Find real questions from previous competitive exam papers with answers and solutions.
Browse complete papersIn the following number series, a wrong number is given. Find out the wrong number.
225, 226, 231, 257, 273, 398
225
226
231
273
398
Correct answer
231
Why this answer is correct
Calculation:
The logic follows here is:
⇒ 225 + 13 = 226
⇒ 226 + 22 = 230
⇒ 230 + 33 = 257
⇒ 257 + 42 = 273
⇒ 273 + 53 = 398
∴ 230 is the wrong term.
In the following number series, a wrong number is given. Find out the wrong number.
2, 26, 286, 2004, 10010, 30030
26
2004
286
2
30030
Correct answer
2004
Why this answer is correct
2 × 13 = 26,
26 × 11 = 286,
286 × 7 = 2002,
2002 × 5 = 10010,
10010 × 3 = 30030.
The wrong term is 2004.
In each of the following number series, the wrong number is given, find out that number.
30, 16, 18, 26, 64, 165
30
64
165
18
26
Correct answer
26
Why this answer is correct
The series follows the following pattern:
30 × 0.5 + 1 = 16
16 × 1 + 2 = 18
18 × 1.5 + 3 = 30
30 × 2 + 4 = 64
64 × 2.5 + 5 = 165
∴ The wrong term in the series is 26.
The number of shirts sold by Shop A is [4/3] times the number of pants sold by Shop A. Ratio of number of shirts and pants sold in shop D is 7:6. The total number of pants sold by A, B and C together is 163. Shop B sold 10 more shirts than the number of pants it sold. The total number of items (shirts + pants) sold by Shop C is 90. The number of pants sold by Shop C is 25% more than the number of shirts sold by Shop C. Number of pants sold in shop B is 17 more than the pants sold in shop A. Number of shirts sold in shop D is five less than the same in shop B.
The total number of items (shirts + pants) sold by Shop A and B together is [n + 22]. Find the value of 8n + 22?
1147
1642
1442
1112
1862
Correct answer
1862
Why this answer is correct
Common Calculation
Let, Pants sold in Shop A is x.
Then, shirts sold in A = [4/3]x
Shop B sold 10 more shirts than pants
Let pants sold in B = y
→ shirts sold in B = y + 10
Pants in B is 17 more than in A
→ y =x + 17
⇒ x = y – 17
Total pants in A, B, and C = 163
Let pants sold in C = z
So: [x + y + z] = 163
Shop C total items = 90
Let shirts in C = a
Then: [a + z ] = 90 ---------à (II)
Pants in C = 25% more than shirts
→ z = 1.25a
z = 1.25a,
So, a + z = 90
⇒ a + 1.25a = 90
⇒ 2.25a = 90
⇒ a = 40, z = [1.25 × 40] = 50
So, x + y = 113
Or, y – 17 + y = 113
Or, y = [130/2] = 65
So, x = 65 – 17 = 48
Now, Shirts sold in A = [4/3] × 48 = 64
Shirts sold in B = y + 10=75
Shirts in D is 5 less than in B
→ Shirts sold in D = y + 10 − 5 = y + 5 = 65 + 5 = 70
Ratio of shirts : pants in D = 7 : 6
So, Number of pants sold in D is 70 × 6 / 7 = 60
| Shop | Number of shirts sold | Number Pants sold |
|---|---|---|
| A | 64 | 48 |
| B | 75 | 65 |
| C | 40 | 50 |
| D | 70 | 60 |
Calculation
Total items in A + B = [n + 22]
Items in A = 64 + 48 = 112
Items in B = 75 + 65 = 140
→ Total = 112 + 140 = 252
So, n + 22 = 252
⇒ n = 230
⇒8n + 22 = [(8 × 230) + 22] = 1840 + 22 = 1862
The number of shirts sold by Shop A is [4/3] times the number of pants sold by Shop A. Ratio of number of shirts and pants sold in shop D is 7:6. The total number of pants sold by A, B and C together is 163. Shop B sold 10 more shirts than the number of pants it sold. The total number of items (shirts + pants) sold by Shop C is 90. The number of pants sold by Shop C is 25% more than the number of shirts sold by Shop C. Number of pants sold in shop B is 17 more than the pants sold in shop A. Number of shirts sold in shop D is five less than the same in shop B.
Number of watches sold in shop D is the average number of pants sold in Shops A and C. Number of watch sold in shop C is 25 more than the number of watches sold in D. Find number of watches sold in shop C.
76
88
96
74
99
Correct answer
74
Why this answer is correct
Common Calculation
Let, Pants sold in Shop A is x.
Then, shirts sold in A = [4/3]x
Shop B sold 10 more shirts than pants
Let pants sold in B = y
→ shirts sold in B = y + 10
Pants in B is 17 more than in A
→ y =x + 17
⇒ x = y – 17
Total pants in A, B, and C = 163
Let pants sold in C = z
So: [x + y + z] = 163
Shop C total items = 90
Let shirts in C = a
Then: [a + z ] = 90 ---------à (II)
Pants in C = 25% more than shirts
→ z = 1.25a
z = 1.25a,
So, a + z = 90
⇒ a + 1.25a = 90
⇒ 2.25a = 90
⇒ a = 40, z = [1.25 × 40] = 50
So, x + y = 113
Or, y – 17 + y = 113
Or, y = [130/2] = 65
So, x = 65 – 17 = 48
Now, Shirts sold in A = [4/3] × 48 = 64
Shirts sold in B = y + 10=75
Shirts in D is 5 less than in B
→ Shirts sold in D = y + 10 − 5 = y + 5 = 65 + 5 = 70
Ratio of shirts : pants in D = 7 : 6
So, Number of pants sold in D is 70 × 6 / 7 = 60
| Shop | Number of shirts sold | Number Pants sold |
|---|---|---|
| A | 64 | 48 |
| B | 75 | 65 |
| C | 40 | 50 |
| D | 70 | 60 |
Calculation
Watches in D = Average of pants in A and C
→ A pants = 48, C pants = 50
→ Average = (48 + 50)/2 = 49
→ D watches = 49
→ C watches = 49 + 25 = 74
The number of shirts sold by Shop A is [4/3] times the number of pants sold by Shop A. Ratio of number of shirts and pants sold in shop D is 7:6. The total number of pants sold by A, B and C together is 163. Shop B sold 10 more shirts than the number of pants it sold. The total number of items (shirts + pants) sold by Shop C is 90. The number of pants sold by Shop C is 25% more than the number of shirts sold by Shop C. Number of pants sold in shop B is 17 more than the pants sold in shop A. Number of shirts sold in shop D is five less than the same in shop B.
Across all four shops A to D, if each shirt sold earns Rs. 500 and each pant sold earns Rs. 400, Find the difference between total revenue generated by selling shirt and pants?
36500
36940
35300
32000
34500
Correct answer
35300
Why this answer is correct
Common Calculation
Let, Pants sold in Shop A is x.
Then, shirts sold in A = [4/3]x
Shop B sold 10 more shirts than pants
Let pants sold in B = y
→ shirts sold in B = y + 10
Pants in B is 17 more than in A
→ y =x + 17
⇒ x = y – 17
Total pants in A, B, and C = 163
Let pants sold in C = z
So: [x + y + z] = 163
Shop C total items = 90
Let shirts in C = a
Then: [a + z ] = 90 ---------à (II)
Pants in C = 25% more than shirts
→ z = 1.25a
z = 1.25a,
So, a + z = 90
⇒ a + 1.25a = 90
⇒ 2.25a = 90
⇒ a = 40, z = [1.25 × 40] = 50
So, x + y = 113
Or, y – 17 + y = 113
Or, y = [130/2] = 65
So, x = 65 – 17 = 48
Now, Shirts sold in A = [4/3] × 48 = 64
Shirts sold in B = y + 10=75
Shirts in D is 5 less than in B
→ Shirts sold in D = y + 10 − 5 = y + 5 = 65 + 5 = 70
Ratio of shirts : pants in D = 7 : 6
So, Number of pants sold in D is 70 × 6 / 7 = 60
| Shop | Number of shirts sold | Number Pants sold |
|---|---|---|
| A | 64 | 48 |
| B | 75 | 65 |
| C | 40 | 50 |
| D | 70 | 60 |
Calculation
Shirts earn Rs. 500, pants Rs. 400
We calculate shirt revenue and pant revenue across A–D
Shirts Total: A: 64, B: 75, C: 40 , D: 70
→ Total = 64 + 75 + 40 + 70 = 249
Pants Total: A: 48, B: 65 , C: 50 , D: 60
→ Total = 48 + 65 + 50 + 60 = 223
Revenue: Shirt revenue = 249 × 500 = Rs. 124500
Pant revenue = 223 × 400 = Rs. 89200
Difference = 124500 − 89200 = 35300
The number of shirts sold by Shop A is [4/3] times the number of pants sold by Shop A. Ratio of number of shirts and pants sold in shop D is 7:6. The total number of pants sold by A, B and C together is 163. Shop B sold 10 more shirts than the number of pants it sold. The total number of items (shirts + pants) sold by Shop C is 90. The number of pants sold by Shop C is 25% more than the number of shirts sold by Shop C. Number of pants sold in shop B is 17 more than the pants sold in shop A. Number of shirts sold in shop D is five less than the same in shop B.
The difference between shirts sold by Shop C and pants sold by Shop D is m. Find the value of 7m?
190
140
150
160
170
Correct answer
140
Why this answer is correct
Common Calculation
Let, Pants sold in Shop A is x.
Then, shirts sold in A = [4/3]x
Shop B sold 10 more shirts than pants
Let pants sold in B = y
→ shirts sold in B = y + 10
Pants in B is 17 more than in A
→ y =x + 17
⇒ x = y – 17
Total pants in A, B, and C = 163
Let pants sold in C = z
So: [x + y + z] = 163
Shop C total items = 90
Let shirts in C = a
Then: [a + z ] = 90 ---------à (II)
Pants in C = 25% more than shirts
→ z = 1.25a
z = 1.25a,
So, a + z = 90
⇒ a + 1.25a = 90
⇒ 2.25a = 90
⇒ a = 40, z = [1.25 × 40] = 50
So, x + y = 113
Or, y – 17 + y = 113
Or, y = [130/2] = 65
So, x = 65 – 17 = 48
Now, Shirts sold in A = [4/3] × 48 = 64
Shirts sold in B = y + 10=75
Shirts in D is 5 less than in B
→ Shirts sold in D = y + 10 − 5 = y + 5 = 65 + 5 = 70
Ratio of shirts : pants in D = 7 : 6
So, Number of pants sold in D is 70 × 6 / 7 = 60
| Shop | Number of shirts sold | Number Pants sold |
|---|---|---|
| A | 64 | 48 |
| B | 75 | 65 |
| C | 40 | 50 |
| D | 70 | 60 |
Calculation
m= Difference between shirts in C and pants in D
→ C shirts = 40, D pants = 60
So, m = 60 – 40 = 20
⇒ 7m = 7 × 20 = 140
The number of shirts sold by Shop A is [4/3] times the number of pants sold by Shop A. Ratio of number of shirts and pants sold in shop D is 7:6. The total number of pants sold by A, B and C together is 163. Shop B sold 10 more shirts than the number of pants it sold. The total number of items (shirts + pants) sold by Shop C is 90. The number of pants sold by Shop C is 25% more than the number of shirts sold by Shop C. Number of pants sold in shop B is 17 more than the pants sold in shop A. Number of shirts sold in shop D is five less than the same in shop B.
The number of shirts sold in shop E is 20 more than the number of shirts sold in shop C. Number pants sold in shop E is same as shop B. Find total number of items [ shirt + pant] sold in shop E?
124
159
137
224
125
Correct answer
125
Why this answer is correct
Common Calculation
Let, Pants sold in Shop A is x.
Then, shirts sold in A = [4/3]x
Shop B sold 10 more shirts than pants
Let pants sold in B = y
→ shirts sold in B = y + 10
Pants in B is 17 more than in A
→ y =x + 17
⇒ x = y – 17
Total pants in A, B, and C = 163
Let pants sold in C = z
So: [x + y + z] = 163
Shop C total items = 90
Let shirts in C = a
Then: [a + z ] = 90 ---------à (II)
Pants in C = 25% more than shirts
→ z = 1.25a
z = 1.25a,
So, a + z = 90
⇒ a + 1.25a = 90
⇒ 2.25a = 90
⇒ a = 40, z = [1.25 × 40] = 50
So, x + y = 113
Or, y – 17 + y = 113
Or, y = [130/2] = 65
So, x = 65 – 17 = 48
Now, Shirts sold in A = [4/3] × 48 = 64
Shirts sold in B = y + 10=75
Shirts in D is 5 less than in B
→ Shirts sold in D = y + 10 − 5 = y + 5 = 65 + 5 = 70
Ratio of shirts : pants in D = 7 : 6
So, Number of pants sold in D is 70 × 6 / 7 = 60
| Shop | Number of shirts sold | Number Pants sold |
|---|---|---|
| A | 64 | 48 |
| B | 75 | 65 |
| C | 40 | 50 |
| D | 70 | 60 |
Calculation
Shirts in E = 20 more than shirts in C
→ Shirts in E = 40 + 20 = 60
Pants in E = same as in B = 65
Total items in E = 60 + 65 = 125
A, B, and C can complete a work in 16, 24, and 32 days respectively. They all started the work together, but B left after working 3 days, and C left 5 days before the completion of the work. In how may days the work get completed?
8 days
9 days
10 days
11 days
12 days
Correct answer
11 days
Why this answer is correct
Given:
A, B, and C can complete a work in 16, 24, and 32 days respectively
They all started the work together, but B left after working 3 days
C left 5 days before the completion of the work
Concept Used:
Work done = efficiency × time
Calculation:
Total work = LCM of (16, 24, 32) = 96 units
The efficiency of A = 96/16 = 6 unit/day
The efficiency of B = 96/24 = 4 unit/day
The efficiency of C = 96/32 = 3 unit/day
Let, the work get completed in T days
According to the question,
⇒ 6T + 4 × 3 + 3 × (T - 5) = 96
⇒ 6T + 12 +3T - 15 = 96
⇒ 9T = 99
⇒ T = 11 days
∴ The work is completed in 11 days
The difference between simple interest and compound interest on a certain amount of money for 2 years is Rs. 4.20. The rate of interest per annum is 5% (both S.I and C.I). Find the sum of money.
Rs. 1180
Rs. 1680
Rs. 1580
Rs. 1980
Rs. 1780
Correct answer
Rs. 1680
Why this answer is correct
Shortcut Trick
Sum = Difference × (100/rate)2 [Only for two years]
Here, Difference = Rs. 4.20, Rate = 5%,
Sum = (4.20) × (100/5)2 = Rs. 1680
∴ The sum of money is Rs. 1680.
Traditional method:
Given:
The difference between simple interest and compound interest is Rs. 4.20
Total time period = 2 years
Rate = 5%
Formula used:
S.I = (PRT)/100
Where S.I = Simple interest, P = Principal, R = Rate, T = Time
C.I = P[{1 + (r/100)}n - 1]
Where C.I = Compound interest, P = Pricipal, r = rate, n = time period
Calculation:
Let, the sum be P
Here, T = 2 years, R = 5%
So, S.I = (P × 5 × 2)/100 = (P/10)
Again, n = 2 years, r = 5%
So, C.I = P[{1 + (5/100)}2 - 1]
⇒ C.I = P[{1 + (1/20)}2 - 1]
⇒ C.I = P[(441/400) - 1]
⇒ C.I = P[41/400]
Now, according to the question, we can say,
P[41/400] - (P/10) = 4.2
⇒ P[(41/400) - (1/10)] = 4.2
⇒ P[(41 - 40)/400] = 4.2
⇒ P[1/400] = 4.2
⇒ P = 4.2 × 400 = 1680
∴ The sum of money is Rs. 1680.