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Let the number of books published by company C in May be x

Number of books published by Company C in June be x

Now,

Average number of books received by each distributor of Company C in May and June was 168.

Average = Sum of all the observations/Total number of observations

⇒ Total number of books received by each distributor of Company C in May and June

⇒ 168 × 32 = 5376

According to the given table

⇒ 65% of x +75% x = 5376

⇒ (65/100) × x + (75/100) × x = 5376

⇒ 140x = 537600

⇒ x = 3840

∴ Number of books published by Company C in June is 3840

Let the number of books published by company D in May be x

Number of books published by company E in May be y

According to question,

$\Rightarrow \frac{1}{8} \times \frac{{72}}{{100}} \times x = \frac{1}{6} \times \frac{{90}}{{100}} \times y$

⇒ x/y = 5/3

∴ Required percentage = (3/5) × 100 = 60%

Let the number of books published by Company D in June be 3x

According to the question,

Number of books published by Company B in June will be x

Now,

(52/100) × 3x = (84/100) × x = 864

⇒ 156x - 84x = 86400

⇒ 72x = 86400

⇒ x = 1200

∴ Number of published by company B is 1200

Total number of distributors of company A in June = 16

Each distributor of company A received 255 books

Total books distributed by company A = 16 × 255 = 4080

Now,

From the table we can say that,

85% = 4080

⇒ 1% = 4080/85

⇒ 100% = (4080/85) × 100 = 4800

∴ Total number of books published by Company A in June = 4800

Calculation:

Let the number of books published by E in June be 100

Number of books received by each distributor of company E in June

$\Rightarrow \frac{1}{{11}} \times \frac{{88}}{{100}} \times 100 = 8$

Number of the books not distributed by the company E among its distributors in June

⇒ (12/100 × 100) = 12

∴ Required percentage = (12 - 8)/12 × 100 = 33.33%

1. The person first goes 5 km towards the east.

2. Then he turns left and travels in the north direction.

3. Then he turns right and travels in the east direction.

4. Then again he turns right and travels in the south direction.

5. He then turns left and travels in the east direction and after taking one more left he travels in the north direction.

6. He finally takes a left turn and travels in the west direction.

The least possible graphical representation of the given data is:

Point N is to the north-west of point Q.

1. The person first goes 5 km towards the east.

2. Then he turns left and travels in the north direction.

3. Then he turns right and travels in the east direction.

4. Then again he turns right and travels in the south direction.

5. He then turns left and travels in the east direction and after taking one more left he travels in the north direction.

6. He finally takes a left turn and travels in the west direction.

The least possible graphical representation of the given data is:

The starting point is L and the finishing point is S which is 8 km to the east of L.

The shortest distance between the starting and the finishing point is 8 km.

1. The person first goes 5 km towards the east.

2. Then he turns left and travels in the north direction.

3. Then he turns right and travels in the east direction.

4. Then again he turns right and travels in the south direction.

5. He then turns left and travels in the east direction and after taking one more left he travels in the north direction.

6. He finally takes a left turn and travels in the west direction.

The least possible graphical representation of the given data is:

Point S is 2 km to the south of point O.

Given:

Left Side 2 4 5 6 7 9 10 13 16 18 19 21 24 25 28 29 30 34 37 39 41 49 55 Right Side

After deleting even numbers:

Left Side 5 7 9 13 19 21 25 29 37 39 41 49 55 Right Side

Numbers in decreasing order:

Left Side 55 49 41 39 37 29 25 21 19 13 9 7 5 Right Side

Thus, 21 will be 6^th from the right when arranged in decreasing order.

Given: Left Side 2 4 5 6 7 9 10 13 16 18 19 21 24 25 28 29 30 34 37 39 41 49 55 Right Side

After deleting prime numbers,

4 6 9 10 16 18 21 24 25 28 30 34 39 49 55 Right Side

The numbers that are to the left of 25 after deleting all prime numbers:

4 6 9 10 16 18 21 24 Right Side

There are such 8 elements.