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Given,

26 January 2020 is Sunday

Remaining days in January is 5 days

Number of days from February 1^st to August 15^th are

Total number days in February = 29 

Total number days in March = 31

Total number days in April = 30

Total number days in  May = 31

Total number days in June = 30

Total number days in July = 31

The days in August up to 15^th

Total number of days = 5 + 29 + 31 + 30 + 31 + 30 + 31 + 15 = 202

Number of odd days = 202 ÷ 7 = 28 weeks + 6 odd days

15 August = Sunday + 6 odd days = Saturday

Hence, "Saturday" is the correct answer.

2020 Year is a leap year

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Number of odd days in January = 5

Number odd days in February = 29 = 4 weeks + 1 = 1

Number odd days in March = 31 = 4 weeks + 3 = 3

Number odd days in April = 30 = 4 weeks + 2 = 2

Number odd days in  May = 31 = 4 weeks + 3 = 3 

Number odd days in June = 30 = 4 weeks + 2 = 2

Number odd days in July = 31 = 4 weeks + 3 = 3

Number of odd days in August 15 days = 2 weeks + 1

Total number of odd days = 5 + 1 + 3 + 2 + 3 + 2 + 3 + 1 = 20 odd days

Number of odd days = 20 ÷ 7 = 2 weeks + 6 odd days

August 15^th = Sunday + 6 odd days = Saturday

The stepwise possible diagram of this sitting arrangement is:

1. A and B are sitting exactly opposite to each other.
2. H is to the immediate left of G but to the immediate right of B 3.  Only E is between B and C. C and G are opposite to each other. F is sitting second to the left of D.

After combining all the statements we get:

5. Only A and E turn 180° and sit facing away from the table.

After rotating 180° by A and E, We get the circle as follows:

After rotating 180°, A shift to the position of B and E shift to the position of F and vice-versa.

Hence, "H" is the correct answer.

The logic follows here is:

Pattern: Number of letters given from "One to Thirteen".

Hence, "3" is the correct answer.

The logic follows here is:

In the First diagram logic is: (Square root of the 25 + square root of 9) x 12 + 2

= (5 + 3) x 12 + 2 = (8 x 12) + 2 = 98.

In the Second diagram logic is: (Square root of the 36 + square root of 16) x 15 + 2

= (6 + 4) x 15 + 2 = (10 x 15) + 2 = 152.

Similarly,

In the Third diagram logic is: (Square root of the 49 + square root of 25) x 18 + 2

= (7 + 5) x 18 + 2 = (12 x 18) + 2 = 218.

Hence, "218" is the correct answer.

The logic follows here is:

Pattern: First alphabet increased by +2, Second alphabet decreased by -3 and Number is difference of (largest alphabet - smallest alphabet - 1)

Hence, "DP11" is the correct answer.

Given:

Principal = Rs.31,250

Rate = 8%

Time = \(1 \frac{1}{2}\) = 3/2 years

Formula Used:

Amount = Principal × {1 + Rate/(2 × 100)}^{2 × time}

Compound Interest = Amount - Principal

Calculation:

Amount = 31250 × (1 + 8/200)^{2 × 3/2}

Amount = Rs.35152

Compound Interest = 35152 - 31250 = Rs.3902

∴ The compound interest is Rs.3902

Calculation:

⇒ 4x/5y = 16/15

⇒ x/y = 4/3

⇒ x = 4y/3

According to the question;

⇒ 2x + 3y = 85

⇒ 2 × (4y/3) + 3y = 85

⇒ 17y/3 = 85

⇒ y = 15

⇒  x = 4 × 15/3 = 20

Then, 2y - x = 30 - 20 = 10

∴ The value of 2y - x is 10.

Given:

The amount spend on house rent is 2/5 of his salary

The amount spend on food is 3/7 of his salary

The amount spend on conveyance is 1/8 of his salary

Calculation:

Let the salary be 1

Total spending on house rent, food and conveyance = 2/5 + 3/7 + 1/8 = 267/280

The remaining amount = 1 - 267/280 = 13/280

⇒ 13/280 = 1300

⇒ 1 = 28000

Amount spend on house rent = 2/5 × 28000 = Rs.11200

Amount spend on food = 3/7 × 28000 = Rs.12000

Total spend on house rent and food = 11200 + 12000 = Rs.23,200

∴ The total expenditure on house rent and food is Rs.23,200

Calculation:

The least common factor of 12, 16 and 24 = 48

The largest 3 digit number = 999

When 999 divided by 48 got remainder 39

The greatest three digit number divisible by 48 = 999 - 39 = 960

∴ The greatest three digit number which is divisible by 12, 16 and 24 is 960

Calculation:

⇒ \(\dfrac{2}{3} + \dfrac{2}{15}+ \dfrac{2}{35}+ \dfrac{2}{63}+ \dfrac{2}{99}\)

⇒ (2310 + 462 + 198 + 110 + 70)/3465

⇒ 3150/3465

⇒ 10/11

∴ The value of \(\dfrac{2}{3} + \dfrac{2}{15}+ \dfrac{2}{35}+ \dfrac{2}{63}+ \dfrac{2}{99}\) is 10/11