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Question 131

LIC ADO 2022• Quantitative Aptitude

The table given below shows the distribution of male adults out of total adults (male and female) and the percentage distribution of children out of total adult in four cities. The total number of male adults in four cities is 2700.

Male AdultsPercentage of children out of total adult
A40p15%
B30p10%
C20p12%
D18p18%

Note: The ratio of male to female adults in city B, C and D is 5:3, 5:6 and 9:11 respectively.

If the number of female adults in city A is 250 more than the number of male adults in city D, then find the total number of female adults in city A, B and D together. 

  1. AOption (a)

    2000

  2. BOption (b)

    1100

  3. COption (c)

    1700

  4. DOption (d)

    1600

  5. EOption (e)

    1500

View answer & explanation

Correct answer

Answer: (c)C.

1700

Why this answer is correct

The total number of male adults in four cities = 2700

⇒ 40p + 30p + 20p + 18p = 2700

⇒ 108p = 2700

⇒ p = 25

The ratio of male to female adults in city B, C and D is 5:3, 5:6 and 9:11 respectively

Male AdultsFemale AdultsTotal Adultsof children out of total adult
A40p = 40 × 25 = 1000
B30p = 30 × 25 = 750(750/5) × 3 = 450750 + 450 = 120010% of 1200 = 120
C20p = 20 × 25 = 500(500/5) × 6 = 600500 + 600 = 110012% of 1100 = 132
D18p = 18 × 25 = 450(450/9) × 11 = 550450 + 550 = 100018% of 1000 = 180
Total2700

 

The number of female adults in city A = 450 + 250 = 700

The total number of female adults in city A, B and D together = 700 + 450 + 550 

⇒ 1700

Question 132

LIC ADO 2022• Quantitative Aptitude

The table given below shows the distribution of male adults out of total adults (male and female) and the percentage distribution of children out of total adult in four cities. The total number of male adults in four cities is 2700.

Male AdultsPercentage of children out of total adult
A40p15%
B30p10%
C20p12%
D18p18%

Note: The ratio of male to female adults in city B, C and D is 5:3, 5:6 and 9:11 respectively.

The total number of children in city B is what percentage of the total number of children in city D?

  1. AOption (a)

    35%

  2. BOption (b)

    66.66%

  3. COption (c)

    40%

  4. DOption (d)

    50%

  5. EOption (e)

    55%

View answer & explanation

Correct answer

Answer: (b)B.

66.66%

Why this answer is correct

The total number of male adults in four cities = 2700

⇒ 40p + 30p + 20p + 18p = 2700

⇒ 108p = 2700

⇒ p = 25

The ratio of male to female adults in city B, C and D is 5:3, 5:6 and 9:11 respectively

Male AdultsFemale AdultsTotal Adultsof children out of total adult
A40p = 40 × 25 = 1000
B30p = 30 × 25 = 750(750/5) × 3 = 450750 + 450 = 120010% of 1200 = 120
C20p = 20 × 25 = 500(500/5) × 6 = 600500 + 600 = 110012% of 1100 = 132
D18p = 18 × 25 = 450(450/9) × 11 = 550450 + 550 = 100018% of 1000 = 180
Total2700

Required % = (120/180) × 100 

⇒ 66.66%

Question 133

LIC ADO 2022• Quantitative Aptitude

The table given below shows the distribution of male adults out of total adults (male and female) and the percentage distribution of children out of total adult in four cities. The total number of male adults in four cities is 2700.

Male AdultsPercentage of children out of total adult
A40p15%
B30p10%
C20p12%
D18p18%

Note: The ratio of male to female adults in city B, C and D is 5:3, 5:6 and 9:11 respectively.

The total number of children in city B and C together is what percentage of the number of male adults in city C?

  1. AOption (a)

    25.5% 

  2. BOption (b)

    22.6% 

  3. COption (c)

    54.5% 

  4. DOption (d)

    50.4% 

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

50.4% 

Why this answer is correct

The total number of male adults in four cities = 2700

⇒ 40p + 30p + 20p + 18p = 2700

⇒ 108p = 2700

⇒ p = 25

The ratio of male to female adults in cities B, C, and D is 5:3, 5:6, and 9:11 respectively

Male AdultsFemale AdultsTotal Adultschildren out of total adult
A40p = 40 × 25 = 1000
B30p = 30 × 25 = 750(750/5) × 3 = 450750 + 450 = 120010% of 1200 = 120
C20p = 20 × 25 = 500(500/5) × 6 = 600500 + 600 = 110012% of 1100 = 132
D18p = 18 × 25 = 450(450/9) × 11 = 550450 + 550 = 100018% of 1000 = 180
Total2700

The total number of children in city B and C together = 120 + 132 = 252

Male adults in city C = 500

Required % = (252/500) × 100 

⇒ 50.4%

Question 134

LIC ADO 2022• Quantitative Aptitude

The table given below shows the distribution of male adults out of total adults (male and female) and the percentage distribution of children out of total adult in four cities. The total number of male adults in four cities is 2700.

Male AdultsPercentage of children out of total adult
A40p15%
B30p10%
C20p12%
D18p18%

Note: The ratio of male to female adults in city B, C and D is 5:3, 5:6 and 9:11 respectively.

If the ratio of male adults to female adults in city A is 10:7, then find the ratio of the total female adults in all four cities and the male adults of cities A and B together.

  1. AOption (a)

    40:31

  2. BOption (b)

    35:46

  3. COption (c)

    51:37

  4. DOption (d)

    47:36

  5. EOption (e)

    46:35

View answer & explanation

Correct answer

Answer: (e)E.

46:35

Why this answer is correct

The total number of male adults in four cities = 2700

⇒ 40p + 30p + 20p + 18p = 2700

⇒ 108p = 2700

⇒ p = 25

The ratio of male to female adults in city B, C and D is 5:3, 5:6 and 9:11 respectively

Male AdultsFemale AdultsTotal Adultsof children out of total adult
A40p = 40 × 25 = 1000
B30p = 30 × 25 = 750(750/5) × 3 = 450750 + 450 = 120010% of 1200 = 120
C20p = 20 × 25 = 500(500/5) × 6 = 600500 + 600 = 110012% of 1100 = 132
D18p = 18 × 25 = 450(450/9) × 11 = 550450 + 550 = 100018% of 1000 = 180
Total2700

 

Given that, the ratio of male adults to female adults in city A = 10 : 7

The number of female adults in city A = (1000/10) × 7 = 700

Required ratio = (700 + 450 + 600 + 550) : (1000 + 750)

⇒ 2300 : 1750

⇒ 46:35

Question 135

LIC ADO 2022• Quantitative Aptitude

The table given below shows the distribution of male adults out of total adults (male and female) and the percentage distribution of children out of total adult in four cities. The total number of male adults in four cities is 2700.

Male AdultsPercentage of children out of total adult
A40p15%
B30p10%
C20p12%
D18p18%

Note: The ratio of male to female adults in city B, C and D is 5:3, 5:6 and 9:11 respectively.

The number of female adults in city B is what percentage of the total number of adults in city D?

  1. AOption (a)

    45%

  2. BOption (b)

    35%

  3. COption (c)

    25%

  4. DOption (d)

    55%

  5. EOption (e)

    60%

View answer & explanation

Correct answer

Answer: (a)A.

45%

Why this answer is correct

The total number of male adults in four cities = 2700

⇒ 40p + 30p + 20p + 18p = 2700

⇒ 108p = 2700

⇒ p = 25

The ratio of male to female adults in city B, C and D is 5:3, 5:6 and 9:11 respectively

Male AdultsFemale AdultsTotal Adultsof children out of total adult
A40p = 40 × 25 = 1000
B30p = 30 × 25 = 750(750/5) × 3 = 450750 + 450 = 120010% of 1200 = 120
C20p = 20 × 25 = 500(500/5) × 6 = 600500 + 600 = 110012% of 1100 = 132
D18p = 18 × 25 = 450(450/9) × 11 = 550450 + 550 = 100018% of 1000 = 180
Total2700

Required % = (Female adults in city B/total number of adults in city D) × 100

⇒ (450/1000) × 100

⇒ 45%

Question 136

LIC ADO 2022• Quantitative Aptitude

What approximate value should come in the place of question mark (?) in the following question?

19.99% of 119.99 + ∛216.06 – √624.99 = ?

  1. AOption (a)

    3

  2. BOption (b)

    15

  3. COption (c)

    12

  4. DOption (d)

    5

  5. EOption (e)

    10

View answer & explanation

Correct answer

Answer: (d)D.

5

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below,

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and follow BODMAS rule in the bracket,

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step - 4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Since, we need to find out the approximate value,

So, we can write these values to their nearest integers.

Given expression is

19.99% of 119.99 + ∛216.06 – √624.99 = ?

20% of 120 + ∛216 – √625 = ?

⇒ 24 + 6 – 25 = ?

⇒ 30 – 25 = ?

⇒ ? = 5

Question 137

LIC ADO 2022• Quantitative Aptitude

What approximate value should come in place of the question mark (?) in the following question?

(√63.99) × 149.99% – 175.99 ÷ 22.22 = ?

  1. AOption (a)

    4

  2. BOption (b)

    6

  3. COption (c)

    2

  4. DOption (d)

    8

  5. EOption (e)

    12

View answer & explanation

Correct answer

Answer: (a)A.

4

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order is given below:

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

(√63.99) × 149.99% – 175.99 ÷ 22.22 = ?

(√64) × 150% – 176 ÷ 22 = ?

⇒ 8 × 1.5 - 8 = ?

⇒ 12 - 8 = ?

⇒ 4 = ?

Question 138

LIC ADO 2022• Quantitative Aptitude

What approximate value should come in place of the question mark (?) in the following question?

(76.87 × 10.99 ÷ 6.97 + 1.99) ÷ ∛26.99 = ?

  1. AOption (a)

    35

  2. BOption (b)

    39

  3. COption (c)

    41

  4. DOption (d)

    53

  5. EOption (e)

    49

View answer & explanation

Correct answer

Answer: (c)C.

41

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order is given below:

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

(76.87 × 10.99 ÷ 6.97 + 1.99) ÷ ∛26.99 = ?

(77 × 11 ÷ 7 + 2) ÷ ∛27 = ?

⇒ ? = (121 + 2) ÷ 3

⇒ ? = 123/3

⇒ ? = 41

Question 139

LIC ADO 2022• Quantitative Aptitude

What approximate value should come in place of the question mark (?) in the following question?

49.827% of 1119.61 - ?% of 1600.092 = 79.762

  1. AOption (a)

    20

  2. BOption (b)

    25

  3. COption (c)

    32

  4. DOption (d)

    30

  5. EOption (e)

    24

View answer & explanation

Correct answer

Answer: (d)D.

30

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order is given below:

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

49.827% of 1119.61 - ?% of 1600.092 = 79.762

⇒ 50% of 1120 - ?% of 1600 = 80

⇒ 560 - 16 × ? = 80

⇒ 560 - 80 = 16 × ?

⇒ 480 = 16 × ?

⇒ ? = 480/16

∴ ? = 30

Question 140

LIC ADO 2022• Quantitative Aptitude

What approximate value should come in the place of question mark (?) in the following question

(34.85)2 - (18.99)2 - (5.01)3 = ?

  1. AOption (a)

    739

  2. BOption (b)

    673

  3. COption (c)

    591

  4. DOption (d)

    807

  5. EOption (e)

    617

View answer & explanation

Correct answer

Answer: (a)A.

739

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below,

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and follow BODMAS rule in the bracket,

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step - 4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Since, we need to find out the approximate value,

So, we can write these values to their nearest integers.

Given expression is

 (34.85)2 - (18.99)2 - (5.01)3 = ?

⇒ ? ≈ (35)2 - (19)2 - (5)3

⇒ ? = 1225 - 361 - 125

⇒ ? = 739

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