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Question 251

Other Govt. Exams 2023• Numerical Aptitude

In each of the following number series, the wrong number is given, find out that number.

234, 230, 221, 196, 147, 114

  1. AOption (a)

    221

  2. BOption (b)

    147

  3. COption (c)

    114

  4. DOption (d)

    196

  5. EOption (e)

    230

View answer & explanation

Correct answer

Answer: (c)C.

114

Why this answer is correct

The series follows the following pattern:

234 - 22 = 230

230 - 32 = 221

221 - 52 = 196

196 - 72 = 147

147 - 112 = 26

∴ The wrong term in the series is 114.

Question 252

Other Govt. Exams 2023• Numerical Aptitude

In each of the following number series, the wrong number is given, find out that number.

49, 56, 77, 112, 151, 224

  1. AOption (a)

    224

  2. BOption (b)

    77

  3. COption (c)

    112

  4. DOption (d)

    151

  5. EOption (e)

    56

View answer & explanation

Correct answer

Answer: (d)D.

151

Why this answer is correct

The series follows the following pattern:

49 + 7 = 56

56 + 21 = 77

77 + 35 = 112 

112 + 49 = 161

161 + 63 = 224

∴ The wrong term in the series is 151.

Question 253

Other Govt. Exams 2023• Numerical Aptitude

In each of the following number series, a wrong number is given. Find out that number.

62, 98, 142, 194, 258, 322

  1. AOption (a)

    142

  2. BOption (b)

    322

  3. COption (c)

    194

  4. DOption (d)

    98

  5. EOption (e)

    258

View answer & explanation

Correct answer

Answer: (e)E.

258

Why this answer is correct

Given:

62, 98, 142, 194, 258, 322

Calculation:

The series follows the following pattern:

82 – 2 = 62

102 – 2 = 98

122 – 2 = 142

142 – 2 = 194  

162 – 2 = 254

182 – 2 = 322

∴ The wrong term in the series is 258.

Question 254

Other Govt. Exams 2023• Numerical Aptitude

What will come in the place of the question mark '?' in the following question?

 4 × ( ? + 120 ) = (8)3 + 640 ÷ 80 + 22

  1. AOption (a)

     12

  2. BOption (b)

     6

  3. COption (c)

     8

  4. DOption (d)

     16

  5. EOption (e)

     11

View answer & explanation

Correct answer

Answer: (e)E.

 11

Why this answer is correct

Given :

 4 × ( ? + 120 ) = 83 + 640÷ 80 + 22

 Calculation : 

  4 × ( ? + 120 ) = 83 + 640÷ 80 + 22

 ⇒ 4 × ( ? + 120 ) = 512 + 8 + 4

 ⇒ 4 × ( ? + 120 ) = 524 

 ⇒ ( ? + 120 ) = 524 /4

 ⇒ ( ? + 120 ) = 131

 ⇒ ? = 131 - 120

 ⇒ ? = 11

Hence,11 will  come in the place of '?'.

Question 255

Other Govt. Exams 2023• Numerical Aptitude

What will come in the place of the question mark '?' in the following question?

 133 ÷ 491/2× 20 + ? = 225001/2 + 310

  1. AOption (a)

     70

  2. BOption (b)

     60

  3. COption (c)

     90

  4. DOption (d)

     55

  5. EOption (e)

     80

View answer & explanation

Correct answer

Answer: (e)E.

 80

Why this answer is correct

Given :

 133 ÷ 491/2 × 20 + ? = 225001/2 + 310

 Calculation :

 133 ÷ 491/2 × 20 + ? = 225001/2 + 310

 ⇒ 133 ÷ (7)2×1/2× 20 + ? = (150)2×1/2 + 310

 ⇒ 133 ÷ 7 × 20 + ? = 150 + 310

 ⇒ 19 × 20 + ? = 460

 ⇒ ? = 460 - 380

 ⇒ ? = 80

 Hence,80 will come in the place of '?'.

Question 256

Other Govt. Exams 2023• Numerical Aptitude

What will come in the place of the question mark '?' in the following question?

 50% of 170 + 60% of 180 + 110 = ? + 10

  1. AOption (a)

     293

  2. BOption (b)

     273

  3. COption (c)

     313

  4. DOption (d)

     413

  5. EOption (e)

     253

View answer & explanation

Correct answer

Answer: (a)A.

 293

Why this answer is correct

Given :

 50% of 170 + 60% of 180 + 110 = ? + 10

 Calculation :

  50% of 170 + 60% of 180 + 110 = ? + 10

 ⇒ 85 + 108 + 110 = ? + 10

 ⇒ 193 + 110 = ? + 10

 ⇒ 303 + ? = 10

 ⇒ ? = 303  - 10

 ⇒ ? = 293

 Hence,293 will come in the place of '?'.

Question 257

Other Govt. Exams 2023• Numerical Aptitude

What will come in the place of the question mark ‘?’ in the following question?

1023 ÷ 31 + 12500 ÷ 5 - ? = 75% of 2500

  1. AOption (a)

    658

  2. BOption (b)

    601

  3. COption (c)

    500

  4. DOption (d)

    468

  5. EOption (e)

    397

View answer & explanation

Correct answer

Answer: (a)A.

658

Why this answer is correct

Given:

841 ÷ 29 + 650 ÷ 5 + ? = 35% of 1600

Concept Used: 

​

Calculation:

1023 ÷ 31 + 12500 ÷ 5 - ? = 75% of 2500

⇒ 33 + 2500 - ? = 75 × 25

⇒ ? = 2533 - 1875 

⇒ ? = 658

∴ The value of (?) is 658.

Question 258

Other Govt. Exams 2023• Numerical Aptitude

What should come in the place of '?' in the following question?

√729 × 6 + 15 × 50% of 450 - 366 ÷ 3 = ?

  1. AOption (a)

    2088

  2. BOption (b)

    3415

  3. COption (c)

    3375

  4. DOption (d)

    2812

  5. EOption (e)

    3130

View answer & explanation

Correct answer

Answer: (b)B.

3415

Why this answer is correct

Correct answer is: 2

Concept used:

The BODMAS rule should be followed to solve the question as per the given table;

Calculation:

√729 × 6 + 15 × 50% of 450 - 366 ÷ 3 = ?

⇒ 27 × 6 + 15 × 50/100 × 450 - 366 ÷ 3 = ?

⇒ 27 × 6 + 15 × 225 - 122 = ?

⇒ 162 + 3375 - 122 =?

⇒ 3537 - 122 = ?

⇒ ? = 3415

 

∴The value of ? is 3415

Question 259

Other Govt. Exams 2023• Numerical Aptitude

What will come in the place of the question mark ‘?’ in the following question?

(423−113)×(312−38)of25=?(4\frac{2}{3}-1\frac{{1}}{{3}}) \times( 3\frac{1}{2} -\frac{3}{8}) of \frac{2}{5}= ?

  1. AOption (a)

    256\frac{{25}}{{6}}

  2. BOption (b)

    253\frac{{25}}{{3}}

  3. COption (c)

    257\frac{{25}}{{7}}

  4. DOption (d)

    236\frac{{23}}{{6}}

  5. EOption (e)

    Answer not known

View answer & explanation

Correct answer

Answer: (a)A.

256\frac{{25}}{{6}}

Why this answer is correct

Concept Used: 

​

Calculation:

(423−113)×(312−38)of25=?(4\frac{2}{3}-1\frac{{1}}{{3}}) \times( 3\frac{1}{2} -\frac{3}{8}) of \frac{2}{5}= ?

⇒ (143−43)×(72−38)of25=?(\frac{14}{3}-\frac{{4}}{{3}}) \times( \frac{7}{2} -\frac{3}{8}) of \frac{2}{5}= ?

⇒ (14−43)×(28−38)of25=?(\frac{{14-4}}{{3}}) \times(\frac{28 -3}{8}) of \frac{2}{5}= ?

⇒ 103×258of25=?\frac{{10}}{{3}} \times\frac{25}{8} of \frac{2}{5}= ?

⇒ 103×54=?\frac{{10}}{{3}} \times\frac{5}{4}= ?

⇒ 256\frac{{25}}{{6}}

∴ The value of ? is 256\frac{{25}}{{6}}

Question 260

Other Govt. Exams 2023• Numerical Aptitude

What value can come in place of the 'x' in the question below?

1427\frac{2}{7} + 39 + 2657\frac{5}{7} - x\sqrt{x} = 4096\sqrt{4096}

  1. AOption (a)

    256

  2. BOption (b)

    196

  3. COption (c)

    216

  4. DOption (d)

    324

  5. EOption (e)

    184

View answer & explanation

Correct answer

Answer: (a)A.

256

Why this answer is correct

Given:

1427\frac{2}{7} + 39 + 2657\frac{5}{7} - x\sqrt{x} = 4096\sqrt{4096}

Calculation:

⇒ 1427\frac{2}{7} + 39 + 2657\frac{5}{7} - x\sqrt{x} = 4096\sqrt{4096}

⇒ (1427\frac{2}{7} + 2657\frac{5}{7}) + 39 - 4096\sqrt{4096} = x\sqrt{x}

⇒ [(14 + 26) + (27\frac{2}{7} + 57\frac{5}{7})] + 39 - 4096\sqrt{4096} = x\sqrt{x} 

⇒ 40 + 77\frac{7}{7} + 39 - 64 = x\sqrt{x}

⇒ 40 + 1 + 39 - 64 = x\sqrt{x}

⇒ x\sqrt{x} = 16

⇒ x = 162

⇒ x = 256

∴ The value of 'x' is 256.