = 100

Given:

A batsman’s 16^th innings score = 60 runs

The average increases by = 3

Calculation:

Let the average after 16^th innings be x

The average after 15^th innings = (x – 3)

∴ According to the question:

⇒ 16x = 15 (x – 3) + 60

⇒ 16x = 15x – 45 + 60

⇒ 16x – 15x = 15

⇒ x = 15

∴ the batsman’s average after his 16^th innings is 15 runs.

Given:

Speed of train = 54 km/h

Time train takes to cross a tree = 13 sec

Length of a platform = 75 m

Formula used:

Speed = Distance/Time

Calculation:

Speed of the train in m/sec = 54 × (5/18) = 15 m/sec

⇒ Length of the train = 15 × 13 = 195 m

Time taken to cross the platform = (195 + 75)/15

⇒ Time taken to cross the platform = 270/15 = 18 sec

∴ The time train will take to cross the platform is 18 sec.

Total produced units = 300 + 450 + 400 + 500 + 420 = 2070

Total sold units = 180 + 300 + 350 + 320 + 360 = 1510

⇒ required difference = 2070 – 1510 = 560

Units produced by A = 300

So, units produced by company F = 300 × 110/100 = 330

Units sold by company C = 350

So, units sold by company F = 350 × 80/100 = 280

Unsold unit of company F = 330 – 280 = 50

Unsold unit of company A = 120

Unsold unit of company B = 150

Unsold unit of company C = 50

Unsold unit of company D = 180

Unsold unit of company E = 60

Average unit remain unsold = (120 + 150 + 50 + 180 + 60)/5 = 112

Unit produced by Company C = 400

Units sold by Company B = 300

⇒ Required percent = (400 -300)/300 × 100 = 33.33%

Unsold unit of company E = 420 – 360 = 60

Unsold unit of company D = 500 – 320 = 180

Unsold units of Company E and D together = 180 + 60 = 240

Sold units of company A = 180

Sold units of company B = 300

Sold units of company A and B together = 180 + 300 = 480

⇒ required ratio = 240 : 480

⇒ 1 : 2