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Question 111

KVS TGT 2023• Subject Specific

If the Hydrocarbon C2H4 is burned in Oxygen gas, Carbon dioxide and water are formed, as described by the unbalanced chemical equation

C2H4 + O2 → CO2 + H2O

When the equation is balanced properly, we predict that one mole of C2H4 will :

  1. AOption (a)

    react with one mole of O2

  2. BOption (b)

    form two moles of CO2

  3. COption (c)

    form three moles of water

  4. DOption (d)

    react with four moles of O2

View answer & explanation

Correct answer

Answer: (b)B.

form two moles of CO2

Why this answer is correct

Correct answer: 2)

Concept:

  • When ethene is burnt in excess of oxygen it gives carbon dioxide and water.
  • This reaction is an exothermic reaction and produces heat.

Explanation:

First, we will balance the Carbon atoms.

After balancing the equation becomes: 

C2H4+O2→2CO2+H2O

Then the Hydrogen atoms are balanced.

After balancing the equation becomes: C2H4+O2→2CO2+2H2O

Finally, Oxygen atoms are balanced.

After balancing the equation becomes:

C2H4 + 3O2→2CO2+2H2O

So, one mole of C2H4 will form two moles of CO2.

Conclusion:

Thus, one mole of C2H4 will form two moles of CO2

Question 112

KVS TGT 2023• Subject Specific

The minimum volume of a block of wood (density = 800 kg/m³), if it is to hold a 50 kg person entirely above the water when he stands on it will be: (density of water 1000 kg/m³)

  1. AOption (a)

    0.25 m3​

  2. BOption (b)

    0.8 m3​

  3. COption (c)

    1.18 m3​

  4. DOption (d)

    1.25 m3​

View answer & explanation

Correct answer

Answer: (a)A.

0.25 m3​

Why this answer is correct

CONCEPT:

Buoyancy and Archimedes’ Principle

  • To float, the weight of the object + person must equal the weight of the water displaced.
  • Archimedes’ Principle:

Buoyant force = weight of displaced water = ρwater × Vdisplaced × g

  • Total weight acting downward = weight of person + weight of wooden block
  • We assume the entire block is submerged when the person stands on it to keep both entirely above water.

EXPLANATION:

  • Let V be the volume of the wooden block.
  • Mass of block = ρblock × V = 800 × V (in kg)
  • Total downward force (weight) =
  • Weight of person = 50 × g
  • Weight of block = (800 × V) × g
  • Total = (800V + 50) × g
  • Buoyant force = ρwater × V × g = 1000 × V × g
  • Equating both (for equilibrium):
  • Cancel g on both sides:
  • Simplifying: 1000V - 800V = 50 ⇒ 200V = 50 ⇒ V = 0.25 m³

Therefore, the correct answer is Option 1) 0.25 m³.

Question 113

KVS TGT 2023• Subject Specific

Which one of the following expressions correctly gives the Ohm's law for a conductor? (Symbols have their usual meanings)

  1. AOption (a)

    \(V={I\over R}\)

  2. BOption (b)

    \(V={R\over I}\)

  3. COption (c)

    V = I2 R

  4. DOption (d)

    V = I R

View answer & explanation

Correct answer

Answer: (d)D.

V = I R

Why this answer is correct

Ohm’s law:

At constant temperature, the current flowing through a resistance is directly proportional to the potential difference across its end.

I ∝ V

\(I=\frac{1}{R}\times V\)

V = I R 

Where V = the potential difference, R = resistance, and I = current flowing.

Ohmic resistance: The resistance that follows ohm’s law is called ohmic resistance.

Additional Information All resistances don’t follow ohm’s law.

Limitations of Ohm’s law

1.    For applying Ohm’s law. the physical conditions such as temperature, dimensions and the connections of the wire or branch or circuit must remain constant. 2.    It is applicable only for liner and bilateral elements or circuits. It is not applicable for non-linear and unilateral elements and circuits such as diodes, Zener diode, rectifiers, voltages regulators etc. 3.    It is unsuitable for non-metallic conductors such as silicon carbide. 4.    The complicated network cannot be solved quickly by this law.

Question 114

KVS TGT 2023• Subject Specific

The potential difference required to pass 4A current through a 24 Ω resistor will be :

  1. AOption (a)

    96 V

  2. BOption (b)

    48 V

  3. COption (c)

    6 V

  4. DOption (d)

    1.5 V

View answer & explanation

Correct answer

Answer: (a)A.

96 V

Why this answer is correct

The correct answer is 96 V

Given:

Resistance(R)= 24 Ω= 24 Ω.

Current (I) = 4 A.

Potential difference(V) = ?

Calculation:

Using Ohm's law

\(V=IR\)

Substitute the above values:

V = 4×24

Potential difference(V) = 96 V.

Question 115

KVS TGT 2023• Subject Specific

A current of 2.0 A flows down a straight metal rod that has a 0.20 cm diameter. The rod is 2.0 m long, and the potential difference between its ends is 40 V. The resistivity of the material of the rod will be :

  1. AOption (a)

    125.6 μΩ m

  2. BOption (b)

    62.8 μΩ m

  3. COption (c)

    31.4 μΩ m

  4. DOption (d)

    15.7 μΩ m

View answer & explanation

Correct answer

Answer: (c)C.

31.4 μΩ m

Why this answer is correct

Concept:

A material's electrical resistivity is a measure of how strongly it opposes the flow of current. The ohm meter (m) is the SI unit of electrical resistivity.

Calculation:

Given:

I = 2A

d = 0.2 cm   = 0.002 m

∴ r =  0.001 m

L = 2.0 m

V = 40 v

We know that,

Cross-section Area (A) =  πr2

= 3.141 × 0.0012

= 0.003141 m2                                    

Resistance (R) = \({V \over I}\)

= 20 ohm

Now,

The resistivity of material ( ρ ) = \({RA \over L}\)

= \({20 \times 0.003141 \over 2}\)

=  0.03141 ohm - m

The correct answer is option (3).

Question 116

KVS TGT 2023• Subject Specific

A 90 cm long copper tube has an inner diameter of 0.8 cm and an outer diameter of 1.0 cm. The electric resistance of the tube when used lengthwise will be :

(Take resistivity of copper 1.57×10-8 Ω m)

  1. AOption (a)

    109.7 μΩ

  2. BOption (b)

    180 μΩ

  3. COption (c)

    281.3 μΩ

  4. DOption (d)

    500 μΩ

View answer & explanation

Correct answer

Answer: (d)D.

500 μΩ

Why this answer is correct

Concept:

Calculation:

Given, length l = 90 cm

= 90 × 0.01 m

= 0.9 m

Specific resistance ρ =  1.57×10-8 Ω−m

External diameter D1 = 1.0 × 10−2 m

Internal diameter D2 = 0.8 × 10−2 m

As the resistance of tube R = \({\rho l \over A}\)

R= \({\rho l \over\frac{\pi}{4} [D^2_1 - D^2_2]}\)

= \({}\)({4 × 1.57×10^{-8} × 0.9 \over\frac{22}{7} (1.0^2 - 0.8^2) × 10^{-4} }\)

= \({}\)({7 × 4 × 1.57×10^{-8} × 0.9 \over 22 (1.0^2 - 0.8^2) × 10^{-4} }\)

= \({}\)(39.564×10^{-8} \over 7.92 × 10^{-4} \)

= 4.99 × 10(- 4) ≈ 500 × 10(-6)

= 500 μΩ

The correct answer is option (4).

Question 117

KVS TGT 2023• Subject Specific

The resistance between points A and B is :

  1. AOption (a)

    2.9 Ω 

  2. BOption (b)

    7.5 Ω

  3. COption (c)

    15 Ω

  4. DOption (d)

    18.6 Ω

View answer & explanation

Correct answer

Answer: (b)B.

7.5 Ω

Why this answer is correct

Concept:

  • Resistance - is the opposition offer in the flow of current. It's Unit is ohm(Ω )

  • Resistances in series:

  • When two or more resistances are connected one after another, the same current flows through them are called resistances in series.

  • The net resistance/equivalent resistance (R) of resistances in series is given by:

  • Equivalent resistance,

  • ​

⇒ R = R1 + R2

  • Resistances in parallel:

  • When the terminals of two or more resistances are connected at the same two points and the potential difference across them is equal is called resistances in parallel.

  • The net resistance/equivalent resistance(R) of resistances in parallel is given by\(⇒ R = \frac{R_1R_2}{R_1+R_2}\)

 

Calculation:

R1 = 6 Ω  , R2 = 9 Ω  are in series

⇒ R1 + R2 = 15 Ω 

R1 and R2 collectively are in parallel with R3 = 15 Ω.

⇒ \(\frac{1}{R1+R2} + \frac{1}{15}\) = \(\frac{2}{15}\) 

⇒ 7.5 Ω 

∴ **The correct option is 2)**R=1R1+1R2+.....Unknown node type: spanUnknown node type: span

Question 118

KVS TGT 2023• Subject Specific

The value of resistor R in order to have current I equals to 0.45 A, will be :

  1. AOption (a)

    150 Ω 

  2. BOption (b)

    200 Ω

  3. COption (c)

    250 Ω

  4. DOption (d)

    300 Ω

View answer & explanation

Correct answer

Answer: (a)A.

150 Ω 

Why this answer is correct

Concept :

Resistance - is the opposition offered in the flow of current. It's Unit is ohm (Ω )

Ohm's Law - states that current through two points in a conductor is directly proportional to the voltage across two points.

 \(V = \frac{I}{R}\)

There are mainly two ways of the combination of resistances:

  1. Resistances in series:
  • When two or more resistances are connected one after another, the same current flows through them are called resistances in series.
  • The net resistance/equivalent resistance (R) of resistances in series is given by:
  • Equivalent resistance,

​

⇒ R = R1 + R2

  1. Resistances in parallel:
  • When the terminals of two or more resistances are connected at the same two points and the potential difference across them is equal is called resistances in parallel.
  • The net resistance/equivalent resistance(R) of resistances in parallel is given by:

\(⇒ R = \frac{R_1R_2}{R_1+R_2}\)

 

Calculation:

We know that 

V = I eq

⇒ Req = V/I

⇒ Req = \(\frac{45}{0.45}\) = 100 Ω 

⇒\(\frac{1}{100}\)  =  \(\frac{1}{300}+\frac{1}{R2}\) 

⇒ R2 = 150 Ω 

∴ The correct answer is option 1).

Question 119

KVS TGT 2023• Subject Specific

A He2+ ion travels at right angles to a magnetic field of 0.80 T with a velocity of 105 m/s. The magnitude of the magnetic force on the ion will be : (electron charge = 1.6 × 10-19 C)

  1. AOption (a)

    0.64×10-14 N

  2. BOption (b)

    1.28×10-14 N

  3. COption (c)

    2.56×10-14 N

  4. DOption (d)

    5.12×10-14 N

View answer & explanation

Correct answer

Answer: (c)C.

2.56×10-14 N

Why this answer is correct

Concept:

  • Magnetic field intensity -  is a measure of how strong or weak any magnetic field is.
  • The SI unit of B is Ns/(Cm) = Tesla (T)
  • Lorentz Force -  The force a magnetic field exerted on a charge q moving with velocity v is called magnetic Lorentz force and it is represented by

​FB = qvBSinθ.

 

Given: 

Magnetic field intensity(B)= 0.80T

Particle = He2+ 

Angle of interaction(θ) = 90º 

Charge on particle(q) = 1.6× 10-19

Velocity of particle(v)= 105 m/s

∵ FB = qvBSinθ 

⇒ FB = qvBSin90º

⇒ FB = 2× 1.6× 10-19 × 105 × 0.80× 1

⇒ FB = 2.56 × 10-14 N

∵ Option 3) is the right option.

Question 120

KVS TGT 2023• Subject Specific

How many grams of SbF3 are needed to produce one gram of Freon-12(CCl2F2), according to the reaction represented by this equation?

2CCl4 + 2SbF3  → 3CCl2F2 + 2SbCl3

SubstanceMolar Mass
SbF3179 g mol-1
CCl2F2121 g mol-1
  1. AOption (a)

    0.667 g

  2. BOption (b)

    0.986 g

  3. COption (c)

    1.50 g

  4. DOption (d)

    2.22 g

View answer & explanation

Correct answer

Answer: (b)B.

0.986 g

Why this answer is correct

Correct answer: 2)

Concept:

  • The number of moles in a given mass of a substance can be found by dividing the mass by the formula mass expressed in g/mol.
  • The value of the mole is equal to the number of atoms in exactly 12 grams of pure carbon-12 (12 g C = 1 mol C atoms = 6.022 × 1023 C atoms).

Explanation:

Given,

Mass of SbF3 = 179 g/mol

Mass of CCl2F2 = 121 g/ mol

Moles of 1 gram of freon = \(\frac{Mass}{Molar ; mass}\)

= \(\frac{1}{121}\)

= 0.0083

According to the balanced equation, 

2CCl4 + 2SbF3  → 3CCl2F2 + 2SbCl3

3 moles of CCl2F2  are produced from 2 moles of SbF3

So, 0.008 mole of CCl2F2 will produced from moles \(\frac{2}{3}\times 0.0083\) moles of SbF3

=0.0055

Mass of SbF3 = 0.0055 x 179

= 0.986 g

Conclusion:

Thus, SbF3 are needed to produce one gram of Freon-12, CCl2F2 = 0.986 g