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Question 511

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

24 + 112 – 64 ÷ 8 + 12 ÷ 3 = ?

  1. AOption (a)

    122

  2. BOption (b)

    132

  3. COption (c)

    133

  4. DOption (d)

    162

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

132

Why this answer is correct

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

24 + 112 – 64 ÷ 8 + 12 ÷ 3 = ?

⇒ 24 + 112 – 8 + 4 = ?

⇒ 136 – 8 + 4 = ?

⇒ 140 – 8 = ?

⇒ ? = 132

∴ Result will be 132.

Question 512

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What should come in place of question mark (?) in the following questions?

26 + 22 – 24 + 112 ÷ 16 × 4 = ?

  1. AOption (a)

    51

  2. BOption (b)

    54

  3. COption (c)

    52

  4. DOption (d)

    53

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

52

Why this answer is correct

Concept Used:       

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

26 + 22 – 24 + 112 ÷ 16 × 4 = ? 

⇒ 26 + 22 – 24 + 7 × 4 = ?

⇒ 26 + 22 – 24 + 28 = ?

⇒ 76 – 24 = ?

⇒ 52 = ?

∴ Result will be 52.

Question 513

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What should come in place of question mark (?) in the following questions?

1728 - √144 × 20 ÷ 2.5 + 89 – 12 = ?

  1. AOption (a)

    1509

  2. BOption (b)

    1609

  3. COption (c)

    1709

  4. DOption (d)

    1109

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

1709

Why this answer is correct

Concept Used:       

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

1728 - √144 × 20 ÷ 2.5 + 89 – 12 = ?

⇒ 1728 – 12 × 8 + 89 – 12 = ?

⇒ 1728 – 96 + 89 – 12 = ?

⇒ 1817 – 108 = ?

⇒ 1709 = ?

∴ Result will be 1709.

Question 514

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What should come in place of question mark (?) in the following questions?

[(22)2 × 2 ÷ 22] ÷ 44 × 5 – 1 = ? – 124

  1. AOption (a)

    628

  2. BOption (b)

    738

  3. COption (c)

    724

  4. DOption (d)

    728

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (e)E.

None of these

Why this answer is correct

Concept Used:       

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

[(22)2 × 2 ÷ 22] ÷ 44 × 5 – 1 = ? – 124

⇒ [484 ÷ 11] ÷ 44 × 5 – 1 = ? – 124

⇒ 44 ÷ 44 × 5 – 1 = ? – 124

⇒ 1 × 5 – 1 = ? – 124

⇒ 5 – 1 = ? – 124

⇒ 4 = ? – 124

⇒ ? = 128

∴ ? = 128

Question 515

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What should come in place of question mark (?) in the following questions?

2000 % of 15 ÷ 5 × 12 = ?

  1. AOption (a)

    730

  2. BOption (b)

    620

  3. COption (c)

    710

  4. DOption (d)

    720

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

720

Why this answer is correct

Concept Used:       

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

⇒ 2000 % of 15 ÷ 5 × 12 = ?

⇒ 300 ÷ 5 × 12 = ?

⇒ 60 × 12 = ?

⇒ ? = 720

∴ ? = 720

Question 516

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

81 – 9 × √49 + 21 + √225 × 2 = ?

  1. AOption (a)

    99

  2. BOption (b)

    79

  3. COption (c)

    89

  4. DOption (d)

    69

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

69

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

81 – 9 × √49 + 21 + √225 × 2 = ?

⇒ 81 – 9 × 7 + 21 + 15 × 2 = ?

⇒ 81 – 63 + 21 + 30 = ?

⇒ 81 – 63 + 51 = ?

⇒ 132 – 63 = ?

⇒ 69 = ?

∴ ? = 69.

Question 517

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

81 ÷ 9 × 3 + 21 – 63 + 16 × 6 = ?

  1. AOption (a)

    31

  2. BOption (b)

    81

  3. COption (c)

    41

  4. DOption (d)

    51

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

81

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

81 ÷ 9 × 3 + 21 – 63 + 16 × 6 = ?

⇒ 9 × 3 + 21 – 63 + 16 × 6 = ?

⇒ 27 + 21 – 63 + 96 = ?

⇒ 144 – 63 = ?

⇒ 81 = ?

∴ The value of ? is 81

Question 518

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

A shopkeeper increased the cost price by 30% and gave 30% discount and suffered a loss of Rs. 810. What was the cost price of product ?

  1. AOption (a)

    990

  2. BOption (b)

    1000

  3. COption (c)

    720

  4. DOption (d)

    9000

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

9000

Why this answer is correct

Given:

M.R.P = 30% more than CP

Discount = 30%

Loss = Rs. 810

Formula Used:

Cost price × (100 + Profit %)/100 = Selling price

Also, Cost price × (100 - Loss %)/100 = Selling price

{(M.R.P – S.P)/M.R.P} × 100 = Discount %

Calculation:

Let the C.P of the product be 100x.

M.R.P = 100x × (130/100)

⇒ 130x

Discount = 30%

⇒ 130x × (30/100) = 39x

S.P = 130x – 39x

⇒ 91x

Loss = C.P – S.P

⇒ 100x – 91x

⇒ 9x

Value of 90x = 810

⇒ x = 810/9

⇒ x = 90

C.P = 100x

⇒ 100 × 90

⇒ 9000

∴ The cost price of the product was Rs. 9000.

Alternate Method

Let C.P be 100x.

C.P : M.R.P : Dis. : S.P : Loss

100x : 130x : 39x : 91x : 9x

Loss = 810

⇒ 9x = 810

⇒ x = 90

C.P = 100x

⇒ 100 × 90

⇒ 9000

∴ The cost price of the product is Rs. 9000.

Question 519

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The salaries of three friends A, B and C are in the ratio 2 ∶ 5 ∶ 7. If the increment in their salary is 5%, 20% and 30% respectively, what is the new ratio of their salaries?

  1. AOption (a)

    40 ∶ 63 ∶ 110

  2. BOption (b)

    35 ∶ 43 ∶ 110

  3. COption (c)

    21 ∶ 60 ∶ 91   

  4. DOption (d)

    29 ∶ 63 ∶ 91   

  5. EOption (e)

    35 ∶ 28 ∶ 97

View answer & explanation

Correct answer

Answer: (c)C.

21 ∶ 60 ∶ 91   

Why this answer is correct

Given: 

The ratio of Salaries of A, B and C = 2 ∶ 5 ∶ 7

Increment in salary of A = 5%

Increment in salary of B = 20%

Increment in salary of C = 30%

Formula used:

Salary after increment = old salary × [(100 + increased percent)/100]

Calculation:

Let the salary of A, B and C is 2x, 5x and 7x respectively.

New salary of A after increment = 2x × (105/100) = 210x/100

New salary of B after increment = 5x × (120/100) = 600x/100

New salary of C after increment = 7x × (130/100) = 910x/100

Now, Ratio of the salaries of A, B and C = 210x ∶ 600x ∶ 910x

⇒ 21 ∶ 60 ∶ 91

∴ The new ratio of salaries of A, B and C is 21 ∶ 60 ∶ 91 respectively.

Question 520

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The milk and water in a mixture are in the ratio of 7 : 5. When 15 litres of milk and 25 litres of water are added in the mixture, The mixture becomes 1 :

  1. Find the quantity of Milk in the new mixture.
  1. AOption (a)

    40 litres

  2. BOption (b)

    35 litres

  3. COption (c)

    45 litres

  4. DOption (d)

    50 litres

  5. EOption (e)

    30 litres

View answer & explanation

Correct answer

Answer: (d)D.

50 litres

Why this answer is correct

Given:

Ratio of milk and water in the mixture = 7 : 5

Amount of milk added = 15 litres

Amount of water added = 25 litres

Ratio of final mixture = 1 : 1

Formula used:

∴ (Ratio of milk in the mixture + new quantity of milk added) : (Ratio of water in the mixture + new quantity of water added) = New ratio of mixture

Calculation:

Let the amount of milk and water be 7x and 5x respectively

New amount of milk added = 15 litres

Final amount of milk = (7x + 15) litres

New amount of water added = 25 litres

Final amount of water added = (5x + 25) litres

Final ratio = 1 : 1

Now, as we know that

(Ratio of milk in the mixture + new quantity of milk added) : (Ratio of water in the mixture + new quantity of water added) = New ratio of mixture

\( \Rightarrow \frac{{7x + 15}}{{5x + 25}} = \frac{1}{1}\)

⇒ 7x + 15 = 5x + 25

⇒ 2x = 10

⇒ x = 5 litres

Now, quantity of milk in the new mixture = (7x + 15) litres

⇒ Quantity of milk in the new mixture = (7 × 5 + 15) litres

⇒ 50 litres