Search Previous Year Questions

Find real questions from previous competitive exam papers with answers and solutions.

Browse complete papers
1305 matching questions · Page 8
Clear

Question 71

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

Directions: Read the following caselet carefully and answer the questions that follow.

A company recorded the attendance of its employees over three consecutive working days—Monday, Tuesday and Wednesday. The total number of employees who attended during these three days was 750. The number of employees who attended on Monday, Tuesday and Wednesday was in the ratio 6 : 5 : 4, respectively. The ratio of Male to Female employees on Monday was 4 : 2, respectively. The number of Female employees on Tuesday was 25% more than the number of Female employees on Monday. The number of Male employees on Wednesday was 20 less than the number of Male employees on Tuesday.

If the number of Female employees on Wednesday increases by 20% and the number of Male employees on Monday decreases by 10%, then what will be the ratio of Female employees on Wednesday to Male employees on Monday?

  1. AOption (a)

    19:25

  2. BOption (b)

    19:30

  3. COption (c)

    19:32

  4. DOption (d)

    19:35

  5. EOption (e)

    19:41

View answer & explanation

Correct answer

Answer: (b)B.

19:30

Why this answer is correct

Common Calculation

Given:

Total employees = 750

Monday : Tuesday : Wednesday = 6 : 5 : 4

Male : Female on Monday = 4 : 2

Female on Tuesday = 25% more than Female on Monday

Male on Wednesday = 20 less than Male on Tuesday

Formula:

Number = (Ratio Share ÷ Total Ratio) × Total

Calculation:

⇒ Total parts = 6 + 5 + 4 = 15

⇒ Monday = (6/15) × 750 = 300

⇒ Tuesday = (5/15) × 750 = 250

⇒ Wednesday = (4/15) × 750 = 200

Monday

⇒ Male : Female = 4 : 2 = 2 : 1

⇒ Male = (2/3) × 300 = 200

⇒ Female = (1/3) × 300 = 100

Tuesday

⇒ Female = 100 × 125/100 = 125

⇒ Male = 250 – 125 = 125

Wednesday

⇒ Male = 125 – 20 = 105

⇒ Female = 200 – 105 = 95

Final Summary

DayMaleFemaleTotal
Monday200100300
Tuesday125125250
Wednesday10595200
Total430320750

Given:

Female employees on Wednesday = 95

Male employees on Monday = 200

Formula:

New Number = Original Number × (100 ± Percentage)/100

Calculation:

⇒ Female employees on Wednesday after 20% increase = 95 × 120/100 = 114

⇒ Male employees on Monday after 10% decrease = 200 × 90/100 = 180

⇒ Required ratio = 114 : 180 = 19 : 30

∴ Answer = 19 : 30

Question 72

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

Directions: Read the following caselet carefully and answer the questions that follow.

A company recorded the attendance of its employees over three consecutive working days—Monday, Tuesday and Wednesday. The total number of employees who attended during these three days was 750. The number of employees who attended on Monday, Tuesday and Wednesday was in the ratio 6 : 5 : 4, respectively. The ratio of Male to Female employees on Monday was 4 : 2, respectively. The number of Female employees on Tuesday was 25% more than the number of Female employees on Monday. The number of Male employees on Wednesday was 20 less than the number of Male employees on Tuesday.

Female employees on Monday and Wednesday together are what percent less than the Male employees on all three days together?

  1. AOption (a)

    45%

  2. BOption (b)

    50%

  3. COption (c)

    52%

  4. DOption (d)

    55%

  5. EOption (e)

    58%

View answer & explanation

Correct answer

Answer: (d)D.

55%

Why this answer is correct

Common Calculation

Given:

Total employees = 750

Monday : Tuesday : Wednesday = 6 : 5 : 4

Male : Female on Monday = 4 : 2

Female on Tuesday = 25% more than Female on Monday

Male on Wednesday = 20 less than Male on Tuesday

Formula:

Number = (Ratio Share ÷ Total Ratio) × Total

Calculation:

⇒ Total parts = 6 + 5 + 4 = 15

⇒ Monday = (6/15) × 750 = 300

⇒ Tuesday = (5/15) × 750 = 250

⇒ Wednesday = (4/15) × 750 = 200

Monday

⇒ Male : Female = 4 : 2 = 2 : 1

⇒ Male = (2/3) × 300 = 200

⇒ Female = (1/3) × 300 = 100

Tuesday

⇒ Female = 100 × 125/100 = 125

⇒ Male = 250 – 125 = 125

Wednesday

⇒ Male = 125 – 20 = 105

⇒ Female = 200 – 105 = 95

Final Summary

DayMaleFemaleTotal
Monday200100300
Tuesday125125250
Wednesday10595200
Total430320750

Given:

Female employees on Monday and Wednesday = 100 + 95

Male employees on all three days = 430

Formula:

Percentage = (Difference ÷ Original) × 100

Calculation:

⇒ Female employees on Monday and Wednesday = 100 + 95 = 195

⇒ Male employees on all three days = 200 + 125 + 105 = 430

⇒ Difference = 430 – 195 = 235

⇒ Required percentage = (235/430) × 100 = 54.65% ≈ 55%

∴ Answer = 55%

Question 73

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

Directions: Read the following caselet carefully and answer the questions that follow.

A company recorded the attendance of its employees over three consecutive working days—Monday, Tuesday and Wednesday. The total number of employees who attended during these three days was 750. The number of employees who attended on Monday, Tuesday and Wednesday was in the ratio 6 : 5 : 4, respectively. The ratio of Male to Female employees on Monday was 4 : 2, respectively. The number of Female employees on Tuesday was 25% more than the number of Female employees on Monday. The number of Male employees on Wednesday was 20 less than the number of Male employees on Tuesday.

If 25 Male employees are transferred from Monday to Wednesday, then what will be the ratio of Male employees on Monday to Wednesday?

  1. AOption (a)

    35:26

  2. BOption (b)

    35:22

  3. COption (c)

    35:28

  4. DOption (d)

    28:37

  5. EOption (e)

    37:26

View answer & explanation

Correct answer

Answer: (a)A.

35:26

Why this answer is correct

Common Calculation

Given:

Total employees = 750

Monday : Tuesday : Wednesday = 6 : 5 : 4

Male : Female on Monday = 4 : 2

Female on Tuesday = 25% more than Female on Monday

Male on Wednesday = 20 less than Male on Tuesday

Formula:

Number = (Ratio Share ÷ Total Ratio) × Total

Calculation:

⇒ Total parts = 6 + 5 + 4 = 15

⇒ Monday = (6/15) × 750 = 300

⇒ Tuesday = (5/15) × 750 = 250

⇒ Wednesday = (4/15) × 750 = 200

Monday

⇒ Male : Female = 4 : 2 = 2 : 1

⇒ Male = (2/3) × 300 = 200

⇒ Female = (1/3) × 300 = 100

Tuesday

⇒ Female = 100 × 125/100 = 125

⇒ Male = 250 – 125 = 125

Wednesday

⇒ Male = 125 – 20 = 105

⇒ Female = 200 – 105 = 95

Final Summary

DayMaleFemaleTotal
Monday200100300
Tuesday125125250
Wednesday10595200
Total430320750

Given:

Male Monday = 200

Male Wednesday = 105

Calculation:

⇒ Male employees on Monday after transfer = 200 – 25 = 175

⇒ Male employees on Wednesday after transfer = 105 + 25 = 130

⇒ Required ratio = 175 : 130 = 35 : 26

∴ Answer = 35 : 26

Question 74

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

Directions: Read the following caselet carefully and answer the questions that follow.

A company recorded the attendance of its employees over three consecutive working days—Monday, Tuesday and Wednesday. The total number of employees who attended during these three days was 750. The number of employees who attended on Monday, Tuesday and Wednesday was in the ratio 6 : 5 : 4, respectively. The ratio of Male to Female employees on Monday was 4 : 2, respectively. The number of Female employees on Tuesday was 25% more than the number of Female employees on Monday. The number of Male employees on Wednesday was 20 less than the number of Male employees on Tuesday.

The average number of employees attending on Monday and Wednesday together is how many more than the average number of employees attending on Tuesday?

  1. AOption (a)

    0

  2. BOption (b)

    5

  3. COption (c)

    10

  4. DOption (d)

    15

  5. EOption (e)

    20

View answer & explanation

Correct answer

Answer: (a)A.

0

Why this answer is correct

Common Calculation

Given:

Total employees = 750

Monday : Tuesday : Wednesday = 6 : 5 : 4

Male : Female on Monday = 4 : 2

Female on Tuesday = 25% more than Female on Monday

Male on Wednesday = 20 less than Male on Tuesday

Formula:

Number = (Ratio Share ÷ Total Ratio) × Total

Calculation:

⇒ Total parts = 6 + 5 + 4 = 15

⇒ Monday = (6/15) × 750 = 300

⇒ Tuesday = (5/15) × 750 = 250

⇒ Wednesday = (4/15) × 750 = 200

Monday

⇒ Male : Female = 4 : 2 = 2 : 1

⇒ Male = (2/3) × 300 = 200

⇒ Female = (1/3) × 300 = 100

Tuesday

⇒ Female = 100 × 125/100 = 125

⇒ Male = 250 – 125 = 125

Wednesday

⇒ Male = 125 – 20 = 105

⇒ Female = 200 – 105 = 95

Final Summary

DayMaleFemaleTotal
Monday200100300
Tuesday125125250
Wednesday10595200
Total430320750

Given:

Monday = 300

Tuesday = 250

Wednesday = 200

Formula:

Average = Sum of Observations ÷ Number of Observations

Calculation:

⇒ Average attendance on Monday and Wednesday = (300 + 200)/2 = 500/2 = 250

⇒ Average attendance on Tuesday = 250

⇒ Difference = 250 – 250 = 0

∴ Answer = 0

Question 75

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

Directions: Read the following caselet carefully and answer the questions that follow.

A company recorded the attendance of its employees over three consecutive working days—Monday, Tuesday and Wednesday. The total number of employees who attended during these three days was 750. The number of employees who attended on Monday, Tuesday and Wednesday was in the ratio 6 : 5 : 4, respectively. The ratio of Male to Female employees on Monday was 4 : 2, respectively. The number of Female employees on Tuesday was 25% more than the number of Female employees on Monday. The number of Male employees on Wednesday was 20 less than the number of Male employees on Tuesday.

Male employees on Tuesday and Wednesday together are what percent of the total employees on Monday?

  1. AOption (a)

    72.33%

  2. BOption (b)

    74%

  3. COption (c)

    76.67%

  4. DOption (d)

    80%

  5. EOption (e)

    83.33%

View answer & explanation

Correct answer

Answer: (c)C.

76.67%

Why this answer is correct

Common Calculation

Given:

Total employees = 750

Monday : Tuesday : Wednesday = 6 : 5 : 4

Male : Female on Monday = 4 : 2

Female on Tuesday = 25% more than Female on Monday

Male on Wednesday = 20 less than Male on Tuesday

Formula:

Number = (Ratio Share ÷ Total Ratio) × Total

Calculation:

⇒ Total parts = 6 + 5 + 4 = 15

⇒ Monday = (6/15) × 750 = 300

⇒ Tuesday = (5/15) × 750 = 250

⇒ Wednesday = (4/15) × 750 = 200

Monday

⇒ Male : Female = 4 : 2 = 2 : 1

⇒ Male = (2/3) × 300 = 200

⇒ Female = (1/3) × 300 = 100

Tuesday

⇒ Female = 100 × 125/100 = 125

⇒ Male = 250 – 125 = 125

Wednesday

⇒ Male = 125 – 20 = 105

⇒ Female = 200 – 105 = 95

Final Summary

DayMaleFemaleTotal
Monday200100300
Tuesday125125250
Wednesday10595200
Total430320750

Given:

Male employees on Tuesday = 125

Male employees on Wednesday = 105

Total employees on Monday = 300

Formula:

Percentage = (Part ÷ Total) × 100

Calculation:

⇒ Male employees on Tuesday and Wednesday = 125 + 105 = 230

⇒ Required percentage = (230 ÷ 300) × 100 = 76.67%

∴ Answer = 76.67%

Question 76

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

Directions

Two equations I and II are given in each question. On the basis of these equations decide the relation between x and y

I. 2x2 + 11x + 14 = 0

II. 2y2 + 17y + 33 = 0

  1. AOption (a)

    x > y

  2. BOption (b)

    x ≥ y

  3. COption (c)

    x < y

  4. DOption (d)

    x ≤ y

  5. EOption (e)

    x = y or the relationship cannot be established.

View answer & explanation

Correct answer

Answer: (e)E.

x = y or the relationship cannot be established.

Why this answer is correct

Equation I:

2x2 + 11x + 14 = 0

2x2 + 4x + 7x + 14 = 0

2x (x + 2) + 7 (x + 2) = 0

∴ x = -2 or x = -7/2

Equation II:

2y2 + 17y + 33 = 0

2y2 + 6y + 11y + 33 = 0

2y (y + 3) + 11 (y + 3) = 0

∴ y = -3 or y = -11/2

xyRelation between x and y
-2-3x > y
-2-11/2x > y
-7/2-3x < y
-7/2-11/2x > y

∴ x = y or the relationship cannot be established.

Question 77

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x2 + 5x – 14 = 0

II. y2 + 3y – 28 = 0

  1. AOption (a)

    x > y

  2. BOption (b)

    x < y

  3. COption (c)

    x ≥ y

  4. DOption (d)

    x ≤ y

  5. EOption (e)

    x = y or relationship between x and y cannot be established.

View answer & explanation

Correct answer

Answer: (e)E.

x = y or relationship between x and y cannot be established.

Why this answer is correct

I. x2 + 5x – 14 = 0

⇒ x2 – 2x + 7x – 14 = 0

⇒ x(x – 2) + 7(x – 2) = 0

⇒ (x – 2) (x + 7) = 0

⇒ x = 2, –7

II. y2 + 3y – 28 = 0

⇒ y2 + 7y – 4y – 28 = 0

⇒ y(y + 7) – 4(y + 7) = 0 

⇒ (y + 7) (y – 4) = 0

⇒ y = –7, 4

Value of xValue of yRelation
2–7x > y
24x < y
–7–7x = y
–74x < y

∴ The relationship between x and y cannot be established

Question 78

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. 3x2 - 43x + 154 = 0

II. 2y2 - 40y + 200 = 0

  1. AOption (a)

    x > y

  2. BOption (b)

    x < y

  3. COption (c)

    x ≥ y

  4. DOption (d)

    x ≤ y

  5. EOption (e)

    x = y or relationship between x and y cannot be established.

View answer & explanation

Correct answer

Answer: (b)B.

x < y

Why this answer is correct

I. 3x2 - 43x + 154 = 0

⇒ 3x2 - 22x - 21x + 154 = 0

⇒ (x - 7) (3x - 22) = 0

⇒ x = 7, 22/3

 

II. 2y2 - 40y + 200 = 0

⇒ 2y2 - 20y - 20y + 200 = 0

⇒ (y - 10) (2y - 20) = 0

⇒ y = 10, 10

Value of xValue of yRelation
710x < y
710x < y
22/310x < y
22/310x < y

 

Hence x < y

Question 79

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

Two trains X and Y start from station A and B simultaneously, travelling towards each other, train X takes 64 hours and train Y takes 100 hours to reach their respective stations after the meeting. What is the total time taken by the slower train to cover the whole distance?

  1. AOption (a)

    180 hours

  2. BOption (b)

    200 hours

  3. COption (c)

    144 hours

  4. DOption (d)

    150 hours

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

180 hours

Why this answer is correct

Given:

Two trains are running in opposite directions between stations A and B.

After crossing, the time taken by each train to reach their destination is 64 and 100 hours respectively.

Formula used:

After crossing each other, if the time taken by 2 trains is T1 and T2 respectively then, S1/S2 = √T2/√T1, here, S1 and S2 are speeds of first and second train respectively.

Calculations:

Let the time taken by slower train be T

We have, T1 = 64, T2 = 100

⇒ S1/S2 = √[100/64] = 5/4

⇒ S1 = (5/4)S2

Total distance covered = 64S1 + 100S2

⇒ 64[(5/4)S2] + 100S2

⇒ Distance = 180S2

 

⇒ T = Total distance/speed of slower train

 

⇒ T = 180S2/S2

 

⇒ T = 180 hours

∴ Time taken by slower train is 180 hours

Question 80

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

B alone can complete the work in 24 days and the efficiency of B is 25% less than that of A. A is double efficient than C. A, B and C together complete the work in x days. Which the following is true about the value of x?

  1. AOption (a)

    Perfect square Number

  2. BOption (b)

    Odd Number

  3. COption (c)

    Highest single digit number 

  4. DOption (d)

    Double of x is 18

  5. EOption (e)

    Perfect cube Number

View answer & explanation

Correct answer

Answer: (e)E.

Perfect cube Number

Why this answer is correct

Calculation

B alone completes the work in 24 days.

Efficiency of B is 25% less than A, so:

Efficiency of B = 0.75 × Efficiency of A

⇒Efficiency of A = [4/3] × Efficiency of B

A is twice as efficient as C, so,

Efficiency of C = [1/2] × Efficiency of A

Let’s assume Total Work = LCM of number of days

Since B completes in 24 days,

let’s take total work = LCM = 24 units × Efficiency of B

But to make calculation easier, assume:

Let Efficiency of B = 3 units/day

Then Total Work = 24 × 3 = 72 units

Efficiency of A = 4 units/day (since A is 4/3 of B)

Efficiency of C = 2 units/day (half of A)

So,

A + B + C efficiency = 4 + 3 + 2 = 9 units/day

Total work=72 units,

Daily combined work=9 units

⇒x = 72/9 = 8 days = perfect cube number

Page 8