Shortcut Trick
Sum of ages after increases = 44 + 4 + 2 = 50 years.
New ratio is 2 ∶ 3 → Total parts = 5.
5 units = 50 ⇒ 1 unit = 10.
New ages: Hrick = 2 × 10 = 20, Oindrila = 3 × 10 = 30.
Present ages: Hrick = 20 − 4 = 16, Oindrila = 30 − 2 = 28.
Original ratio = 16 ∶ 28 = 4 ∶ 7.
∴ The correct answer is 4 ∶ 7.
Alternate Method
Given: Sum of Present Ages = 44 years. New Ratio = 2 ∶ 3 after adding 4 and 2 years respectively.
Calculations:
⇒ Let Hrick's present age be H and Oindrila's be O.
⇒ H + O = 44 — (Equation 1)
⇒ (H + 4) ÷ (O + 2) = 2 ÷ 3
⇒ 3(H + 4) = 2(O + 2)
⇒ 3H + 12 = 2O + 4 ⇒ 3H − 2O = −8 — (Equation 2)
⇒ From (1), O = 44 − H. Substitute in (2):
⇒ 3H − 2(44 − H) = −8
⇒ 3H − 88 + 2H = −8 ⇒ 5H = 80 ⇒ H = 16
⇒ O = 44 − 16 = 28
⇒ Ratio x ∶ y = 16 ∶ 28 = 4 ∶ 7
∴ The correct answer is 4 ∶ 7.
Additional Information
Ratio and Sum Relation
If the sum of two quantities is S and their ratio is a ∶ b, then the quantities are [a ÷ (a+b)] × S and [b ÷ (a+b)] × S.
Age Problems Shift
When ages are increased or decreased, the sum of ages changes by the total number of years added to or subtracted from each individual.