Shortcut Trick
For questions involving the median of algebraic terms, the fastest approach is to test the given options directly.
Test Option 1 (x = 3):
Substitute x = 3 into the set {x + 4, 2x − 3, 5x, x + 1, 3x + 2}.
The values become {7, 3, 15, 4, 11}.
Arranging in ascending order gives: 3, 4, 7, 11, 15.
The middle term (median) is 7, which perfectly matches the question's given condition.
∴ The correct answer is 3.
Alternate Method
Given:
Data set = {x + 4, 2x − 3, 5x, x + 1, 3x + 2}
Condition: x > 1, where x is a natural number.
Median = 7
Formula Used:
The median of an odd number of terms is the middle value when arranged in ascending order: ((n + 1) ÷ 2)th term.
1<sup>st</sup> 2<sup>nd</sup> Median 4<sup>th</sup> 5<sup>th</sup> 2x − 3 x + 1 x + 4 = 7 3x + 2 5x Ascending Order of Terms (For x = 3)
Calculations:
⇒ Total number of terms (n) = 5.
⇒ The median will be the 3rd term when sorted in ascending order.
⇒ Let's analyze the relative values of the given expressions for x > 1.
⇒ Clearly, 5x and 3x + 2 will be the largest terms in the set.
⇒ The three smallest terms are x + 1, 2x − 3, and x + 4.
⇒ If 2x − 3 were the median, 2x − 3 = 7 ⇒ x = 5. However, substituting x = 5 gives {9, 7, 25, 6, 17}, which has a median of 9, not 7.
⇒ Thus, x + 4 naturally takes the 3rd position and acts as the true median.
⇒ Equating the 3rd term to the given median: x + 4 = 7.
⇒ x = 7 − 4 = 3.
∴ The correct answer is 3.
Additional Information
Median of Ungrouped Data
To find the median, arrange the data in ascending or descending order. If n is odd, the median is the ((n + 1) ÷ 2)th term. If n is even, it is the average of the (n ÷ 2)th and (n ÷ 2 + 1)th terms.
Mean vs Median
The mean is sensitive to extreme values (outliers), whereas the median provides a more robust and stable measure of central tendency for skewed distributions.
Mode of Data
The mode is the value that appears most frequently in a given data set. A dataset can have a single mode, multiple modes, or no mode at all if all values are unique.