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1. D lives immediately above the flat in which A lives in the same flat but not in flat Q.
2. There is two floors between the floor on which A and Z live.

    From this we get the following possibilities.

3. There is only one floor between the floors on which Z and B live.

    This implies B lives in flat Q on floor 2 in both the cases.

4. Y who lives on an even numbered floor lives above the floor on which C lives.
5. C lives below the floor on which X lives.

    From this we can say that Y lives in flat Q and flat P in case 1 and in case 2, respectively. Thus, C lives in flat Q on floor 1 in both the cases. X lives in either flat P or flat Q but lives on floor 3.

6. C and X live in the same flat but not with Z.   

    From this case 2 is eliminated as we cannot determine the flat in which X lives. Hence, in case 1 X lives in flat Q on floor 3. W lives in flat P on floor 3. From this we get the final arrangement as follows.

AFTER INTERCHANGING:

If W and B interchange their position, then D lives immediately below B.

Hence, D is the correct option.

1. D lives immediately above the flat in which A lives in the same flat but not in flat Q.
2. There is two floors between the floor on which A and Z live.

    From this we get the following possibilities.

3. There is only one floor between the floors on which Z and B live.

    This implies B lives in flat Q on floor 2 in both the cases.

4. Y who lives on an even numbered floor lives above the floor on which C lives.
5. C lives below the floor on which X lives.

    From this we can say that Y lives in flat Q and flat P in case 1 and in case 2, respectively. Thus, C lives in flat Q on floor 1 in both the cases. X lives in either flat P or flat Q but lives on floor 3.

6. C and X live in the same flat but not with Z.   

    From this case 2 is eliminated as we cannot determine the flat in which X lives. Hence, in case 1 X lives in flat Q on floor 3. W lives in flat P on floor 3. From this we get the final arrangement as follows.

Hence, D lives below the floor on which W lives is true.

Left side N T * I A ^ $ J # B * B U A R Q D & L O @ P T ! F Right side

So, in the above series only one symbol is immediately followed by a consonant and preceded by vowel i.e. O@P

Hence, one is the correct answer$

Left side N T * I A ^ $ J # B * B U A R Q D & L O @ P T ! F Right side

If all symbols are removed from the given series, we get

Left side N T I A J B B U A R Q D L O P T F Right side

Hence, 9^th from the right end is A

Hence, A is the correct answer$.

Left side N T * I A ^ $ J # B * B U A R Q D & L O @ P T ! F Right side

5^th to left + 7^th from the right = 12^th from the right i.e. A

Hence, A is the correct answer$.

Left side N T * I A ^ $ J # B * B U A R Q D &L O @ P T ! F Right side

There are two vowels which are immediately followed and immediately preceded by a letter i.e. I A ^ and L O @

Hence, two is the correct answer$.

Left side N T * I A ^ $ J # B * B U A R Q D & L O @ P T ! F Right side

If all symbols are replaced with a digit 5 then-new series is

N T 5 I A 5 5 J 5 B 5 B U A R Q D 5 L O 5 P T 5 F

Hence, there are six 5’s in the new series each of which is followed by a consonant.

Confusion Points There are eight symbol which changed to 5. After that condition is given that we have to make the pair of 5 - Consonant. so such type of Six pair are there$.

1) F is the third highest score in the group and has scored 56 marks. 

2)  D is the highest scorer in the group.

D > _____ > F (56) > _____ > _____ > _____

3) B scores the second highest mark. 

4) Marks of F is less than  D.

5) A scores fewer marks than C and E.

D > B > F (56) > C/E > C/E > A

Hence, B scores second highest in the group.

1) F is the third highest score in the group and has scored 56 marks. 

2)  D is the highest scorer in the group.

D > _____ > F (56) > _____ > _____ > _____

3) B scores the second highest mark. 

4) Marks of F is less than  D.

5) A scores fewer marks than C and E.

D > B > F (56) > C/E > C/E > A

Here either C or E is the second lowest scorer.

Hence, either option 1 or option 2 is the correct answer.

1) F is the third highest score in the group and has scored 56 marks. 

2)  D is the highest scorer in the group.

D > _____ > F (56) > _____ > _____ > _____

3) B scores the second highest mark. 

4) Marks of F is less than  D.

5) A scores fewer marks than C and E.

D > B > F (56) > C/E > C/E > A

Here either C or E is the second-lowest scorer.

If sum of F and B marks is 116 then marks of B = 116  - 56  = 60.

So the possible mark of D is 62

Hence, the Possible mark of D is 62.