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Question 81

GATE CE 2024• Civil Engineering

In general, the outer edge is raised above the inner edge in horizontal curves for

  1. AOption (a)

    Highways and Railways only

  2. BOption (b)

    Highways only

  3. COption (c)

    Railways and Taxiways only

  4. DOption (d)

    Highways, Railways and Taxiways

View answer & explanation

Correct answer

Answer: (a)A.

Highways and Railways only

Why this answer is correct

Explanation:

The concept of raising the outer edge above the inner edge in horizontal curves is known as super-elevation (cant or banking) and is primarily used in:

  1. Highways – To counteract centrifugal force on vehicles, reducing the risk of skidding and overturning.
  2. Railways – To provide a smooth transition for trains on curves, reducing lateral forces and rail wear.

However, taxiways generally do not require super-elevation because aircraft move at lower speeds on taxiways, and the main concern is ensuring smooth, level surfaces for ground maneuvering rather than counteracting lateral forces.

Thus, the correct choice is Highways and Railways only

Question 82

GATE CE 2024• Civil Engineering

What is the CORRECT match between the air pollutants and treatment techniques given in the table?

Air pollutantsTreatment techniques
P.NO2i.Flaring
Q.SO2ii.Cyclonic separator
R.COiii.Lime scrubbing
S.Particlesiv.NH3 injection
  1. AOption (a)

    P - iv, Q - iii, R - i, S - ii

  2. BOption (b)

    P - i, Q - ii, R - iii, S - iv

  3. COption (c)

    P - ii, Q - i, R - iv, S - iii

  4. DOption (d)

    P - ii, Q - iii, R - iv, S - i

View answer & explanation

Correct answer

Answer: (a)A.

P - iv, Q - iii, R - i, S - ii

Why this answer is correct

Explanation:

  • P. NO₂ → iv. NH₃ injection

(Selective catalytic reduction (SCR) or selective non-catalytic reduction (SNCR) involves NH₃ injection to reduce NO₂ emissions.)

  • Q. SO₂ → iii. Lime scrubbing

(Lime scrubbing is used in flue gas desulfurization (FGD) to remove SO₂ from emissions.)

  • R. CO → i. Flaring

(Flaring is used to burn off excess CO and other hydrocarbons in industrial processes.)

  • S. Particles → ii. Cyclonic separator

(Cyclonic separators help in removing particulate matter from air streams.)

Question 83

GATE CE 2024• Civil Engineering

The statements P and Q are related to matrices A and B , which are conformable for both addition and multiplication.

P : (A + B)T = AT + BT

Q : (AB)T = AT BT

Which one of the following options is CORRECT?

  1. AOption (a)

    Both P and Q are false

  2. BOption (b)

    Both P and Q are true

  3. COption (c)

    P is false and Q is true

  4. DOption (d)

    P is true and Q is false

View answer & explanation

Correct answer

Answer: (d)D.

P is true and Q is false

Why this answer is correct

Explanation:

According to the properties of a matrix

(i) (A + B)T = AT + BT

The sum of the transpose of matrices is equal to the transpose of the sum of two matrices.

(ii) (AB)T = AT BT

The product of the transpose of two matrices in reverse order is equal to the transpose of the product of them.

Question 84

GATE CE 2024• Civil Engineering

What is the CORRECT match between the survey instruments/parts of instruements shown in the table and the operations carried out with them?

Instruments/Parts of instrumentsOperations
P.Bubble tubei.Tacheometry
Q.Plumb bobii.Minor movements
R.Tangent screwiii.Centering
S.Stadia cross-wireiv.Levelling
  1. AOption (a)

    P - ii, Q - iii, R - iv, S - i

  2. BOption (b)

    P - iv, Q - iii, R - ii, S - i

  3. COption (c)

    P - iii, Q - iv, R - i, S - ii

  4. DOption (d)

    P - i, Q - iii, R - ii, S - iv

View answer & explanation

Correct answer

Answer: (b)B.

P - iv, Q - iii, R - ii, S - i

Why this answer is correct

Explanation:

  • P. Bubble tube → iv. Levelling

(The bubble tube is used in leveling instruments to check and adjust the horizontal level.)

  • Q. Plumb bob → iii. Centering

(A plumb bob helps in centering the instrument precisely over a survey point.)

  • R. Tangent screw → ii. Minor movements

(Tangent screws allow fine adjustments and minor movements for precise alignment.)

  • S. Stadia cross-wire → i. Tacheometry

(Stadia cross-wires are used in tacheometry for measuring distances using a theodolite or level.)

Question 85

GATE CE 2024• Civil Engineering

Consider the statements P and Q.

P: In a Pure project organization, the project manager maintains complete authroity and has maximum control over the project.

Q: A matrix organization structure facilitates quick response to changes, conflicts, and project needs.

Which one of the following options is CORRECT?

  1. AOption (a)

    P is false and Q is true

  2. BOption (b)

    Both P and Q are false

  3. COption (c)

    Both P and Q are true

  4. DOption (d)

    P is true and Q is false

View answer & explanation

Correct answer

Answer: (c)C.

Both P and Q are true

Why this answer is correct

Explanation:

Statement P: "In a Pure project organization, the project manager maintains complete authority and has maximum control over the project."

True

  • A pure project organization (also called a projectized organization) gives the project manager full authority over project execution, decision-making, and resources.
  • The project team reports directly to the project manager, as confirmed by standard project management literature.

Statement Q: "A matrix organization structure facilitates quick response to changes, conflicts, and project needs."

True

  • As per the matrix organization structure description in the images, one of its advantages is:
  • "The structure facilitates quick response to changes, conflicts, and project needs."
  • The matrix structure combines functional and project-based management, ensuring efficient adaptability to project demands and conflicts.

Question 86

GATE CE 2024• Civil Engineering

A 2 m wide rectangular channel is carrying a discharge of 30 m3/s at a bed slope of 1 in 300. Assuming the energy correction factor as 1.1 and acceleration due to gravity as 10 m/s2, the critical depth of flow (in meters) is _________ (rounded off) to 2 decimal places)

View answer & explanation

Correct answer

Answer: 2.91Answer: 2.91

Why this answer is correct

Explanation:

Discharge (Q) = 30 m3/s

Width of channel (B) = 2m

Bed slope = 1 in 300

Energy correction factor (α) = 1.1

g = 10 m/s2

Discharge per unit width \((q)=\frac{Q}{B}\)

\(=\frac{30}{2}=15 \mathrm{~m}^3 / \mathrm{sec} / \mathrm{m}\)

Critical depth does not depend on slope or the roughness of channel.

Critical depth is given by

 \(\left(y_c\right)=\left(\frac{q^2 \cdot \alpha}{g}\right)^{1 / 3}\)

\(=\left(\frac{1.1 \times 15^2}{10}\right)^{1 / 3}=2.914 \mathrm{~m} \simeq 2.91 \mathrm{~m}\)

Additional InformationTotal energy \((E)=y+\frac{\alpha V^2}{2 g}\)

\(=y+\frac{\alpha q^2}{y^2 \times 2 g} \)

\(\frac{d E}{d y} =1+\frac{\alpha q^2}{2 g} \frac{(-2)}{y^3}\)

For critical low, putting \(\frac{d E}{d y}=0\)

\(\frac{\alpha q^2}{g y_c^3}=1\)

\(\therefore \quad y_c=\left(\frac{\alpha q^2}{g}\right)^{1 / 3}\)

Question 87

GATE CE 2024• Civil Engineering

Which one of the following saturated fine-grained soils can attain a negative Skempton's pore pressure coefficient (A)?

  1. AOption (a)

    Quick clays

  2. BOption (b)

    Lightly-consolidated clays

  3. COption (c)

    Normally-consolidated clays

  4. DOption (d)

    Over-consolidated clays

View answer & explanation

Correct answer

Answer: (d)D.

Over-consolidated clays

Why this answer is correct

Explanation:

For normally consolidated clays A = 0.5 - 1

  • For OC clays, A = f (OCR), for heavily over consolidated clays, A < 0.

Additional Information

Pore Pressure Parameters:

(i) Sometimes it is not possible to determine pore pressure practically, then the theoretical approach given by skempton can be adopted.

(ii) Pore pressure parameters A and B are empirical coefficients that are used to express the response of pore pressure to changes in vertical pressure and lateral pressure under "undrained condition".

Parameter B:

(i) This parameter is defined under cell pressure stage and represents the ratio of change in pore pressure to the change in cell pressure.

B = ΔUc/Δσc

(ii) B varies from o to 1 depending on the degree of saturation. "B" is zero for dry soil and is equals unity for fully saturated soil.

Parameter A:

(i) This parameter is valid in deviator stage and is defined in terms of another parameter A̅, such that

A̅ = A.B

(ii) The parameter A̅ represents the ratio of change in pore pressure to change in deviator stress during shear stage.

\(\bar A = \dfrac{{\Delta {U_d}}}{{\Delta {\sigma _d}}} = \dfrac{{\Delta {U_d}}}{{\Delta ({\sigma _1} - {\sigma _3})}} = \dfrac{{\Delta {U_d}}}{{\Delta {\sigma _1} - \Delta {\sigma _3}}}\)

(iii) The parameter depends upon strain in soil, degree of saturation, over consolidated ratio, stratification of soil, sample disturbance, etc. Its value may be as low as -0.5 for over consolidated soil with high O.C.R. to as high as 3 or loose saturated sand.

Question 88

GATE CE 2024• Civil Engineering

For a reconnaisssance survey, it is necessary to obtain vertical aerial photographs of a terrain at an average scale of 1 : 13000 using a camera. If the permissible flying height is assumed as 3000 m above a datum and the average terrain elevation is 1050 m above the datrum, the required focal length (in mm ) of the camera is

  1. AOption (a)

    125

  2. BOption (b)

    100

  3. COption (c)

    150

  4. DOption (d)

    200

View answer & explanation

Correct answer

Answer: (c)C.

150

Why this answer is correct

Explanation:

Given Data:

  • Required scale of aerial photograph = 1 : 13,000
  • Permissible flying height above datum = 3000 m
  • Average terrain elevation above datum = 1050 m

Now,

Scale  \(=\frac{1}{13000}\)

Hence, 

\(\mathrm{S} =\frac{\mathrm{f}}{\mathrm{H}-\mathrm{h}} \)

\(\frac{1}{13000} =\frac{\mathrm{f}}{3000-1050} \)

∴   f = 0.15 m = 150 mm

Question 89

GATE CE 2024• Civil Engineering

Consider teh following data for a project of 300 days duration.

Budgeted cost of work scheduled (BCWS) = Rs. 200

Budgeted cost of work performed (BCWP) = Rs. 150

Actual cost of work performed (ACWP) = Rs. 190 The 'schedule variance' for the project is

  1. AOption (a)

    (-)Rs. 50

  2. BOption (b)

    (+)Rs. 50

  3. COption (c)

    (+)50 days

  4. DOption (d)

    (-)50 days

View answer & explanation

Correct answer

Answer: (a)A.

(-)Rs. 50

Why this answer is correct

Explanation:

As per given data:

  • Budgeted Cost of Work Scheduled (BCWS) = Rs. 200
  • Budgeted Cost of Work Performed (BCWP) = Rs. 150
  • Actual Cost of Work Performed (ACWP) = Rs. 190

Schedule Variance is given by

= BCWP - BCWS 

= 150 - 200

= -50

Question 90

GATE CE 2024• Civil Engineering

A simply supported, uniformly loaded, two-way slab panel is torsionally unrestrained. The effective span lengths along the short span ( x ) and long span ( y ) directions of the panel are Ix and Iy respectively. The design moments for the reinforcements along the x and y directions are Mux and Muy respectively. By using Rankine-Grashoff method, the ratio Mux/Muy is proportional to

  1. AOption (a)

    Iy/Ix

  2. BOption (b)

    Ix/Iy

  3. COption (c)

    (Iy/Ix)2

  4. DOption (d)

    (Ix/Iy)2

View answer & explanation

Correct answer

Answer: (c)C.

(Iy/Ix)2

Why this answer is correct

Explanation:

Grashoff method is used to determine the bending moment in two way RCC slab. It is used for load distribution when the slab is simply supported on all four edges and the corners are not held down.

As per Rankine Grashoff method

\(M_{u x}=\frac{r^4}{8\left(1+r^4\right)} w \epsilon_x^2\)

\(M_{u y}=\frac{r^2}{8\left(1+r^4\right)} w \epsilon_x^2\)

Here \(r=\frac{\ell_y}{\ell_x} \)

\(\Rightarrow \quad \frac{\mathrm{M}_{\mathrm{ux}}}{\mathrm{M}_{\mathrm{uy}}}=\mathrm{r}^2=\left(\frac{\ell_{\mathrm{y}}}{\ell_{\mathrm{x}}}\right)^2\)