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Given Series:

Left Side  Z @ 9 4 M R $ P 7 # Y G 5 K 3 & C B 4 D V E 1 ? 6 % L  Right Side

Numbers in the above arrangement, which are immediately preceded by an alphabet but not immediately followed by an alphabet:

Z @ 9 4 M R $ P 7 # Y G 5 K 3 & C B 4 D V E 1 ? 6 % L 

Hence, there are three numbers in the above arrangement which are immediately preceded by an alphabet but not immediately followed by an alphabet: P 7 #, K 3 & and E 1 ?

Given Series:

Left Side  Z @ 9 4 M R $ P 7 # Y G 5 K 3 & C B 4 D V E 1 ? 6 % L  Right Side

• If all the numbers are dropped, then the arrangement will be:

                    Z @ M R $ P # Y G K & C B D V E ? % L 

• And, the ninth element from the right end is &.

        ( Z  @ M  R  $  P  #  Y  G  K  &  C  B   D  V   E   ?  %  L ) Right End

Hence, the ninth element from the right end is &$.

Given Series:

Left Side Z @ 9 4 M R $ P 7 # Y G 5 K 3 & C B 4 D V E 1 ? 6 % L Right Side

• Condition 1: Seventh to the left of,
• Condition 2: Seventeenth element from the right end.

Starting from the second condition, the

seventeenth element from the right end is Y.

Then, the seventh element to the left of Y is 4.

Hence, 4 is the correct answer.

1. Whenever in such questions, a combination of opposite ends is asked; firstly add the positions mentioned- like here, 7^th to the left and 17^th from the right, so 17 + 7 = 24.
2. Then, count from the end mentioned in the second condition i.e. on counting from the right end here, ‘4’ is at the 24^th position.

          Therefore, 4 is the correct answer$.

Given Series:

Left Side Z @ 9 4 M R $ P 7 # Y G 5 K 3 & C B 4 D V E 1 ? 6 % L Right Side

• Condition 1: Eleventh to the left of,
• Condition 2: Twenty-fifth element from the left end.

Starting from the second condition, the twenty-fifth element from the left end is 6.

Then, the eleventh element to the left of 6 is K.

Hence, K is the correct answer.

1. Whenever in such questions, a combination of same ends is asked; firstly subtract the positions mentioned- like here, 11^th to the left and 25^th from the left, so 25 - 11 = 14.
2. Then, count from the end mentioned in the second condition i.e. on counting from the left end here, ‘K’ is at the 14^th position.

Hence, K is the correct answer$.

Thus, there are 5 such pairs of numbers: Forward – (2-4), (3-5), (5-7), (3-7) and Backward – (3-4).

Hence, five is the correct answer.

The codes are as follows:

Hence, 'party car' will be coded as 'su fa'.

The codes are as follows:

Hence, 'your' will be coded as 'hn'.

The codes are as follows:

Hence, 'sun boat' will be coded as 'ek ty'

The codes are as follows:

Hence, 'pr' is the code for 'are'.

The codes are as follows:

Hence, 'fast run' will be coded as 'xb gd'.