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Question 331

LIC ADO 2019• Reasoning Ability and Numerical Ability

Direction: In the following questions, the symbols, ©, $, *, @ and % are used with the following meaning as illustrated below:

'A © B' means ‘A is either greater than or equal to B’

'A $ B' means ‘A is either smaller than or equal to B’

'A % B' means ‘A is neither greater then nor smaller than B’

'A * B' means ‘A is greater than B’

'A @ B' means ‘A is smaller than B’

Now in each of the following questions assuming the given statements to be True, find which of the conclusion/s given below them is/are definitely True?

Statements:       

L @ M, M % T, T @ O

Conclusions:    

 I. O $ M        

 II. T $ L

  1. AOption (a)

    Only I follows

  2. BOption (b)

    Only II follows

  3. COption (c)

    Either I or II follows

  4. DOption (d)

    Neither I nor II follows

  5. EOption (e)

    Both I and II follows

View answer & explanation

Correct answer

Answer: (d)D.

Neither I nor II follows

Why this answer is correct

According to the question

X is
Symbol©$%*@
Meaning≥≤=><
to Y

Given statement: L @ M, M % T, T @ O

On converting: L < M, M = T, T < O

On combining: L < M = T < O

Conclusions: 

I. T @ L → T < L → False (As, L < M = T < O → L < T)

II. O $ M → O ≤ M → False (As, L < M = T < O → O > M)

Hence, Neither I nor II follows**.**

Question 332

LIC ADO 2019• Reasoning Ability and Numerical Ability

Direction: In the following questions, the symbols, ©, $, *, @ and % are used with the following meaning as illustrated below:

'A © B' means ‘A is either greater than or equal to B’

'A $ B' means ‘A is either smaller than or equal to B’

'A % B' means ‘A is neither greater then nor smaller than B’

'A * B' means ‘A is greater than B’

'A @ B' means ‘A is smaller than B’

Now in each of the following questions assuming the given statements to be True, find which of the conclusion/s given below them is/are definitely True?

Statements:       

C % F, F @ G, G © M

Conclusions:  

I. M % F        

II. C @ G

  1. AOption (a)

    Only I follows

  2. BOption (b)

    Only II follows

  3. COption (c)

    Either I or II follows

  4. DOption (d)

    Neither I nor II follows

  5. EOption (e)

    Both I and II follows

View answer & explanation

Correct answer

Answer: (b)B.

Only II follows

Why this answer is correct

According to the question

X is
Symbol©$%*@
Meaning≥≤=><
to Y

Statements:       

C % F, F @ G, G © M

Conclusions:  

I. M % F        

II. C @ G

Given statement: C % F, F @ G, G © M

On converting: C = F, F < G, G ≥ M

On combining: C = F < G ≥ M

Conclusions: 

I. M % F → M = F → False (As, C = F < G ≥ M → clear relation between M and F can’t be determined)

II. C @ G → C < G → True (As, C = F < G → C < G)

Hence, only II follows.$

Question 333

LIC ADO 2019• Reasoning Ability and Numerical Ability

The given pie chart shows the percentage distribution of the total number of 12th students passed (science and commerce) in five different zone i.e. east zone, west zone, central zone, north zone and south zone and the table chart shows the number of 12th students passed from science department in five different zones.

The total number of students 12th passed = 5000

 

ZoneThe number of 12th students passed from science department
East600
West250
Central700
North850
South550

The number of 12th students passed from science department in central and south zones together is what percentage more/less than the total number of the 12th students passed in east zone?

  1. AOption (a)

    15% less

  2. BOption (b)

    20% more

  3. COption (c)

    25% more

  4. DOption (d)

    15% more

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

25% more

Why this answer is correct

Calculation:

The number of 12th students passed from science department in central zone = 700

The number of 12th students passed from science department in south zone = 550

Total number of 12th students passed from science department = (700 + 550)

⇒ 1250

Total number of 12th passed students in east zone = (5000 × 20/100)

⇒ 1000

Now,

Required percentage of passed students from science department in central and south zone to total number of students in east zone = [(1250 – 1000)/1000 × 100]

⇒ (250/1000 × 100)

⇒ 25%

∴ Required percentage is 25% more.

Question 334

LIC ADO 2019• Reasoning Ability and Numerical Ability

The given pie chart shows the percentage distribution of the total number of 12th students passed (science and commerce) in five different zone i.e. east zone, west zone, central zone, north zone and south zone and the table chart shows the number of 12th students passed from science department in five different zones.

The total number of students 12th passed = 5000

 

ZoneThe number of 12th students passed from science department
East600
West250
Central700
North850
South550

Out of the total number of 12th students passed from commerce department in west and south zones, 5/6th of the students are girls and the remaining are boys, then find the number of 12th boys passed from commerce department in west and south zones?

  1. AOption (a)

    90

  2. BOption (b)

    75

  3. COption (c)

    100

  4. DOption (d)

    106

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

75

Why this answer is correct

Calculation:

Total number of 12th students passed in west zone = (5000 × 10/100)

⇒ 500

Number of 12th students passed from commerce department in west zone = (500 – 250)

⇒ 250

Total number of 12th students passed in south zone = (5000 × 15/100)

⇒ 750

Number of 12th students passed from commerce department in south zone = (750 –  550)

⇒ 200

Total number of 12th passed from commerce department in west and south zone = (250 + 200)

⇒ 450

Now,

5/6th of the students of commerce department are girls in west and south zones = (450 × 5/6)

⇒ 375

Number of 12th boys passed from commerce department in west and south zones together = (450 – 375)

⇒ 75

∴ Required number of 12th passed boys is 75

Question 335

LIC ADO 2019• Reasoning Ability and Numerical Ability

The given pie chart shows the percentage distribution of the total number of 12th students passed (science and commerce) in five different zone i.e. east zone, west zone, central zone, north zone and south zone and the table chart shows the number of 12th students passed from science department in five different zones.

The total number of students 12th passed = 5000

 

ZoneThe number of 12th students passed from science department
East600
West250
Central700
North850
South550

Find the difference between the total number of 12th students passed from science department in east and west zones together and the number of 12th students passed from commerce department in central zone?

  1. AOption (a)

    295

  2. BOption (b)

    300

  3. COption (c)

    305

  4. DOption (d)

    350

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

300

Why this answer is correct

Calculation:

The number of 12th students passed from science department in east zone = 600

The number of 12th students passed from science department in west zone = 250

Total number of 12th students passed from science department in east and west zones = (600 + 250)

⇒ 850

Total number of 12th passed students in central zone = (5000 × 25/100)

⇒ 1250

The number of 12th passed students from commerce department in central zone = (1250 – 700)

⇒ 550

Now,

The difference between the total number of 12th students passed from science department in east and west zones together and the number of 12th students passed from commerce department in central zone = (850 – 550)

⇒ 300

∴ Required difference is 300

Question 336

LIC ADO 2019• Reasoning Ability and Numerical Ability

The given pie chart shows the percentage distribution of the total number of 12th students passed (science and commerce) in five different zone i.e. east zone, west zone, central zone, north zone and south zone and the table chart shows the number of 12th students passed from science department in five different zones.

The total number of students 12th passed = 5000

 

ZoneThe number of 12th students passed from science department
East600
West250
Central700
North850
South550

If the number of 12th students passed from commerce and art department in north zone is three times the number of 12th students passed from science department in north zones, then the number of 12th students passed from art department from north zone is what percentage of the total number of 12th students including art department passed in north zone?

  1. AOption (a)

    52.15%

  2. BOption (b)

    54.90%

  3. COption (c)

    55.88%

  4. DOption (d)

    55%

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

55.88%

Why this answer is correct

Calculation:

Let the number of art students be x

Then,

Total number of 12th students passed in north zone = (5000 × 30/100)

⇒ 1500

The number of 12th students passed from commerce department = (1500 – 850)

⇒ 650

The number of 12th students passed from science department in north zone = 850

According to the question

⇒ 650 + x = 3 × 850

⇒ 650 + x = 2550

⇒ x = (2550 – 650)

⇒ x = 1900

Now,

Total number of 12th students passed in north zone = (1500 + 1900)

⇒ 3400

Required percentage = (1900/3400 × 100)

⇒ 55.88%

∴ The number of 12th students passed from art department from north zone to the total number of 12th students passed in north zone is 55.88%

Question 337

LIC ADO 2019• Reasoning Ability and Numerical Ability

The given pie chart shows the percentage distribution of the total number of 12th students passed (science and commerce) in five different zone i.e. east zone, west zone, central zone, north zone and south zone and the table chart shows the number of 12th students passed from science department in five different zones.

The total number of students 12th passed = 5000

 

ZoneThe number of 12th students passed from science department
East600
West250
Central700
North850
South550

Find the ratio of the total number of 12th students passed in west zone and the average number of 12th students passed from commerce department in east and west zones?

  1. AOption (a)

    20 : 13

  2. BOption (b)

    13 : 20

  3. COption (c)

    11 : 15

  4. DOption (d)

    3 : 5

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

20 : 13

Why this answer is correct

Calculation:

The total number of 12th students passed in west zone = (5000 × 10/100)

⇒ 500

The number of 12th students passed from commerce department in west zone = (500 – 250)

⇒ 250

The total number of 12th students passed in east zone = (5000 × 20/100)

⇒ 1000

The number of 12th students passed in commerce department in east zone = (1000 – 600)

⇒ 400

The total number of 12th students passed from commerce department in east and west zones = (400 + 250)

⇒ 650

The average number of 12th students passed from commerce department in east and west zones = (650/2)

⇒ 325

Required ratio = (500 : 325)

⇒ 20 : 13

∴ The ratio of the total number of 12th students passed in west zone and the average number of 12th students passed from commerce department in east and west zones is 20 : 13

Question 338

LIC ADO 2019• Reasoning Ability and Numerical Ability

What approximate value should come in place of the question mark (?) in the following question?

269.67 + 362.87 – 45.40 = (1281.20 – 84.80) ÷ ?

  1. AOption (a)

    4

  2. BOption (b)

    5

  3. COption (c)

    1

  4. DOption (d)

    2

  5. EOption (e)

    7

View answer & explanation

Correct answer

Answer: (d)D.

2

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given Expression,

269.67 + 362.87 – 45.40 = (1281.20 – 84.80) ÷ ?

We can also write values as:

269.67 ≈ 270, 362.87 ≈ 363, 45.40 ≈ 45, 1281.20 ≈ 1281, 84.80 ≈ 85

Given expression becomes,

⇒ 270 + 363 – 45 = (1281 – 85) ÷ ?

⇒ 270 + 363 – 45 = 1196 ÷ ?

⇒ 633 – 45 = 1196 ÷ ?

⇒ 588 = 1196 ÷ ?

⇒ ? = 1196/588

⇒ ? ≈ 2

Question 339

LIC ADO 2019• Reasoning Ability and Numerical Ability

What approximate value should come in place of the question mark (?) in the following question?

(5899.10 – 288.70) ÷ 29.96 = 12.81 × 11.80 + ?

  1. AOption (a)

    28

  2. BOption (b)

    40

  3. COption (c)

    45

  4. DOption (d)

    31

  5. EOption (e)

    25

View answer & explanation

Correct answer

Answer: (d)D.

31

Why this answer is correct

Rules of Approximation:

  1. If a number has digits to the right of the decimal less than 5, then just drop the digits to the right of the decimal. The number so obtained will be the approximated value.
  2. If a number has digits to the right of the decimal more than 5, then just drop the digits to the right of the decimal and raise the remaining number by '1'.The number so obtained will be the approximated value.

Concept:

Follow BODMAS rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given Expression,

(5899.10 – 288.70) ÷ 29.96 = 12.81 × 11.80 + ?

We can also write values as:

5899.10 ≈ 5899, 288.70 ≈ 289, 29.96 ≈ 30, 12.81 ≈ 13, 11.80 ≈ 12

Calculation:

Given expression becomes,

⇒ (5899 – 289) ÷ 30 = 13 × 12 + ?

⇒ 5610 ÷ 30 = 13 × 12 + ?

⇒ 187 = 13 × 12 + ?

⇒ 187 = 156 + ?

⇒ ? ≈ 31

Question 340

LIC ADO 2019• Reasoning Ability and Numerical Ability

What approximate value should come in place of the question mark (?) in the following question?

(90.1 + 181.89) ÷ 4.10 + 262.30 = ? % of 8250.054

  1. AOption (a)

    11

  2. BOption (b)

    4

  3. COption (c)

    9

  4. DOption (d)

    10

  5. EOption (e)

    8

View answer & explanation

Correct answer

Answer: (b)B.

4

Why this answer is correct

Rules of Approximation:

  1. If a number has digits to the right of the decimal less than 5, then just drop the digits to the right of the decimal. The number so obtained will be the approximated value.
  2. If a number has digits to the right of the decimal more than 5, then just drop the digits to the right of the decimal and raise the remaining number by '1'.The number so obtained will be the approximated value.

Concept:

Follow BODMAS rule to solve this question, as per the order is given below:

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

(90.1 + 181.189) ÷ 4.10 + 262.30 = ? % of 8250.054

We can also write values as:

90.1 ≈ 90, 181.89 ≈ 182, 4.10 ≈ 4, 262.30 ≈ 262, 8250.054 ≈ 8250

Calculation:

Given expression becomes,

⇒ (90 + 182) ÷ 4 + 262 = ? % of 8250

⇒ 272 ÷ 4 + 262 = ?% of 8250

⇒ 68 + 262 = ?% of 8250

⇒ 330 = ?% of 8250

⇒ 330/8250 = ?/100

⇒ 33/825 = ?/100

⇒ 3/75 = ?/100

⇒ 1/25 = ?/100

⇒ 100/25 = ?

⇒ ? ≈ 4