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Given

Statement:

Y < U ≤ Q ≥ S >T = O > P

Conclusions:

I. P < Q → True as Q ≥ S >T = O > P, thus Q > P.

II. Y < S → False as Y < U ≤ Q ≥ S, thus there is no definite relation between them.

Hence, only conclusion I is true.

Given statement is:  C < P ≤ M = U = S < E ≥ T

Conclusion:

I. C > E → FalseasC < P ≤ M = U = S < E, thusC < E.

II. E < P → False as P ≤ M = U = S < E, P < E.

Hence, neither conclusion I nor II is true.

Given: A > K ≤ D; D < B; B > K ≤ C

On combining: A > K ≤ D = C < B

I. A < C ⇒ False (as A > K ≤ D = C relation between A and C can’t be established)

II. A = C ⇒ (as A > K ≤ D = C relation between A and C can’t be established)

Hence, Neither I nor II is true.

Forward pair: ST

Backward pair: None

Thus, there are one such pair of letters in the word "MISTAKE" which have as many letters between them as in the English alphabetical series (both in forward and backward direction).

Hence, the correct answer is one such pair.

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

1. E has a reservation on Wednesday. 

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

3. There are exactly two days between G and B.

4. The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

5. D's reservation is after B but before F.

Now, we can eliminate Case 2.

This is our final arrangement,

Hence, the correct answer is C.

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

1. E has a reservation on Wednesday. 

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

3. There are exactly two days between G and B.

4. The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

5. D's reservation is after B but before F.

Now, we can eliminate Case 2.

This is our final arrangement,

Hence, the correct answer is Thursday.

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

1. E has a reservation on Wednesday. 

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

3. There are exactly two days between G and B.

4. The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

5. D's reservation is after B but before F.

Now, we can eliminate Case 2.

This is our final arrangement,

Hence, the correct answer is B.

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

1. E has a reservation on Wednesday. 

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

3. There are exactly two days between G and B.

4. The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

5. D's reservation is after B but before F.

Now, we can eliminate Case 2.

This is our final arrangement,

Hence, the correct answer is Three.

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

1. E has a reservation on Wednesday. 

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

3. There are exactly two days between G and B.

4. The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

5. D's reservation is after B but before F.

Now, we can eliminate Case 2.

This is our final arrangement,

Hence, the correct answer is F - Saturday.

Since, each letter cluster contains a vowel except MPR which contain only consonants.

Hence, the odd one is MPR.