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Question 561

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

Directions: Study the following bar graph carefully and answer the questions that follow.

The double bar graph shows data regarding five different Managers (A, B, C, D, and E) working in an IT infrastructure company.

  • The Blue Bar represents the Total Number of Projects handled by each manager.
  • The Orange Bar represents the Average Cost per Project (in ₹ Lakhs) for that specific manager.

Note:

Total Cost = Number of Projects × Average Cost per Project.

A new Manager 'F' handles the same number of projects as the average number of projects handled by A and C. The Average Cost per project for F is equal to the average of the costs per project of B and D. Find the Total Cost of projects handled by Manager F.

  1. AOption (a)

    ₹2,697 Lakhs

  2. BOption (b)

    ₹2,745 Lakhs

  3. COption (c)

    ₹2,586 Lakhs

  4. DOption (d)

    ₹2,640 Lakhs

  5. EOption (e)

    ₹2,810 Lakhs

View answer & explanation

Correct answer

Answer: (a)A.

₹2,697 Lakhs

Why this answer is correct

General Solution:

Given:

Managers A, B, C, D, E with Number of Projects and Average Cost (₹ Lakhs):

A: 68 projects, ₹45

B: 73 projects, ₹52

C: 56 projects, ₹65

D: 84 projects, ₹35

E: 62 projects, ₹48

Total Costs:

⇒ A: 68 × 45 = 3060 (₹ Lakhs)

⇒ B: 73 × 52 = 3796 (₹ Lakhs)

⇒ C: 56 × 65 = 3640 (₹ Lakhs)

⇒ D: 84 × 35 = 2940 (₹ Lakhs)

⇒ E: 62 × 48 = 2976 (₹ Lakhs)

Calculations:

⇒ Projects_F = (68 + 56) ÷ 2 = 62

⇒ Avg cost_F = (52 + 35) ÷ 2 = 87 ÷ 2 = 43.5 (₹ Lakhs)

⇒ Total Cost_F = 62 × 43.5 = 2697 (₹ Lakhs)

Hence, the correct answer is ₹2,697 Lakhs

Question 562

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

Directions: Study the following bar graph carefully and answer the questions that follow.

The double bar graph shows data regarding five different Managers (A, B, C, D, and E) working in an IT infrastructure company.

  • The Blue Bar represents the Total Number of Projects handled by each manager.
  • The Orange Bar represents the Average Cost per Project (in ₹ Lakhs) for that specific manager.

Note:

Total Cost = Number of Projects × Average Cost per Project.

The Total Cost of projects handled by Manager B is what percentage more or less than the Total Cost of projects handled by Manager E?

  1. AOption (a)

    24.5% more 

  2. BOption (b)

    27.5% more

  3. COption (c)

    21.5% less

  4. DOption (d)

    27.5% less 

  5. EOption (e)

    32.5% more

View answer & explanation

Correct answer

Answer: (b)B.

27.5% more

Why this answer is correct

General Solution:

Given:

Managers A, B, C, D, E with Number of Projects and Average Cost (₹ Lakhs):

A: 68 projects, ₹45

B: 73 projects, ₹52

C: 56 projects, ₹65

D: 84 projects, ₹35

E: 62 projects, ₹48

Total Costs:

⇒ A: 68 × 45 = 3060 (₹ Lakhs)

⇒ B: 73 × 52 = 3796 (₹ Lakhs)

⇒ C: 56 × 65 = 3640 (₹ Lakhs)

⇒ D: 84 × 35 = 2940 (₹ Lakhs)

⇒ E: 62 × 48 = 2976 (₹ Lakhs)

Calculations:

⇒ B = 3796 ; E = 2976

⇒ Difference = 3796 − 2976 = 820

⇒ Percent more = (820 ÷ 2976) × 100 ≈ 0.2755 × 100 = 27.55% ≈ 27.5% more

Hence, the correct answer is 27.5% more.

Question 563

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

Directions: Study the following bar graph carefully and answer the questions that follow.

The double bar graph shows data regarding five different Managers (A, B, C, D, and E) working in an IT infrastructure company.

  • The Blue Bar represents the Total Number of Projects handled by each manager.
  • The Orange Bar represents the Average Cost per Project (in ₹ Lakhs) for that specific manager.

Note:

Total Cost = Number of Projects × Average Cost per Project.

Manager C achieved a total revenue of ₹4,368 Lakhs from all projects. Find the Profit earned by Manager C.

  1. AOption (a)

    ₹728 Lakhs

  2. BOption (b)

    ₹795 Lakhs

  3. COption (c)

    ₹778 Lakhs 

  4. DOption (d)

    ₹786 Lakhs

  5. EOption (e)

    ₹790 Lakhs

View answer & explanation

Correct answer

Answer: (a)A.

₹728 Lakhs

Why this answer is correct

General Solution:

Given:

Managers A, B, C, D, E with Number of Projects and Average Cost (₹ Lakhs):

A: 68 projects, ₹45

B: 73 projects, ₹52

C: 56 projects, ₹65

D: 84 projects, ₹35

E: 62 projects, ₹48

Total Costs:

⇒ A: 68 × 45 = 3060 (₹ Lakhs)

⇒ B: 73 × 52 = 3796 (₹ Lakhs)

⇒ C: 56 × 65 = 3640 (₹ Lakhs)

⇒ D: 84 × 35 = 2940 (₹ Lakhs)

⇒ E: 62 × 48 = 2976 (₹ Lakhs)

Calculations:

⇒ C Total Cost = 3640

⇒ C Revenue = 4368 ⇒ Profit_C = 4368 − 3640 = 728 (₹ Lakhs)

Hence, the correct answer is ₹728 Lakhs

Question 564

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

Directions: Study the following bar graph carefully and answer the questions that follow.

The double bar graph shows data regarding five different Managers (A, B, C, D, and E) working in an IT infrastructure company.

  • The Blue Bar represents the Total Number of Projects handled by each manager.
  • The Orange Bar represents the Average Cost per Project (in ₹ Lakhs) for that specific manager.

Note:

Total Cost = Number of Projects × Average Cost per Project.

For Manager E, 50% of the projects were "High-Priority" and the remaining were "Standard". Find the value of the number of 'Standard" projects.

  1. AOption (a)

    38 

  2. BOption (b)

    39

  3. COption (c)

    33

  4. DOption (d)

    29

  5. EOption (e)

    31

View answer & explanation

Correct answer

Answer: (e)E.

31

Why this answer is correct

General Solution:

Given:

Managers A, B, C, D, E with Number of Projects and Average Cost (₹ Lakhs):

A: 68 projects, ₹45

B: 73 projects, ₹52

C: 56 projects, ₹65

D: 84 projects, ₹35

E: 62 projects, ₹48

Total Costs:

⇒ A: 68 × 45 = 3060 (₹ Lakhs)

⇒ B: 73 × 52 = 3796 (₹ Lakhs)

⇒ C: 56 × 65 = 3640 (₹ Lakhs)

⇒ D: 84 × 35 = 2940 (₹ Lakhs)

⇒ E: 62 × 48 = 2976 (₹ Lakhs)

Calculations:

For E — 50% High-Priority, remaining 50% Standard

Number of Standard Projects = 62 × 50 / 100 = 31

Hence, the correct answer is 31.

Question 565

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

Directions: Study the following bar graph carefully and answer the questions that follow.

The double bar graph shows data regarding five different Managers (A, B, C, D, and E) working in an IT infrastructure company.

  • The Blue Bar represents the Total Number of Projects handled by each manager.
  • The Orange Bar represents the Average Cost per Project (in ₹ Lakhs) for that specific manager.

Note:

Total Cost = Number of Projects × Average Cost per Project.

What is the ratio of the Total Cost of all projects handled by Manager A to the Total Cost of all projects handled by Manager D?

  1. AOption (a)

    49 : 51 

  2. BOption (b)

    51 : 49 

  3. COption (c)

    45 : 47 

  4. DOption (d)

    15 : 14

  5. EOption (e)

    17 : 16

View answer & explanation

Correct answer

Answer: (b)B.

51 : 49 

Why this answer is correct

General Solution:

Given:

Managers A, B, C, D, E with Number of Projects and Average Cost (₹ Lakhs):

A: 68 projects, ₹45

B: 73 projects, ₹52

C: 56 projects, ₹65

D: 84 projects, ₹35

E: 62 projects, ₹48

Total Costs:

⇒ A: 68 × 45 = 3060 (₹ Lakhs)

⇒ B: 73 × 52 = 3796 (₹ Lakhs)

⇒ C: 56 × 65 = 3640 (₹ Lakhs)

⇒ D: 84 × 35 = 2940 (₹ Lakhs)

⇒ E: 62 × 48 = 2976 (₹ Lakhs)

Calculations:

Total Cost A : Total Cost D

⇒ 3060 : 2940 = divide by 60 ⇒ 51 : 49

Hence, the correct answer is 51 : 49.

Question 566

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The total amount invested by A and B in a business is Rs. 75,000. A invested his capital for 8 months, while B invested his capital for 12 months. At the end of the term, both received an equal share of the profit. What was the amount invested by A?

  1. AOption (a)

    Rs. 30,000

  2. BOption (b)

    Rs. 40,000

  3. COption (c)

    Rs. 50,000

  4. DOption (d)

    Rs. 45,000

  5. EOption (e)

    Rs. 35,000

View answer & explanation

Correct answer

Answer: (d)D.

Rs. 45,000

Why this answer is correct

Given:

Total capital invested by A and B = Rs. 75,000

A invests for 8 months

B invests for 12 months

Both receive equal profit ⇒ Their effective capital (Capital × Time) must be equal.

Let A's capital = x

Then B's capital = 75,000 − x

Condition for equal profit:

A_capital × A_time = B_capital × B_time

x × 8 = (75,000 − x) × 12

Solve:

8x = 12(75,000 − x)

8x = 900,000 − 12x

8x + 12x = 900,000

20x = 900,000

x = 900,000 ÷ 20 = 45,000

A's investment = Rs. 45,000

Hence, the correct answer is Rs. 45,000

Question 567

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The total quantity of milk in three containers A, B, and C is 28 litres. The ratio of milk in A, B, and C is initially 4 : 1 : 2. If 4 litres of milk is added to container B, what will be the new ratio of milk in A, B, and C?

  1. AOption (a)

    3 : 2 : 1

  2. BOption (b)

    2 : 1 : 1

  3. COption (c)

    4 : 3 : 2

  4. DOption (d)

    1 : 2 : 1

  5. EOption (e)

    None of the above

View answer & explanation

Correct answer

Answer: (b)B.

2 : 1 : 1

Why this answer is correct

Given:

Total milk = 28 litres

Initial ratio A : B : C = 4 : 1 : 2

Find actual quantities:

Total ratio parts = 4 + 1 + 2 = 7

⇒ 1 part = 28 ÷ 7 = 4 litres

⇒ A = 4 × 4 = 16 L

⇒ B = 1 × 4 = 4 L

⇒ C = 2 × 4 = 8 L

4 litres added to container B:

New B = 4 + 4 = 8 L

New ratio:

A : B : C = 16 : 8 : 8

Divide by common factor 8:

= 2 : 1 : 1

Hence, the correct answer is 2 : 1 : 1

Question 568

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The cost price of 12 articles is 2424. The shopkeeper sells these articles at a profit of 25%, then, find the amount gained by the shopkeeper on each article.

  1. AOption (a)

    48

  2. BOption (b)

    50

  3. COption (c)

    50.5

  4. DOption (d)

    55.5

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

50.5

Why this answer is correct

Given:

C.P of 12 article = Rs. 2424

Profit = 25%

Concept:

Cost price × (100 + Profit %)/100 = Selling price

Where C.P = Cost price, S.P = Selling price

Calculation:

C.P of 12 article = Rs. 2424

C.P of each article:

⇒ 2424/12

⇒ 202

S.P of an article = 202 × (125/100)

⇒ 202 × 5/4

⇒ 252.5

Profit = S.P – C.P

⇒ 252.5 – 202

⇒ 50.5

∴ Rs. 50.5 gained by the shopkeeper on each article.

Question 569

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

37.5 × 2 + 15 ÷ 3 – 14/3 of (?) = 10

  1. AOption (a)

    6

  2. BOption (b)

    8

  3. COption (c)

    5

  4. DOption (d)

    10

  5. EOption (e)

    15

View answer & explanation

Correct answer

Answer: (e)E.

15

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is

37.5 × 2 + 15 ÷ 3 – 14/3 of (?) = 10 

⇒ 75 + 5 – 14/3 of (?) = 10 

⇒ 70 = 14/3 of (?) 

⇒ ? = 15

Question 570

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

3 × 5/9 of ( 36 ÷ 4 ) × 6 - ? + 5 = 4

  1. AOption (a)

    40

  2. BOption (b)

    76

  3. COption (c)

    91

  4. DOption (d)

    26

  5. EOption (e)

    35

View answer & explanation

Correct answer

Answer: (c)C.

91

Why this answer is correct

Concept:

Follow BODMAS rule to solve this question, as per the order given below, 

CALCULATION :

Given expression :

3 × 5/9 of ( 36 ÷ 4 ) × 6 - ? + 5 = 4

⇒ 3 × 5/9 of (9) × 6 - ? + 5 = 4

⇒ 3 × 5 × 6 - ? + 5 = 4

⇒ 90 - ? + 5 = 4 

⇒ 90 - 4 + 5 = ?

⇒ ? = 91 

∴ ? = 91

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