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Question 21

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 2

Rs. 6000 becomes Rs. 8340 in K years at simple interest. If the rate of interest is 13% per annum, what is the value of K?

  1. AOption (a)

    2 years 

  2. BOption (b)

    4 years

  3. COption (c)

    3 years

  4. DOption (d)

    5 years

View answer & explanation

Correct answer

Answer: (c)C.

3 years

Why this answer is correct

Given:

Principal = Rs. 6000 

Amount = Rs. 8340 

Rate = 13% 

Time = K

Formula used:

S.I = PRT/100

Where P → principal, R → rate, T → time 

Simple interest = Amount - Principal

Calculation:

According to the question,

Simple interest = 8340 - 6000 = 2340 

By using formula, we get 

Simple interest = (6000 × 13 × K)100

⇒ 2340 = 780 × K 

⇒ 3 = K 

∴ The value of K is 3 years.

Question 22

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 2

The pie chart given below shows the number of movies released on different weekends of a month. The number is shown as a percentage of total movies released in the month.

If the total number of movies released in the month are 200, then the number of movies released in W4 is how much more than the movies released in W1?

  1. AOption (a)

    16

  2. BOption (b)

    12

  3. COption (c)

    8

  4. DOption (d)

    20

View answer & explanation

Correct answer

Answer: (a)A.

16

Why this answer is correct

Given:

Total number of movies = 200

W4 = 20% of total movies 

W1 = 12% of total movies

Calculation:

According to the question,

100% → 200 movies

⇒ 1% → 2 movies 

Number of movies released in W4 = 20%

⇒ 20 × 2 = 40

Number of movies released in W1 = 12%

⇒ 12 × 2 = 24

Required difference = 40 - 24

⇒ 16

∴ In week 'W4' 16 more movies released as compared to 'W1'.

Question 23

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 2

A car has to travel 250 km in 30 hours. It covers 1/5 part of the journey in 1/6 time. What should be its speed for the remaining journey to reach on time?

  1. AOption (a)

    10 km/hr

  2. BOption (b)

    8 km/hr

  3. COption (c)

    ​12 km/hr

  4. DOption (d)

    ​15 km/hr

View answer & explanation

Correct answer

Answer: (b)B.

8 km/hr

Why this answer is correct

Given:

Total distance =  250 km

Total time = 30 h

Car covered 1/5 part of the journey in 1/6 time.

Formula Used:

Speed = Distance/Time

Calculation:

According to the question,

Distance travelled by car = (1/5) × 250

⇒ 50 km

Time taken to travel this distance = (1/6) × 30

⇒ 5 hours

So, Remaining distance to be travelled by car = 250 - 50

⇒ 200 km

&, Remaining time to travel this distance = 30 - 5

⇒ 25 hours

Now, Speed of the car for the remaining journey = (Remaining distance)/(Remaining time)

⇒ 200/25

⇒ 8 km/hr

∴ The speed of the car to cover the remaining journey on time is 8 km/hr.

Question 24

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 2

Two cubes each of edge 24 cm are combined to form a single cuboid. What is the volume of the new cuboid?

  1. AOption (a)

    17688 cm3

  2. BOption (b)

    27648 cm3

  3. COption (c)

    25678 cm3

  4. DOption (d)

    13824 cm3

View answer & explanation

Correct answer

Answer: (b)B.

27648 cm3

Why this answer is correct

Given:

Two cubes combined to form a single cuboid

Edge of cube = 24 cm

Formula used:

Volume of a cuboid = L × B × H,

where,

L = Length, B = Breadth, H = Height of the cuboid

Calculation:

According to the question,

Two cubes each of edge 24 cm are combined to form a single cuboid.

Observe the following diagram for better understanding.

So, After combining the cubes,

Length of the cuboid = 24 + 24 

⇒ 48 cm

Breadth of the cuboid = 24 cm

& Height of the cuboid = 24 cm

So, Volume of the cuboid = L × B × H

⇒ 48 × 24 × 24 

⇒ 27648 cm3

∴ The volume of the new cuboid is 27648 cm3.

Question 25

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 2

The line graph given below shows the number of rotis made by a rotimaker in a hotel on different days.

The rotis made on D5 is what percent more than the rotis made on D1?

  1. AOption (a)

    26.56%

  2. BOption (b)

    24.56%

  3. COption (c)

    22.56%

  4. DOption (d)

    18.56%

View answer & explanation

Correct answer

Answer: (a)A.

26.56%

Why this answer is correct

Given:

Rotis made on D5 = 1296

Rotis made on D1 = 1024

Calculation:

According to the question,

Required percentage = [(Rotis made on D5 - Rotis made on D1)/(Rotis made on D1)] × 100%

⇒ [(1296 - 1024)/1024] × 100%

⇒ (272/1024) × 100%

⇒ (17/64) × 100%

⇒ 26.56%

∴ The rotis made on D5 is 26.56% percent more than the rotis made on D1.

Question 26

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 2

A sum of money becomes Rs. 39930 in 3 years and Rs. 36300 in 2 years when kept at compound interest (compounding annually). What is the sum? 

  1. AOption (a)

    Rs. 34000

  2. BOption (b)

    Rs. 28000

  3. COption (c)

    Rs. 32000

  4. DOption (d)

    Rs. 30000

View answer & explanation

Correct answer

Answer: (d)D.

Rs. 30000

Why this answer is correct

Given:

Amount in 3 years = Rs. 39930

Amount in 2 years = Rs. 36300

Formula used:

A = P(1 + r/100)n

Where, A = Amount, r = Rate of interest, n = Time in year

Calculation:

According to the question,

39930 = P(1 + r/100)3      ----(1)

36300 = P(1 + r/100)2      ----(2)

Dividing equation (1) by equation (2), we get

(39930/36300) = [(1 + r/100)3/(1 + r/100)2]

⇒ 11/10 = 1 + r/100

⇒ r/100 = 1/10

⇒ r = 10%

From equation (2),

36300 = P[1 + (10/100)]2

⇒ 36300 = P(11/10)2

⇒ P = 36300 × (100/121)

⇒ P = 30000

∴ The sum is Rs. 30000.

Shortcut Trick

Percentage increase = 36300 - 39930 = 3630

⇒ (3630 / 36300) × 100 = 10%

let the principal be x

⇒ x + (10/100)2 × x = 36300

⇒ 1.21x = 36300

⇒ x = 36300 / 1.21 = Rs.30000

 ∴ The sum is Rs. 30000.

Question 27

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 2

A can complete a work alone in 8 days. B can complete the same work alone in 12 days. C alone complete the same work in 16 days. They complete the work in 3 days with the help of D. If they get Rs.12000 for the work, then how much money does the D get?

  1. AOption (a)

    Rs. 2500

  2. BOption (b)

    Rs. 2750

  3. COption (c)

    Rs. 2250

  4. DOption (d)

    Rs. 3000

View answer & explanation

Correct answer

Answer: (c)C.

Rs. 2250

Why this answer is correct

Given:

A completes the work = 8 days

B completes the work = 12  days

C completes the work = 16 days

Total wages = Rs. 12000

Concept used:

The total work will be LCM of individual time taken by A and B and C. 

Efficiency α Share

Calculation:

Total work = LCM of (8, 12, 16)

⇒ Total work = 48

Efficiency of A = 48/8 = 6

Efficiency of B = 48/12 = 4

Efficiency of C = 48/16 = 3

⇒ The total efficiency of A , B and C = 13

Total efficiency of A, B, C and D = (48/3) = 16

Efficiency of D = 16 - 13

⇒ The efficiency of D = 3

The share will be distributed in the ratio of 6 ∶ 4 ∶ 3 ∶ 3.

Let the share of A, B, C and D be 6x, 4x, 3x and 3x

According to the question, 

Total share = Rs. 12000

⇒ 6x + 4x + 3x + 3x = 12000

⇒ x = 12000/16

⇒ x = 750

Share of D = 3 × 750

⇒ Share of D = Rs. 2250. ∴ The share of D is Rs. 2250.

Question 28

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 2

The table given below shows the number of questions in different sets.

SetNumber of questions
S154
S256
S360
S462
S566
S672

The number of questions in set 1 is approximately how much percent less than the number of questions in set 4?

  1. AOption (a)

    14.9 percent

  2. BOption (b)

    10.9 percent

  3. COption (c)

    0.169

  4. DOption (d)

    12.9 percent

View answer & explanation

Correct answer

Answer: (d)D.

12.9 percent

Why this answer is correct

Given:

The number of questions in set 1 = 54

The number of questions in set 4 = 62

Calculation:

Let the number of questions in set 1 be x less than the number of questions in set 4.

According to the question, 

x = 62 - 54

⇒ 8

Now, Required percentage = (8/62) × 100%

⇒ (400/31)%

⇒ 12.903%

∴ The number of questions in set 1 is approximately 12.9% less than the number of questions in set 4.

Question 29

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 2

100 men can make 60 chairs in 4 days working 2 hours a day. How many men are required to make 120 chairs in 10 days working 4 hours a day?

  1. AOption (a)

    34 men

  2. BOption (b)

    40 men

  3. COption (c)

    30 men

  4. DOption (d)

    28 men

View answer & explanation

Correct answer

Answer: (b)B.

40 men

Why this answer is correct

Given:

Number of days taken by 100 men to make 60 chairs working 2 hours a day = 4 days

Chairs to be made in 10 days working 4 hours a day = 120

Formula used:

(M1 × D1 × H1)/W1 = (M2 × D2 × H2)/W2

Where, M1, M2 = Number of men D1, D2 = Number of days, H1, H2 = Number of hours, W1, W2 = Work Done

We will use only the terms that are given in the question

Calculation:

According to the question,

M1 = 100, D1 = 4 days, H1 = 2 hours and W1 = 60 chairs

D2 = 10 days, H2 = 4 hours and W2 = 120 chairs

(M1 × D1 × H1)/W1 = (M2 × D2 × H2)/W2         

⇒ (100 × 4 × 2)/60 = (M2 × 10 × 4)/120

⇒ 100 × 8 × 120 = M2 × 40 × 60

⇒ M2 = 40

∴ 40 men are required to make 120 chairs in 10 days working 4 hours a day.

Question 30

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 2

The length, breadth and height of a cuboid is 12 cm, 9 cm and 8 cm respectively. What is the length of the longest diagonal of the cuboid?

  1. AOption (a)

    16 cm

  2. BOption (b)

    13 cm

  3. COption (c)

    17 cm

  4. DOption (d)

    14.5 cm

View answer & explanation

Correct answer

Answer: (c)C.

17 cm

Why this answer is correct

Given:

The length of the cuboid = 12 cm

The breadth of the cuboid = 9 cm

The height of the cuboid = 8 cm

Formula used:

D = √(l2 + b2 + h2)

where, D = The longest diagonal of a cuboid, l = The length of a cuboid

b = The breadth of a cuboid, h = The height of a cuboid

Calculation:

According to the question, 

D = √(122 + 92 + 82)

⇒ √(144 + 81 + 64)

⇒ √289

⇒ 17 cm

∴ The longest diagonal of the cuboid is 17 cm.