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Question 11

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 1

\(\dfrac{(0.73)^3+(0.31)^3}{(0.73)^2-0.73\times0.31+(0.31)^2}\)

  1. AOption (a)

    1.04

  2. BOption (b)

    2.14

  3. COption (c)

    1.01

  4. DOption (d)

    1.08

View answer & explanation

Correct answer

Answer: (a)A.

1.04

Why this answer is correct

Given:

The expression is \(\dfrac{(0.73)^3+(0.31)^3}{(0.73)^2-0.73\times0.31+(0.31)^2}\)

Formula Used:

(a3 + b3) = (a + b)(a2 - ab + b2)

Calculation:

According to the question, we have

The given expression is

\(\dfrac{(0.73)^3+(0.31)^3}{(0.73)^2-0.73\times0.31+(0.31)^2}\)        ----(1)

In the formula used

(a3 + b3) = (a + b)(a2 - ab + b2)

⇒ (a3 + b3)/(a2 - ab + b2) = (a + b)        ----(2)

Now, comparison between equation (1) and equation (2)

a = 0.73

b = 0.31

⇒ (a + b) = (0.73 + 0.31)

⇒ (a + b) = 1.04

∴ The value of given expression is 1.04.

Question 12

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 1

Anil sells a pen at a loss of 35%. If he had sold the pen for Rs 240 more, then he would have a loss of 20%. To gain profit of 40%, what should be the selling price of the pen?

  1. AOption (a)

    Rs. 3240

  2. BOption (b)

    ​Rs. 2240

  3. COption (c)

    ​Rs. 2460

  4. DOption (d)

    ​Rs. 2340

View answer & explanation

Correct answer

Answer: (b)B.

​Rs. 2240

Why this answer is correct

Given:

Loss = 35%

If Anil sold the pen at Rs. 240 more he would Loss 20%

Formula Used:

S.P = C.P × {(100 - L%)/100}

S.P = C.P × {(100 + P%)/100}

S.P = Selling Price, C.P = Cost Price

L = Loss, P = Profit

Calculation:

Let the C.P of the pen be 100x

According to the question, we have

S.P = 100x × (100 - 35/100)

⇒ S.P = 65x

Now, he sold Rs. 240 more, then 20% loss

100x × (100 - 20/100) = 65x + 240

⇒ 80x = 65x + 240

⇒ 80x - 65x = 240

⇒ 15x = 240

⇒ x = 16

C.P = 100 × 16

⇒ 1600

Now, he gains 40%

S.P = 1600 × (100  + 40)/100

⇒ 1600 × (140/100)

⇒ 2240

∴ The selling price of the pen is Rs. 2240.

Question 13

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 1

What is the sum of the average of first 19 natural numbers and the average of first 6 positive odd numbers?

  1. AOption (a)

    17

  2. BOption (b)

    19

  3. COption (c)

    18

  4. DOption (d)

    16

View answer & explanation

Correct answer

Answer: (d)D.

16

Why this answer is correct

Formula Used:

The sum of first n natural numbers = {n × (n + 1)}/2

where, n = number of natural numbers

Average = The sum of the observations/The number of the observations

Calculation:

According to the question, we have

The sum of the first 19 natural numbers = {19 × (19 + 1)}/2

⇒ 19 × 10

⇒ 190

Average of the first 19 natural numbers = 190/19

⇒ 10

The first 6 positive odd numbers are 1, 3, 5, 7, 9 and 11

The sum of first 6 positive odd numbers = 1 + 3 + 5 + 7 + 9 + 11

⇒ 36

The average of the first 6 positive odd numbers = 36/6

⇒ 6

Now,

The sum of the average = 10 + 6

⇒ 16

∴ The sum of the average of first 19 natural numbers and the average of first 6 positive odd numbers is 16.

Question 14

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 1

If \(A=\dfrac{1}{30}+\dfrac{1}{20}+\dfrac{1}{42}:and:Y=\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\)then find A + Y.

  1. AOption (a)

    21 / 140

  2. BOption (b)

    21 / 160

  3. COption (c)

    23 / 150

  4. DOption (d)

    23 / 140

View answer & explanation

Correct answer

Answer: (a)A.

21 / 140

Why this answer is correct

Given:

\(A=\dfrac{1}{30}+\dfrac{1}{20}+\dfrac{1}{42}:\)

\(Y=\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\)

Calculation:

A = (1/30) + (1/20) + (1/42)

⇒ A = (14 + 21 + 10)/420

⇒ A = 45/420 = 3/28

B = (1/56) + (1/72) + (1/90)

⇒ B = (45 + 35 + 28)/2520

⇒ B = 108/2520 = 3/70

Now, 

A + B = (3/28) + (3/70)

⇒ A + B = 21/140

∴ The value of A + B is 21/140.

Question 15

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 1

The cost price of a bat is 5/6 of the marked price. What will be the gain/loss percentage after allowing a discount of 30% on the marked price?

  1. AOption (a)

    24% profit

  2. BOption (b)

    24% loss

  3. COption (c)

    16% profit

  4. DOption (d)

    16% loss

View answer & explanation

Correct answer

Answer: (d)D.

16% loss

Why this answer is correct

Given:

C.P/M.P = 5/6

Discount = 30%

Formula used:

Discount = [(D%)/100] × M.P

S.P = M.P - Discount

Loss = C.P - S.P

Calculation:

Let C.P and M.P be 500 and 600

Discount = 30%

Discount = [(D%)/100] × M.P

Discount = (30/100) × 600

⇒ Discount = 180

So, S.P = M.P - Discount

S.P = 600 - 180

⇒ S.P = 420

Loss = C.P - S.P

Loss = 500 - 420 = 80

Loss% = (80/500) × 100 = 16%

∴ The profit percentage is 16%.

Question 16

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 1

The ratio of marked price to the selling price of a article is 5 : 2. What is the discount percentage?

  1. AOption (a)

    40 percent

  2. BOption (b)

    30 percent

  3. COption (c)

    60 percent

  4. DOption (d)

    50 percent

View answer & explanation

Correct answer

Answer: (c)C.

60 percent

Why this answer is correct

Given:

MP : SP = 5 : 2

Where, MP = Marked Price, SP = Selling Price

Formula used:

Discount% = {(MP - SP)/MP} × 100

Calculation:

Let MP and SP be 5x and 2x

According to the formula used,

Discount% = {(MP - SP)/MP} × 100

⇒ Discount% = {(5x - 2x)/5x} × 100

⇒ Discount% = (3x/5x) × 100 = 60

∴ The discount percentage is 60%

Question 17

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 1

The selling price of an article is Rs. 960 and profit earned on it is 50%. If the new profit percentage is 30%, then what will be the selling price of the article?

  1. AOption (a)

    Rs. 832

  2. BOption (b)

    Rs. 844

  3. COption (c)

    Rs. 736

  4. DOption (d)

    Rs. 748

View answer & explanation

Correct answer

Answer: (a)A.

Rs. 832

Why this answer is correct

Given:

Selling Price = Rs. 960

Profit earned = 50%

Formula used:

S.P = {(100 + Profit%)/100} × C.P

Where, S.P = Selling Price, C.P = Cost Price

Calculation:

According to the formula used,

S.P = {(100 + Profit%)/100} × C.P

⇒ 960 = {(100 + 50)/100} × C.P

⇒ 960 × (2/3) = C.P

⇒ C.P = 640

According to the question,

The new profit percentage is 30%

S.P = {(100 + Profit%)/100} × C.P

⇒ S.P = {(100 + Profit%)/100} × C.P

⇒ S.P = {(100 + 30)/100} × 640 = 832

∴ The new selling price of the article is Rs. 832

Question 18

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 1

The ratio of age of two person A and B is 3 : 4. If the sum of their ages is 56, then what is the age of B?

  1. AOption (a)

    24 years

  2. BOption (b)

    32 years

  3. COption (c)

    22 years

  4. DOption (d)

    36 years

View answer & explanation

Correct answer

Answer: (b)B.

32 years

Why this answer is correct

Given:

The ratio of age of A and B is 3 : 4

The Sum of their ages is 56

Calculation:

Let the ages of A and B is 3x and 4x

According to the given question,

⇒ 3x + 4x = 56

⇒ 7x = 56

⇒ x = 56/7

⇒ x = 8

The age of B = 4x = 4 × 8

⇒ 32

∴ The age of B is 32 years.

Question 19

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 1

Ram sold a table at Rs. 960. On selling this table, he earned a profit of Rs. 160. What is the profit percentage?

  1. AOption (a)

    20 %

  2. BOption (b)

    25 %

  3. COption (c)

    33.33 %

  4. DOption (d)

    16.66 %

View answer & explanation

Correct answer

Answer: (a)A.

20 %

Why this answer is correct

Given:

Selling price = Rs. 960

Profit = Rs. 160

Formula used:

Profit % = (P/C.P.) × 100

Profit = S.P. - C.P.

Where, Cost price = C.P, Selling price = S.P, Profit = P

Calculation:

Profit = S.P. - C.P.

⇒ 160 = 960 - C.P.

⇒ C.P. = Rs. 800      ----(1)

Profit % = (P/C.P.) × 100

⇒ P % = (160/800) × 100

⇒ P % = 20

∴ The total profit is 20%.

Question 20

DSSSB Junior Secretariat Assistant 2019• Arithmetic Ability 1

If \(A=5\dfrac{1}{2}+7\dfrac{3}{4}-2\dfrac{1}{4}:and:B=11\dfrac{1}{4}-3\dfrac{1}{2}-5\dfrac{3}{4}\) then what is the value of A2 + B2?

  1. AOption (a)

    145

  2. BOption (b)

    150

  3. COption (c)

    125

  4. DOption (d)

    130

View answer & explanation

Correct answer

Answer: (c)C.

125

Why this answer is correct

Given:

A = \(5\frac{1}{2} + 7\frac{3}{4} - 2\frac{1}{4}\)

B = \(11\frac{1}{4} - 3\frac{1}{2} - 5\frac{3}{4}\)

Calculation:

A = \(5\frac{1}{2} + 7\frac{3}{4} - 2\frac{1}{4}\)

⇒ A = (11/2) + (31/4) - (9/4)

⇒ A = {(22 + 31 - 9)/4}

⇒ A = 44/4

⇒ A = 11      ----(1)

B = \(11\frac{1}{4} - 3\frac{1}{2} - 5\frac{3}{4}\)

⇒ B = (45/4) - (7/2) - (23/4)

⇒ B = {(45 - 14 - 23)/4}

⇒ B = (8/4)

⇒ B = 2      ----(2)

Now, 

⇒ A2 + B2 

From equation (1) and equation (2)

⇒ (11)2 + (2)2

⇒ 125

∴ The value of A2 + B2 is 125.