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By using the symbols in the table given below, we can draw the following family tree:

Clearly, C is the wife of P.

Hence, ‘Wife’ is the correct answer.

The logic followed here is:

As we know that the year 2000 is divisible by 400, and so the number of odd days = 0.

Next, the number of leap years till 2010 = 2 i.e. 2004 and 2008.

And, the number of ordinary years till 2010 = 8

So, the total number of odd days will be till 2011 is

= 8 + 2(2) = 12 odd days

Again, the total number of odd days till 19^th Feb 2011 

= 12 + 31 (Jan) + 19 (Feb)

= 62 odd days = 8 weeks and 6 odd days

 

Thus, the day on 19^th Feb 2011 is Saturday.

Hence, the correct answer is 'option 2'.

The logic followed here is:

Similarly,

Hence, "option 2" is the correct answer.

According to given information-

• Number of persons = 6
• Name of persons -  Raj, Shruti, Priya, Mohan, Ajit and Geet

​• Mohan is second from Priya's right and Priya is third from Raj's left.

• Ajit is second from Mohan's right and Geet is not Mohan's neighbour. Thus, final arrangement will be-

Clearly, Raj is sitting fourth to the right of Geet.

Hence, 'option 3' is the correct answer.

BODMAS RULE:

 

 

 

 

 

 

 

Given equation is  18 × 7 ÷ 36 + 78 - 14 = 86

 

Option 1):

By interchanging (6 and 4) and (- and +) in the given equation

Interchanged equation is : 18 × 7 ÷ 34 - 78 +16 = 86

⇒  18 × 0.206 - 78 +16 = 86

⇒   3.708 – 78 + 16 = 86

⇒   3.708 + 16 – 78 = 86

⇒   19.708  - 78 = 86

⇒   - 58.292 ≠ 86

⇒   LHS ≠ RHS

Option 2):

By interchanging (1 and 4) and (×  and ÷) in the given equation

Interchanged equation is : 48 ÷ 7 ×  36 + 78  - 41 = 86

⇒ 6.86 × 36 + 78 – 41 = 86

⇒ 246.96 + 78 – 41 = 86

⇒ 324.96 – 41 = 86

⇒ 283.96 ≠ 86

⇒ LHS ≠ RHS

Option 3):

By interchanging (3 and 4) and (×  and +) in the given equation

Interchanged equation is : 18 + 7 ÷  46 × 78  - 13 = 86

⇒ 18 + 0.152 × 78 – 13 = 86

⇒ 18 + 11.856 – 13 = 86

⇒ 29.856 – 13 = 86

⇒  16.856 ≠ 86

⇒ LHS ≠ RHS

Option 4):                                                   

By interchanging (4 and 3) and (÷ and -) in the given equation

Interchanged equation is : 18 × 7 – 46 + 78 ÷ 13 = 86

⇒  18 × 7 – 46 + 6 = 86

⇒  126 – 46 + 6 = 86

⇒ 126 + 6 – 46 = 86

⇒  132 – 46 = 86

⇒  LHS = RHS                                                                       

Hence, option 4 is the correct answer.

As per the given information,

• A stands in the 13^th position from the front of the queue and there are 2 persons between A and B. B stands after A:

• If the first 8 persons are removed from the queue:

Here, when the first 8 persons are removed from the queue, A becomes 5^th from the front. Thus, the position of B will be '8^th'.

Thus, the position of B from the front of the queue is '8^th'.

Hence, the correct answer is "8".

The logic followed here is:

Hence, 'XMCV' is the correct answer.

According to the given information,

1) Peter departs from his home and walks 10 m towards north.

   

2. She then turns right and walks 36 m.

3) He turns left and walks 5 m. 

4) Now he turns left again and walks 25 m and stops.

5) A pole is placed exactly 15 m south from where he is standing.

Hence, the correct answer is "11 m, west".

BODMAS:

By decoding given information:

By interchanging the signs and using BODMAS rule, we get:

117 × 6 ÷ 9 × 2 + 25 - 52 = ?

117 × $2\over 3$ × 2  + 25  - 52 = ?

39 × 2 × 2 + 25 - 52 = ?

156 + 25 - 52 = ?

156 - 27 = 129

Hence, the correct answer is "129".

The position of letters according to the English alphabet series:

‘MISERY’ is written as ‘LJHPBO’

Similarly,

‘PRAISE’ be written '?'

Hence, the correct answer is "UMLXHP".