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The least possible Venn diagram for the given statements is as follows:

Conclusions:

I. All Mouse are Laptop→ False (As per the statement there is no definite relation between mouse and laptop)

II. All Computers are Laptop→ False (As per the statement some computer are laptop but whether all computer are laptop or not is not definite)

Hence, Neither I nor II follows.

The least possible Venn diagram for the given statements is as follows

Conclusions:

I. Some Cars are Trucks→ True (If all Truck are Vehicles and all Vehicles are Cars then some Cars are Trucks possible to be definite).

II. All Trucks are Cars→ True (If all Trucks are Vehicles and all Vehicles are Cars then all Trucks are Cars possible to be definite)

Hence, Both I and II follow.

Additional Information

1. Some X are Y means some part of the X circle is within the Y circle. 2. No X is Y means circle X and Y are not intersecting at all.
2. All X is Y means the whole circle X lies within the Y circle.
3. If there is no exact conclusion for the given statements then the possibility case arises.
4. If Only X is Y means all Y is X, Y cannot make positive relation with any other element except X negative can be possible.  
5. Only a few = Some + Some not.

The least possible Venn diagram for the given statements is as follows

Conclusions:

I. All Sofa are Chair → False (If no Chair is Table and no Sofa is Chair then there is no possibility to be all Sofa are Chair).

II. No Sofa is Chair → False (It is possible but not definite).

Hence, None follow.

Conditions of Either-or case:

1. The elements should be the same in both the statements.
2. Both the conclusions should be false individually.
3. One conclusion should be positive and one conclusion should be negative (Complementary pair)

The two complementary pairs are:

1. All + Some not

2. No + Some

Note: Some + Some not and All + No is not considered under Either-or case.

Additional Information

1. Some X are Y means some part of the X circle is within the Y circle. 2. No X is Y means circle X and Y are not intersecting at all.
2. All X is Y means the whole circle X lies within the Y circle.
3. If there is no exact conclusion for the given statements then the possibility case arises.
4. If Only X is Y means all Y is X, y cannot make positive relation with any other element except X negative can be possible. 
5. Only a few = Some + Some not.

The least possible Venn diagram is shown below

i) Some screen are definitely not display ⇒ False (As there is no negative realtion given between Screens and Displays, definite conclusion of some not will be false.)

ii) All display being screens is a possibility ⇒ True (As there is no definite relation given between Display and Screens, a possibility will be true.)

Hence, only II follows.

According to the given information-

1. Only one floor gap is there between R and L and both lives in same flat number. K lives to the west of R. R lives above L. Hence, R and L live on flat 2. Here we get 2 possible cases, case 1 and case 2. In case 1, R and L live in floor 4 and floor 2 respectively and in case 2, R and L lives in floor 3 and floor 1 respectively.

2. U lives to the east of C. U does not live on the top floor. Here we het three case. i.e. Case-1(a), case-1(b) and case -3. In case-1(a) C and U lives on floor 3. In case-1(b), C and U lives on floor 1 and in case- 2, C and U lives on floor 2.

3. Only one floor gap is there between C and J and both lives in same flat number. J lives on one of the floors below N and both lives in same flat number. So, in case 1(a), C lives in 3^rd floor and J lives in 1^st floor because J lives on the floor below N hence N lives on floor 2. Case-1 (b) will be eliminated and In case 2, If we placed C on floor 1 and J on floor 3 then we must place N on floor 2 but there is also K available in floor 3. So, from this case-2 gets eliminated. So, the final arrangement is-

Two persons are lives above N on the same flat.

According to the given information-

1. Only one floor gap is there between R and L and both lives in same flat number. K lives to the west of R. R lives above L. Hence, R and L live on flat 2. Here we get 2 possible cases, case 1 and case 2. In case 1, R and L live in floor 4 and floor 2 respectively and in case 2, R and L lives in floor 3 and floor 1 respectively.

2. U lives to the east of C. U does not live on the top floor. Here we het three case. i.e. Case-1(a), case-1(b) and case -3. In case-1(a) C and U lives on floor 3. In case-1(b), C and U lives on floor 1 and in case- 2, C and U lives on floor 2.

3. Only one floor gap is there between C and J and both lives in same flat number. J lives on one of the floors below N and both lives in same flat number. So, in case 1(a), C lives in 3^rd floor and J lives in 1^st floor because J lives on the floor below N hence N lives on floor 2. Case-1 (b) will be eliminated and In case 2, If we placed C on floor 1 and J on floor 3 then we must place N on floor 2 but there is also K available in floor 3. So, from this case-2 gets eliminated. So, the final arrangement is-

 U lives on flat 2 floor 3.

According to the given information-

1. Only one floor gap is there between R and L and both lives in same flat number. K lives to the west of R. R lives above L. Hence, R and L live on flat 2. Here we get 2 possible cases, case 1 and case 2. In case 1, R and L live in floor 4 and floor 2 respectively and in case 2, R and L lives in floor 3 and floor 1 respectively.

2. U lives to the east of C. U does not live on the top floor. Here we het three case. i.e. Case-1(a), case-1(b) and case -3. In case-1(a) C and U lives on floor 3. In case-1(b), C and U lives on floor 1 and in case- 2, C and U lives on floor 2.

3. Only one floor gap is there between C and J and both lives in same flat number. J lives on one of the floors below N and both lives in same flat number. So, in case 1(a), C lives in 3^rd floor and J lives in 1^st floor because J lives on the floor below N hence N lives on floor 2. Case-1 (b) will be eliminated and In case 2, If we placed C on floor 1 and J on floor 3 then we must place N on floor 2 but there is also K available in floor 3. So, from this case-2 gets eliminated. So, the final arrangement is-

 R lives on the floor just above U on the same flat.

According to the given information-

1. Only one floor gap is there between R and L and both lives in same flat number. K lives to the west of R. R lives above L. Hence, R and L live on flat 2. Here we get 2 possible cases, case 1 and case 2. In case 1, R and L live in floor 4 and floor 2 respectively and in case 2, R and L lives in floor 3 and floor 1 respectively.

2. U lives to the east of C. U does not live on the top floor. Here we het three case. i.e. Case-1(a), case-1(b) and case -3. In case-1(a) C and U lives on floor 3. In case-1(b), C and U lives on floor 1 and in case- 2, C and U lives on floor 2.

3. Only one floor gap is there between C and J and both lives in same flat number. J lives on one of the floors below N and both lives in same flat number. So, in case 1(a), C lives in 3^rd floor and J lives in 1^st floor because J lives on the floor below N hence N lives on floor 2. Case-1 (b) will be eliminated and In case 2, If we placed C on floor 1 and J on floor 3 then we must place N on floor 2 but there is also K available in floor 3. So, from this case-2 gets eliminated. So, the final arrangement is-

 R lives on the north-east of C.

According to the given information-

1. Only one floor gap is there between R and L and both lives in same flat number. K lives to the west of R. R lives above L. Hence, R and L live on flat 2. Here we get 2 possible cases, case 1 and case 2. In case 1, R and L live in floor 4 and floor 2 respectively and in case 2, R and L lives in floor 3 and floor 1 respectively.

2. U lives to the east of C. U does not live on the top floor. Here we het three case. i.e. Case-1(a), case-1(b) and case -3. In case-1(a) C and U lives on floor 3. In case-1(b), C and U lives on floor 1 and in case- 2, C and U lives on floor 2.

3. Only one floor gap is there between C and J and both lives in same flat number. J lives on one of the floors below N and both lives in same flat number. So, in case 1(a), C lives in 3^rd floor and J lives in 1^st floor because J lives on the floor below N hence N lives on floor 2. Case-1 (b) will be eliminated and In case 2, If we placed C on floor 1 and J on floor 3 then we must place N on floor 2 but there is also K available in floor 3. So, from this case-2 gets eliminated. So, the final arrangement is-

N lives on Floor 2 Flat 1.

Given Series:

Left Side  Z @ 9 4 M R $ P 7 # Y G 5 K 3 & C B 4 D V E 1 ? 6 % L  Right Side

Consonants in the above arrangement which are immediately preceded by a consonant and immediately followed by a symbol:

Z @ 9 4 M R $ P 7 # Y G 5 K 3 & C B 4 D V E 1 ? 6 % L 

Hence, there is one consonant in the above arrangement which is immediately preceded by a consonant and immediately followed by a symbol: R in M R $

Hence, One is the correct answer$.