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Question 571

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

4 × 22.5 ÷ 1.5 + ? –  6 = 30

  1. AOption (a)

    20

  2. BOption (b)

    -24

  3. COption (c)

    -15

  4. DOption (d)

    25

  5. EOption (e)

    18

View answer & explanation

Correct answer

Answer: (b)B.

-24

Why this answer is correct

Given expression : 

4 × 22.5 ÷ 1.5 + ? –  6 = 30

⇒ 4 × 15 + ? – 6 = 30

⇒ 60 + ? - 6 = 30

 ∴ ? = 30 - 60 + 6 = -24

Question 572

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What should come in place of the question mark '?' in the following number series?

[(275 - 124) + 42 - 92 - 36)] + 14 = ?

  1. AOption (a)

    64

  2. BOption (b)

    36

  3. COption (c)

    52

  4. DOption (d)

    32

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

64

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

Now,

[(275 - 124) + 42 - 92 - 36)] + 14 = ?

⇒ [151 + 16 - 81 - 36] + 14 = ? 

⇒ 50 + 14

⇒ 64 = ?

⇒ ? = 64

∴ The required value  is 64

Question 573

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

75 - 3 × {(62 ÷ 6) ÷ 3} ÷ \(\frac{1}{3}\) + 13 =?

  1. AOption (a)

    50

  2. BOption (b)

    40

  3. COption (c)

    60

  4. DOption (d)

    70

  5. EOption (e)

    80

View answer & explanation

Correct answer

Answer: (d)D.

70

Why this answer is correct

Follow the BODMAS rule to solve this question, as per the order given below:

75

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Now,

75 - 3 × {(62 ÷ 6) ÷ 3} ÷ \(\frac{1}{3}\) + 13 =?

⇒ 75 - 3 × {(62 × 1/6) ÷ 3} ÷ \(\frac{1}{3}\) + 13 = ?

⇒ 75 - 3 × {6 ÷ 3} ÷ \(\frac{1}{3}\) + 13 = ?

⇒ 75 - 3 × 2 × 3/1 + 13 = ?

⇒ 75 - 18 + 13 = ?

⇒ 88 - 18 = ?

⇒ ? = 70

∴ The required value in the place of the question mark (?) is 70

Question 574

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in place of the question mark?

220 ÷ 5 ÷ 0.4 + 20 × 3 = ?

  1. AOption (a)

    170

  2. BOption (b)

    175

  3. COption (c)

    189

  4. DOption (d)

    128

  5. EOption (e)

    146

View answer & explanation

Correct answer

Answer: (a)A.

170

Why this answer is correct

Solution:

We have to follow the BODMAS rule

Calculation:

220 ÷ 5 ÷ 0.4 + 20 × 3 = ?

⇒ 44 ÷ 0.4 + 20 × 3 = ?

⇒110 + 20 × 3 = ?

⇒ 110 + 60 = ?

⇒ ? = 170

∴ 170 will come in place of question mark

Question 575

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

(42 × 6 × 6) ÷ 36 × 9 = 20% of ?

  1. AOption (a)

    340

  2. BOption (b)

    550

  3. COption (c)

    270

  4. DOption (d)

    720

  5. EOption (e)

    27

View answer & explanation

Correct answer

Answer: (d)D.

720

Why this answer is correct

Given:

(42 × 6 × 6) ÷ 36 × 9 = 20% of ?

Solution:

Follow the BODMAS rule according to the table given below:

Calculation:

(42 × 6 × 6) ÷ 36 × 9 = 20% of ?

⇒ (96 × 6) ÷ 36 × 9 = 20% of ?

⇒ 576 ÷ 36 × 9 = 20% of ?

⇒ 16 × 9 = 20% of ?

⇒ (144 × 100)/20 = ?

⇒ ? = 720

∴ 720 will come in place of the question mark

Question 576

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

\(13\frac{6}{7} + 8\frac{2}{5} - 1\frac{5}{7} \times 2\frac{1}{3} = ;?\)

  1. AOption (a)

    \(2\frac{7}{{35}}\)

  2. BOption (b)

    \(14\frac{7}{{35}}\)

  3. COption (c)

    \(12\frac{7}{{25}}\)

  4. DOption (d)

    \(8\frac{9}{{35}}\)

  5. EOption (e)

    \(18\frac{9}{{35}}\)

View answer & explanation

Correct answer

Answer: (e)E.

\(18\frac{9}{{35}}\)

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

Calculation:

Considering the given equation

\(13\frac{6}{7} + 8\frac{2}{5} - 1\frac{5}{7} × 2\frac{1}{3} = ;?\)

We can transform each term within the given equation in the p/q form as follows: -

⇒ 97/7 + 42/5 - 12/7 × 7/3 = ?

⇒ 97/7 + 42/5 - 12/3 = ?

⇒ 97/7 + 42/5 - 4 = ?

⇒ 779/35 - 4 = ?

⇒ (779 - 140)/35 = ?

⇒ 639/35 = ? 

⇒ ? = 639/35

⇒ ? = \(18\frac{9}{{35}}\)

∴ The required value of "?" in the given equation is ​\(18\frac{9}{{35}}\)​

Question 577

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What should come in place of question mark (?) in the following questions?

[(121)2 ÷ 11 × 2] ÷ 44 × 2 – 57 = ?2

  1. AOption (a)

    4

  2. BOption (b)

    16

  3. COption (c)

    9

  4. DOption (d)

    8

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

8

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

Calculation:

Considering the given equation

[(121)2 ÷ 11 × 2] ÷ 44 × 2 – 57 = ?2

⇒ [14641 ÷ 11 × 2] ÷ 44 × 2 – 57 = ?2

⇒ [1331 × 2] ÷ 44 × 2 – 57 = ?2

⇒ [2662] ÷ 44 × 2 – 57 = ?2

⇒ 2662 ÷ 44 × 2 – 57 = ?2

⇒ 60.5 × 2 – 57 = ?

⇒ 121 – 57 = ?

⇒ 64 = ?2

⇒ 8 = ?

∴ ? = 8

Question 578

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What should come in place of question mark (?) in the following questions?

12167 ÷ 23 × 2 + 386 + ?2 = 2888

  1. AOption (a)

    48

  2. BOption (b)

    58

  3. COption (c)

    43

  4. DOption (d)

    38

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

38

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

Calculation:

Considering the given equation

12167 ÷ 23 × 2 + 386 + ?2 = 2888

⇒ 529 × 2 + 386 + ?2 = 2888

⇒ 1058 + 386 + ?2 = 2888

⇒ 1444 + ?2 = 2888

⇒ ?2 = 2888 – 1444

⇒ ?2 = 1444

⇒ ? = 38

∴ ? = 38

Question 579

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

∛6859 + √441 – ∛4096 – √576 = ?

  1. AOption (a)

    1

  2. BOption (b)

    48

  3. COption (c)

    0

  4. DOption (d)

    -42

  5. EOption (e)

    None of these.

View answer & explanation

Correct answer

Answer: (c)C.

0

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculations:

∛6859 + √441 – ∛4096 – √576 = ?

⇒ 19 + 21 – 16 – 24 = ?

⇒ 19 + 21 – 16 – 24 = ?

⇒ 40 – 40 = ?

⇒ ? = 0

∴ The value of ? is 0

Question 580

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

Find the value of ‘?’ in the following question.

[122 + (142 – 40)] × 2.5 = ? × 25

  1. AOption (a)

    25

  2. BOption (b)

    35

  3. COption (c)

    15

  4. DOption (d)

    30

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

30

Why this answer is correct

Concept used:

Follow BODMAS rule to solve the question as per the order given below:

Step 1: Part of an equation enclosed in ‘Brackets’ must be solved first and in the bracket.

Step 2: Any mathematical ‘of’ or ‘Exponent’ must be solved next.

Step 3: Next, the parts of the equation that contain ‘Division’ and ‘Multiplication’ are calculated.

Step 4: Last but not least, the part of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.

Now,

Calculations:

Considering the given equation,

[122+ (142 – 40)] × 2.5 = ? × 25

⇒ [122 + (196 – 40)] × 2.5 = ? × 25

⇒ [122 + 156] × 2.5 = ? × 25

⇒ [144 + 156] × 2.5 = ? × 25

⇒ 300 × 2.5 = ? × 25

⇒ 750 = ? × 25

∴ ? = 30