The following is the isotopic composition of an element, 'X':
200X: 90%
199X: 8%
202X: 2%
The weighted average atomic mass of the naturally occurring element 'X' comes the closest to:
- AOption (a)
200 u
- BOption (b)
201 u
- COption (c)
202 u
- DOption (d)
199 u
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Correct answer
200 u
Why this answer is correct
CONCEPT:
Weighted Average Atomic Mass
- The weighted average atomic mass of an element is the average mass of its isotopes, weighted by their fractional abundances in nature.
- The formula for calculating the weighted average atomic mass is:
Average Atomic Mass = (fractional abundance of isotope 1 × atomic mass of isotope 1) + (fractional abundance of isotope 2 × atomic mass of isotope 2) + ...
EXPLANATION:
- In the given problem, the isotopic composition of element 'X' is:
- 200X: 90% or 0.90 (atomic mass = 200 u)
- 199X: 8% or 0.08 (atomic mass = 199 u)
- 202X: 2% or 0.02 (atomic mass = 202 u)
- The weighted average atomic mass is calculated as:
- Average Atomic Mass = (0.90 × 200) + (0.08 × 199) + (0.02 × 202)
- Average Atomic Mass = 180 + 15.92 + 4.04
- Average Atomic Mass ≈ 199.96 u
Therefore, the weighted average atomic mass of element 'X' is approximately 200 u.




