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Question 41

Kolkata Police SI 2021• Test

The description of Samudragupta's war campaigns are found from which inscription or 'Prashasti'? 

  1. AOption (a)

    Mahishwar Prashasti

  2. BOption (b)

    Allahabad Prashasti

  3. COption (c)

    Nasik Prashasti

  4. DOption (d)

    Harishen Prashasti

View answer & explanation

Correct answer

Answer: (b)B.

Allahabad Prashasti

Why this answer is correct

The correct answer is Allahabad Prashasti.

Key Points 

  • The Allahabad Prashasti or the Allahabad Pillar Inscription is a very important source that gives information about the extensive military campaigns and conquests of Samudragupta, who was one of the most prominent rulers of the Gupta Dynasty.
  • This prashasti was composed by Harishena, a court poet and minister of Samudragupta, and it provides an elaborate description of the king's military campaigns, his benevolence, and his talents.
  • It was inscribed on an Ashokan pillar located at Allahabad (Prayagraj), Uttar Pradesh, India.
  • The Allahabad Prashasti is a significant example of ancient Sanskrit prose and offers valuable insights into the political and cultural life of Gupta-era India.

Question 42

Kolkata Police SI 2021• Test

B. C. Roy award is given in the field of 

  1. AOption (a)

    Environment

  2. BOption (b)

    Journalism

  3. COption (c)

    Music

  4. DOption (d)

    Medicine

View answer & explanation

Correct answer

Answer: (d)D.

Medicine

Why this answer is correct

The correct answer is Medicine.

Key Points

  • The Dr. B. C. Roy awards, instituted in 1962, are given to eminent achievers in the field of Medicine.
  • The awards are named after the noted doctor Bidhan Chandra Roy.
  • The Medical Council of India confers awards to the experts in the field.

Additional Information

FieldAwards
MusicGrammy Award
JournalismPulitzer Prizes
EnvironmentIndira Gandhi Paryavaran Puraskar (Indira Gandhi Environment Award)

Question 43

Kolkata Police SI 2021• Test

If order of the English alphabet is reversed starting from Z to A, which will be the eighth letter to the right of 'O'? 

  1. AOption (a)

    W

  2. BOption (b)

    G

  3. COption (c)

    F

  4. DOption (d)

    V

View answer & explanation

Correct answer

Answer: (b)B.

G

Why this answer is correct

English Alphabet series:

ABCDEFGHIJKLMNOPQRSTUVWXYZ

Reverse order:

ZYXWVUTSRQPONMLKJIHGFEDCBA

Eighth letter to the right of 'O' is G

ZYXWVUTSRQPONMLKJIHGFEDCBA

Hence the correct answer is Option 2: G

Question 44

Kolkata Police SI 2021• Test

Kushan Emperor Kanishka was transformed into Buddhism by whom? 

  1. AOption (a)

    Vishnugope

  2. BOption (b)

    Aswaghosha

  3. COption (c)

    Agrasen 

  4. DOption (d)

    Birupaksha

View answer & explanation

Correct answer

Answer: (b)B.

Aswaghosha

Why this answer is correct

The correct answer is Aswaghosha.

Key Points

  • Kushan Emperor Kanishka is believed to have converted to Buddhism under the influence of the Buddhist scholar and monk Aswaghosha.
  • Aswaghosha was a Buddhist philosopher and dramatist, considered the greatest poet and playwright in Sanskrit after Kalidasa.
  • Aswaghosha played a crucial role in spreading Buddhism and is credited with converting the Kushan emperor Kanishka to Buddhism.
  • Apart from his influential role, he is also known for his philosophical works and as the author of "Buddhacharita," a biography of Buddha.
  • Emperor Kanishka is also well-known for convening the Fourth Buddhist Council in Kashmir, which was an attempt to discuss and reconcile differences in Buddhist doctrines.
  • His reign marked a significant period of expansion and development for Buddhism, spreading it along the Silk Road into parts of Central Asia and China.
  • Kanishka was a great patron of Buddhism, however, he also respected other religious traditions and included Zoroastrians, Greeks, and Hindus in his court.

Additional Information

  • Agrasen:
  • Maharaja Agrasen is a legendary figure and is known as the progenitor of the Agrawal community.
  • He was a contemporary to the last Tirthankara, Mahavira.
  • Birupaksha: 
  • The term "Birupaksha" is most commonly associated with a deity worshipped in the Indian temples at Hampi and Pattadakal.

Question 45

Kolkata Police SI 2021• Test

[(12)2 × (14)2] ÷ (16)2 = ?

  1. AOption (a)

    104.25

  2. BOption (b)

    282.24

  3. COption (c)

    110.25

  4. DOption (d)

    126

View answer & explanation

Correct answer

Answer: (c)C.

110.25

Why this answer is correct

Given:

 

12², 14², 16²

 

Concept:

 

The problem requires basic arithmetic calculation. The operations should be carried out according to the order of operations, which stipulates that operations within brackets should be done first, followed by exponents, then multiplication and division from left to right.

 

Solution:

 

Calculate the square of each number inside the brackets:

 

⇒ (12)^2 = 144 ⇒ (14)^2 = 196 ⇒ (16)^2 = 256

 

Substitute the squares back into the equation and perform the multiplication and division:

 

⇒ [(12)^2 × (14)^2] ÷ (16)^2 = (144 × 196) ÷ 256

 

Perform the multiplication: ⇒ (144 × 196) = 28224

 

Finally, perform the division: ⇒ 28224 ÷ 256 = 110.25

 

Therefore, the value of [(12)^2 × (14)^2] ÷ (16)^2 is 110.25.

Question 46

Kolkata Police SI 2021• Test

\(\frac{3}{4}\)th of \(\frac{2}{9}\)th of \(\frac{1}{5}\)th of a number is 249.6. What is 50% of that number?

  1. AOption (a)

    3734

  2. BOption (b)

    3794

  3. COption (c)

    3744

  4. DOption (d)

    3749

View answer & explanation

Correct answer

Answer: (c)C.

3744

Why this answer is correct

Solution

Let the number be P

3/4 x 2/9 x 1/5 x P  = 249.6

P = 249.6 x 30 

50% of P =  (50/100) x 249.6 x 30 

= 249.6 x 15

= 3744

Question 47

Kolkata Police SI 2021• Test

The ratio of the length and the breadth of a rectangular plot is 6 ∶ 5 If the breadth of the plot is 34 meter less than the length, what is the perimeter of the rectangular plot? 

  1. AOption (a)

    748 m

  2. BOption (b)

    408 m

  3. COption (c)

    374 m

  4. DOption (d)

    814 m

View answer & explanation

Correct answer

Answer: (a)A.

748 m

Why this answer is correct

Given:

 

The ratio of length to breadth: 6 ∶ 5

 

Difference between length and breadth: 34 meters

 

Concept: The perimeter of a rectangle is given by the formula Perimeter = 2 × (Length + Breadth).

 

The ratio of lengths can be used to derive the actual lengths and then be substituted into the formula.

 

Solution:

 

Let's assume that the length of the rectangular plot is 6x and the breadth is 5x.

 

According to the condition, the difference between the length and breadth is 34m. ⇒ 6x - 5x = 34 ⇒ x = 34

 

Now we can calculate the actual length and breadth:

 

⇒ Length = 6x = 6 × 34 = 204 meters ⇒ Breadth = 5x = 5 × 34 = 170 meters

 

Finally, calculate the perimeter using the formula: ⇒ Perimeter = 2 × (Length + Breadth) ⇒ Perimeter = 2 × (204 + 170) = 748 meters

 

Therefore, the perimeter of the rectangular plot is 748 meters.

Question 48

Kolkata Police SI 2021• Test

The battle of Plassey was fought in 

  1. AOption (a)

    1787

  2. BOption (b)

    1766

  3. COption (c)

    1757

  4. DOption (d)

    1780

View answer & explanation

Correct answer

Answer: (c)C.

1757

Why this answer is correct

The correct answer is 1757.

Key Points

  • The Battle of Plassey is regarded as a historic turning point for the British in India.

  • It established the political and military supremacy of the British in Bengal.

  • Battle of Plassey

  • The Battle of Plassey was fought in 1757 in the Plassey (or Palashi) region of West Bengal, on the east of the Bhagirathi river.

  • British East India Company, led by Robert Clive, won against the forces of Siraj-ud-Daulah, the last independent Nawab of Bengal, and his French allies.

  • In the aftermath, Mir Jafar was installed as the Nawab of Bengal, on the throne of Murshidabad.

Additional Information

  • Reasons behind the Battle of Plassey
  • The British victory in the Carnatic made the Nawab of Bengal apprehensive of the rising power of the British.
  • The East India Company kept misusing its power, including fortifying Calcutta without the Nawab’s permission.
  • The Nawab marched to Fort Williams and captured it, leading to the infamous ‘Black Hole of Calcutta’ incident.
  • Robert Clive was sent to overthrow the Nawab leading to the battle.

Question 49

Kolkata Police SI 2021• Test

The driver of an ambulance sees a bus moving in the same direction 40 meter ahead of him. After 20 second, the bus is 60 meter behind. If the speed of the ambulance is 30 km/hr, what is the speed of the bus? 

  1. AOption (a)

    22 km/hr

  2. BOption (b)

    12 km/hr

  3. COption (c)

    10 km/hr

  4. DOption (d)

    15 km/hr

View answer & explanation

Correct answer

Answer: (b)B.

12 km/hr

Why this answer is correct

Given:

 

The initial distance between the ambulance and the bus: is 40 meters

Time taken for the ambulance to overtake the bus: 20 seconds

Distance between the ambulance and bus after overtaking: 60 meters

Speed of ambulance: 30 km/hr

 

Concept:

 

The speed of a moving body can be calculated from the relation:

 

Speed = Distance/Time.

 

Solution:

 

Convert the speed of the ambulance from km/hr to m/s by multiplying with 5/18:

 

⇒ Speed of ambulance in m/s = 30 × (5/18) = 8.33 m/s

 

Calculate the total distance covered by the ambulance in 20 seconds:

 

⇒ Total distance covered by ambulance = Speed of ambulance × Time

 

⇒ Total distance = 8.33 m/s × 20 seconds = 166.6 meters

 

The ambulance covered 40 meters to reach the bus and 60 meters after that to go ahead of the bus. Subtract these distances from the total distance to find the distance covered by the bus:

 

⇒ Distance covered by bus = Total distance covered by ambulance - Distance ambulance was behind - Distance ambulance went ahead

 

⇒ Distance covered by bus = 166.6 m - 40 m - 60 m = 66.6 meters

 

Calculate the speed of the bus using the distance covered by bus and time:

 

⇒ Speed of bus = Distance covered by bus / Time

 

⇒ Speed of bus in m/s = 66.6 m / 20 seconds = 3.33 m/s

 

Finally, convert the speed of the bus from m/s to km/hr by multiplying by 18/5:

 

⇒ Speed of bus in km/hr = 3.33 m/s × 18/5 = 12 km/hr

 

Therefore, the speed of the bus is 12 km/hr.

Question 50

Kolkata Police SI 2021• Test

India's national carrier, Air India, has been officially handed over to 

  1. AOption (a)

    Spicejet

  2. BOption (b)

    Indigo Airlines

  3. COption (c)

    The Tata Group

  4. DOption (d)

    Jet Airways

View answer & explanation

Correct answer

Answer: (c)C.

The Tata Group

Why this answer is correct

The correct answer is The Tata Group.

Key Points

  • Air India has been sold to Tata Group for a sum of Rs 18000 crore.
  • Tata Group acquired 100% stake in Air India.
  • Tata Group also acquired 100% stake in Air India's low-cost carrier named Air India Express.
  • Tata Group also acquired  50% stake in AISATS ( Air India Singapore Airport Terminal Service).
  • There were two bidders in the race for acquisition of Air India:
  1. Tata Group
  2. Spice Jet

Additional Information

  • Air India has been sold to Tata Group in 2021.
  • Air India was established as Tata Air Services in the year 1932.
  • Air India was acquired by the Government of India in the year 1953 under the Air Corporations Act.