Search Previous Year Questions

Given:

Two stations A and B are 180 km apart

Two trains meet after 5 hours

The local train is 4 km/hr faster than the goods train

Concept Used:

Distance = speed × time

Calculation:

Let, the speed of the goods train = A km/hr

And, speed of local train = (A + 4) km/hr

According to the question,

⇒ 180/(A + A + 4) = 5

⇒ 2A = 32

⇒ A = 16

The speed of the local train = (16 + 4) = 20 km/hr

∴ The correct answer is option 1

Calculation

A + B can complete work in 40 days

B + C can complete work in 60 days

A + C can complete work in 30 days

A + B + C complete 3/2 work together

Total wage = Rs. 5400

We are to find C's share.

Take total work as LCM of 40, 60, 30

LCM of 40, 60, and 30 = 120 units

Now we compute the combined efficiencies:

A + B = 120 / 40 = 3 units/day

B + C = 120 / 60 = 2 units/day

A + C = 120 / 30 = 4 units/day

Let’s add:

(A+B) + (B+C) + (A+C) = 3+2+4=9 units/day

A+B+C = 9/2 = 4.5 units/day

Total work done by A + B + C

They complete 3/2 of total work.

Total work = 120 units

⇒ 3/2 × 120 = 180 units

Since A + B + C = 4.5 units/day:

Days = 180 / 4.5 = 40 days

C’s efficiency = 4.5 – 3 = 1.5

In 40 days C did 40  × 1.5 = 60 unit work

Wage for per unit work is 5400 / 180 = 30

So, C’s wage = 60 × 30 = 1800

Given Series:

3375, 289, 6859, 441, 12167, (?)

The logic followed here is as follows:

⇒ (15)³ = 3375

⇒ (17)² = 289

⇒ (19)³ = 6859

⇒ (21)² = 441

⇒ (23)³ = 12167

⇒ (25)² = 625

Hence, 625 will come in the place of (?).

Given Series:

1220, 1617, 2086, 2633, 3264, (?)

The logic followed here is as follows:

⇒ (11)³ - 111 = 1220

⇒ (12)³ - 111 = 1617

⇒  (13)3 - 111 = 2086

⇒  (14)3 - 111 = 2633

⇒  (15)3 - 111 = 3264

⇒  (16)3 - 111 = 3985

Hence, 3985 will come in the place of (?).

Given Series:

2, 12, 130, 56, (?), 132

The logic followed here is as follows:

⇒ 1 + 1³ = 2

⇒ 3 + 3² = 12

⇒ 5 + 5³ = 130

⇒ 7 + 7² = 56

⇒ 9 + 9³ = 738

⇒ 11 + 11² = 132

Hence, 738 will come in the place of (?).

Original candidates in centre A,

Male = 250 and Female = 200

Seventy candidates are transferred from E to A in the ratio = 4:3

Total parts = 4 + 3 = 7

Male candidates transferred to A = 70 x 4/7 = 40

Female candidates transferred to A = 70 x 3/7 = 30

Also, 20% of the original female candidates of A are transferred to E.

20% x 200 = 40

Therefore, the new number of male candidates in A = 250 + 40 = 290

The new number of female candidates in A = 200 + 30 – 40 = 190

Required ratio = 290:190 = 29:19

New males in D = 120% x 210 = 252

New females = 90% x 150 = 135

New total = 252 + 135 = 387

Required Difference = 550 – 387 = 163