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Question 61

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

Study the Bar Graph and Table given below and answer the questions that follow.

A total of 1150 items were manufactured by four companies, A, B, C, and D. The Bar Graph shows the number of items sold by each company, while the Table shows the difference between the number of items manufactured and sold. 

Difference = Manufactured Items − Sold Items

 

CompanyDifference between Manufactured and Sold Items
A60
B80
C50
D60

Find the ratio of the total number of items manufactured by companies A and B together to the total number of items sold by companies C and D together.

  1. AOption (a)

    51:49

  2. BOption (b)

    53:51

  3. COption (c)

    55:52

  4. DOption (d)

    52:49

  5. EOption (e)

    54:51

View answer & explanation

Correct answer

Answer: (b)B.

53:51

Why this answer is correct

CompanyItems SoldDifference between Manufactured and SoldItems ManufacturedUnsold Items
A18060180 + 60 = 24060
B21080210 + 80 = 29080
C24050240 + 50 = 29050
D27060270 + 60 = 33060
Total9002501150250

 

Total number of items manufactured by A and B = 240 + 290 = 530

Total number of items sold by C and D = 240 + 270 = 510

Required ratio = 530: 510 = 53: 51

Question 62

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

Study the Bar Graph and Table given below and answer the questions that follow.

A total of 1150 items were manufactured by four companies, A, B, C, and D. The Bar Graph shows the number of items sold by each company, while the Table shows the difference between the number of items manufactured and sold. 

Difference = Manufactured Items − Sold Items

 

CompanyDifference between Manufactured and Sold Items
A60
B80
C50
D60

If 20% of the items sold by company A and 10% of the items sold by company D were returned by customers, find the total number of items effectively sold by all four companies.

  1. AOption (a)

    827

  2. BOption (b)

    837

  3. COption (c)

    847

  4. DOption (d)

    857

  5. EOption (e)

    867

View answer & explanation

Correct answer

Answer: (b)B.

837

Why this answer is correct

CompanyItems SoldDifference between Manufactured and SoldItems ManufacturedUnsold Items
A18060180 + 60 = 24060
B21080210 + 80 = 29080
C24050240 + 50 = 29050
D27060270 + 60 = 33060
Total9002501150250

 

Total number of items sold = 180 + 210 + 240 + 270 = 900

Number of items returned from company A = 20% of 180 = 36

Number of items returned from company D = 10% of 270 = 27

Total number of items effectively sold = 900 − 36 – 27 = 837

Question 63

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

Study the Bar Graph and Table given below and answer the questions that follow.

A total of 1150 items were manufactured by four companies, A, B, C, and D. The Bar Graph shows the number of items sold by each company, while the Table shows the difference between the number of items manufactured and sold. 

Difference = Manufactured Items − Sold Items

 

CompanyDifference between Manufactured and Sold Items
A60
B80
C50
D60

Find the ratio of the number of unsold items of companies B and C.

  1. AOption (a)

    5:3

  2. BOption (b)

    8:5

  3. COption (c)

    7:4

  4. DOption (d)

    3:2

  5. EOption (e)

    9:5

View answer & explanation

Correct answer

Answer: (b)B.

8:5

Why this answer is correct

CompanyItems SoldDifference between Manufactured and SoldItems ManufacturedUnsold Items
A18060180 + 60 = 24060
B21080210 + 80 = 29080
C24050240 + 50 = 29050
D27060270 + 60 = 33060
Total9002501150250

 

Number of unsold items of B : Number of unsold items of C = 80 : 50 = 8 : 5

Question 64

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

A 180-litre mixture contains milk and water in the ratio of 5:4 respectively. 25% mixture are removed and then 15 litres of milk are added. If the final mixture contains [x + 10] % milk and [y + 10] % water. Find the value of x + y?

  1. AOption (a)

    80

  2. BOption (b)

    85

  3. COption (c)

    64

  4. DOption (d)

    98

  5. EOption (e)

    72

View answer & explanation

Correct answer

Answer: (a)A.

80

Why this answer is correct

Calculation

Initial mixture = 180 litres

Milk : Water = 5 : 4

⇒ Total parts = 5 + 4 = 9

⇒ Milk = [5/9] × 180 = 100 L

⇒ Water = [4/9] × 180 = 80 L

Remove 25% of mixture

25% of 180 = 45 litres removed

Milk removed = [100/180] × 45=25 L

Water removed = [80/180] × 45 = 20

After removal:

Milk left = 100 – 25 = 75 L

Water left = 80 – 20 = 60 L

Add 15 litres of milk

Milk = 75 + 15 = 90 L

Water = 60 L

Total = 90 + 60 = 150 L

Milk % = [90/150] × 100 =60%

⇒ x + 10 = 60

⇒ x = 50

Water % = [60/150] × 100 = 40%

⇒ y + 10 = 40 ⇒ y = 30

So, x + y = 80

Question 65

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

After a 25% initial discount on the marked price of an item, a shopkeeper offers a 20% additional discount on the discounted price. If the final sale price of the article is Rs. 600, then what is its marked price?

  1. AOption (a)

    Rs. 680

  2. BOption (b)

    Rs. 725

  3. COption (c)

    Rs. 1000

  4. DOption (d)

    Rs. 1070

  5. EOption (e)

    Rs. 1200

View answer & explanation

Correct answer

Answer: (c)C.

Rs. 1000

Why this answer is correct

Given:

1st Discount = 25% of M.P

2nd Discount = 20% of 1st Discount

S.P = Rs. 600

Concept Used:

D = M.P × Rate of Discount 

Successive Discount = [a + b - (ab/100)]%

M.P = Marked Price, D = Discount, S.P = Selling Price

Calculation:

Let the marked price be x.

According to the question,

x × (75/100) × (80/100) = 600

⇒ x = (600 × 100 × 100)/(75 × 80)

⇒ x = 1000

∴ The Marked Price is Rs. 1000.

Question 66

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

The ratio of the speed of the stream to the speed of the boat in still water is 4 : 9. Time taken by the boat to cover 270 km upstream in t hours and the same boat to cover 468 km downstream in (t - 6) hours. Find the distance covered by the boat in still water in 8 hours.

  1. AOption (a)

    180 km

  2. BOption (b)

    360 km

  3. COption (c)

    288 km

  4. DOption (d)

    216 km

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

216 km

Why this answer is correct

Shortcut Trick

Ratio of Stream Speed (v) : Still Water Speed (u) = 4 : 9

Upstream Speed (u−v) = 5 units | Downstream Speed (u+v) = 13 units

Ratio of Distances: 270 / 468 = 15 : 26

Using Time = Distance / Speed: (15/5) / (26/13) = 3 : 2 (Time Ratio)

Difference (3−2) = 1 unit → 6 hours ∴ Still speed = 27 kmph

∴ The correct answer is 216 km.

Alternate Method

Given: Ratio v : u = 4 : 9. Upstream dist = 270 km, Downstream dist = 468 km.

Formula: Distance = Speed × Time

⇒ Let u = 9x and v = 4x. Upstream speed = 5x, Downstream speed = 13x.

⇒ 270 / 5x = t and 468 / 13x = t − 6

⇒ 54/x = t and 36/x = t − 6

⇒ 54/x − 36/x = 6 ⇒ 18/x = 6 ⇒ x = 3

⇒ Speed of boat in still water = 9 × 3 = 27 kmph

⇒ Distance in 8 hours = 27 × 8 = 216 km

∴ The correct answer is 216 km.

Additional Information

Downstream Speed

The effective speed of the boat when traveling in the same direction as the stream. Downstream = u + v.

Upstream Speed

The effective speed of the boat when traveling against the direction of the stream. Upstream = u − v.

Still Water Calculation

Speed of boat in still water (u) = (Downstream + Upstream) ÷ 2.

Question 67

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

A invests Rs. X at rate of 20% p.a. compound interest for 2 years. At the end of 2 years, he received Rs. 1698.4 as interest. If he invests Rs. 'X + 500' at the rate of 23% simple interest for 3.5 years, then find simple interest received by him.

  1. AOption (a)

    3964.8

  2. BOption (b)

    3509.8

  3. COption (c)

    3254.8

  4. DOption (d)

    3658.8

  5. EOption (e)

    3478.8

View answer & explanation

Correct answer

Answer: (b)B.

3509.8

Why this answer is correct

Given:

Compound Interest Rate = 20% p.a.

Time = 2 years

CI = ₹1698.4

New Principal = X + 500

Simple Interest Rate = 23% p.a.

Time = 3.5 years

Formula used:

CI = P\([(1+\frac{r}{100})^t - 1 ]\)

SI = (P × R × T) ÷ 100

Calculations:

⇒ 1698.4 = X × ((1 + 20/100)2 - 1)

⇒ 1698.4 = X × (1.44 - 1) = X × 0.44

⇒ X = 1698.4 ÷ 0.44 = 3860

Now, New Principal = X + 500 = 3860 + 500 = ₹4360

⇒ SI = 4360 × 23 × 3.5 ÷ 100 = 3509.8

∴ Simple Interest received = ₹3509.8

Question 68

IBPS Probationary Officer (PO) 2026• Quantitative Aptitude• Quantitative Aptitude

10 years ago, the ratio of the age of mother and daughter was 5: 2. 8 years hence, the respective ratio of the age of mother and daughter will become 7: 4. If the age of the father is 5 years more than the present age of the mother. Find the sum of the age of father and daughter 10 years ago.

  1. AOption (a)

    81

  2. BOption (b)

    79

  3. COption (c)

    68

  4. DOption (d)

    77

  5. EOption (e)

    76

View answer & explanation

Correct answer

Answer: (c)C.

68

Why this answer is correct

Solution:

10 years ago, let the age of mother = 5x years, age of daughter = 2x years

Present Age of mother = 5x + 10

Present Age of daughter = 2x + 10

8 years hence, mother age = 5x + 18 years

Daughter age = 2x + 18 years

(5x+18)/ (2x+18) = 7:4

x = 9

Present age of mother = (5 × 9 + 10) = 45 = 55

Present age of daughter = (2 × 9 + 10) = 28

Present age of father = (55 + 5) = 60

Therefore the age of father and daughter 10 years ago = (60 + 28 - 20) = 68

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